Java 试一试catch dones'；无法捕捉异常

在下面的代码中，我得到了IOException的

不可访问的catch块。在
}catch（IOException e）{
中使用
IOException
时，决不会从try语句体错误（带下划线）引发此异常

class driver {

  public static void main(String[] args) {
    // TODO Auto-generated method stub
    Customer forrest = new Customer("Forrest Gump", 1,
        "42 New Street, New York, New York");
    Customer random = new Customer("Random Name", 2,
        "44 New Street, New York, New York");
    Customer customer[] = { null, forrest, random };
    int whichOption = 1;
    int id = 0;
    char action = ' ';
    char accSrc = ' ';
    char accDest = ' ';
    double amount = 0;
    BankAccount src = null;
    do {

      try{
        // process JOptionPane input information
        String input = JOptionPane
            .showInputDialog("Please enter your transaction information: ");
        Scanner s = new Scanner(input);
        id = Integer.parseInt(s.next());
        action = Character.toUpperCase((s.next().charAt(0)));

        if (action == 'T') {
          amount = s.nextDouble();
          accSrc = s.next().charAt(0);
          accDest = s.next().charAt(0);
        } else if (action == 'G' || action == 'I') {
          accSrc = s.next().charAt(0);
        } else {
          // if D,W
          amount = s.nextDouble();
          accSrc = s.next().charAt(0);
        }

      } catch (IOException e){

      }
      // taking action accordingly (T)ransfer, (D)eposit, (W)ithdraw, (I)nterest
      if (action == 'T') {

        (customer[id].getAccount(accSrc)).transfer(amount,
            customer[id].getAccount(accDest));
      } else if (action == 'G') {
        System.out.println("The current balance on your " + accSrc
            + " account is "
            + customer[id].getAccount(accSrc).getBalance() + "\n");
      } else if (action == 'D') {
        (customer[id].getAccount(accSrc)).deposit(amount);
      } else if (action == 'W') {
        (customer[id].getAccount(accSrc)).withdraw(amount);
      } else if (action == 'I') {
        (customer[id].getAccount(accSrc)).computeInterest();
      }
      whichOption = JOptionPane
          .showConfirmDialog(null , "Do you want to continue?");

      System.out.println("The balance on " + customer[id].getName()
          + " auto account is " + customer[id].A.balance);
      System.out.println("The balance on " + customer[id].getName()
          + " savings account is " + customer[id].S.balance);
      System.out.println("The balance on " + customer[id].getName()
          + " checkings account is " + customer[id].C.balance);
      System.out.println("The balance on " + customer[id].getName()
          + " loan account is " + customer[id].L.balance + "\n");

    } while (whichOption == 0);

  }
}

似乎您在
try
块中所做的任何操作都不会引发
IOException
，这是因为您在
try/catch
中执行的任何操作都不会引发IOException

根据扫描仪

大多数Scanner类方法抛出
FileNotFoundException
（这在您的情况下不适用，因为不从文件中读取）（或）
IllegalArgumentException
（或）
IllegalStateException

您需要将
IOException
更改为上述任一异常（或）删除try/catch。
该try块中的任何方法调用都不会抛出
IOException
，这就是catch是无法访问的代码的原因

您可以安全地删除try和catch，因为这种情况永远不会发生。
您的
catch
块是空的，这表明您无论如何都不会真正处理异常。您可能在其中有一些代码使您捕获了它，但现在您不再拥有它。只需删除整个
try-catch
将不会有进一步的问题。
您可以删除IOException和try-catch，因为try-catch中的任何语句都不会引发此异常。
try/catch
块为空，代码不会引发
IOException
，但它可能会引发其他异常。
您对源代码做了什么要删除缩进？我下一步一定要这样做time@assylias：同意。更新答案。