Java 不显示接收数据报数据包
我试图制作一个小型java程序,使用Java 不显示接收数据报数据包,java,network-programming,datagram,Java,Network Programming,Datagram,我试图制作一个小型java程序,使用DatagramServer和DatagramPacket将文本消息从服务器写入客户端 这是我在服务器和客户端部分编写的代码 serverm.java byte b[] = new byte[1200]; System.out.println("Enter some text"); BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); Stri
DatagramServer
和DatagramPacket
将文本消息从服务器写入客户端
这是我在服务器和客户端部分编写的代码
serverm.java
byte b[] = new byte[1200];
System.out.println("Enter some text");
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String inputMessage = br.readLine();
b = inputMessage.getBytes();
DatagramSocket d = new DatagramSocket(6125);
DatagramPacket p = new DatagramPacket(b,i,InetAddress.getLocalHost(),5461);
d.send(p);
byte b[] = new byte[1024];
try
{
DatagramSocket d = new DatagramSocket(5461);
DatagramPacket p = new DatagramPacket(b,1024);
d.receive(p);
String outputMessage = new String(p.getData(),0,p.getLength());
System.out.println(outputMessage);
}
clientm.java
byte b[] = new byte[1200];
System.out.println("Enter some text");
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String inputMessage = br.readLine();
b = inputMessage.getBytes();
DatagramSocket d = new DatagramSocket(6125);
DatagramPacket p = new DatagramPacket(b,i,InetAddress.getLocalHost(),5461);
d.send(p);
byte b[] = new byte[1024];
try
{
DatagramSocket d = new DatagramSocket(5461);
DatagramPacket p = new DatagramPacket(b,1024);
d.receive(p);
String outputMessage = new String(p.getData(),0,p.getLength());
System.out.println(outputMessage);
}
当运行java程序时,它在服务器向客户端发送消息时运行—收到的消息只打印空行。如何获取要显示的字符串?当我将服务器中的“i”变量设置为0时,我能够重现您的问题
确保该值是您发送的数据包的长度。谢谢。我忘记将字符串长度更新为变量
I