Java 是否有办法使用1以外的数字作为输入以继续程序？它似乎没有认识到我所面临的问题；我有

所以我在做一个纸牌游戏，它几乎就像石头剪刀一样。这是规则，皇帝打公民，公民打奴隶，奴隶打皇帝。一方有4个公民和一个奴隶，另一方有4个公民和一个皇帝。我已经为每张牌设置了相等的数值，但由于某些原因，我似乎无法在不使用1来扮演皇帝的情况下使程序继续

public static void emperorsTurn() {
    Random cards = new Random();
    int numberx = 0;
    for (int counter = 1; counter <= 3; counter++) {
        numberx = 1 + cards.nextInt(5);
    }

    Scanner sc = new Scanner(System.in);
    System.out.println("Please pick the card you are playing. \n 
                        if you are playing the Emperor press 1, 
                        if you are playing the citizen press 2");
    int eOS = sc.nextInt(); //fix the input

    if (eOS == 1 && numberx == 2) {
        System.out.println("you have played the emperor! \n 
                            the emperor defeats the citizen");
    }
    if (eOS == 1 && numberx == 1) {
        System.out.println("you have played the emperor! \n 
                            the emperor is defeated by the slave");

        if (eOS == 2 && numberx == 1) {
            System.out.println("you have played the citizen, this defeats the slave");

            if (eOS == 2 && numberx == 2) {
                System.out.println("you have played the citizen, this ties with the citizen");

                if (eOS == 2 && numberx == 3) {
                    System.out.println("you have played the citizen, this defeats the slave"); 
                }
            }
        }
    }
}

publicstaticvoidempersturn（）{
随机卡片=新随机（）；
整数x=0；
对于（int counter=1；counter，这是因为这部分代码（注释）永远不会执行，因为eOs必须始终为1。如果eOs是任何其他数字，则if条件将始终失败：

if (eOS == 1 && numberx == 1) {
        System.out.println("you have played the emperor! \n the emperor 
 is defeated by the slave");

        /*if (eOS == 2 && numberx == 1) {
            System.out.println("you have played the citizen, this 
 defeats the slave");

            if (eOS == 2 && numberx == 2) {
                System.out.println("you have played the citizen, this 
 ties with the citizen");


                if (eOS == 2 && numberx == 3) {
                    System.out.println("you have played the citizen, 
 this defeats the slave");*/


 }}}}}

要实现所需，必须将代码重写为：

if (eOS == 1 && numberx == 1) {
        System.out.println("you have played the emperor! \n the emperor 
 is defeated by the slave");

}
else if (eOS == 2) 
{
        if (numberx == 1) {
             System.out.println("you have played the citizen, this 
             defeats the slave");
        }
        else if (numberx == 2) {
             System.out.println("you have played the citizen, this 
             ties with the citizen");
        }

        else if (numberx == 3) {
              System.out.println("you have played the citizen, 
           this defeats the slave");
        }
        else
        {
             //print out something else if number is not 1,2 or 3
        }
}

或者您可以通过以下方式进行：

switch(eOs)
{
     case 1:
         if(numberx == 1) {
             System.out.println("you have played the emperor! \n the emperor 
            is defeated by the slave");
         }
       break;
     case 2:
        if (numberx == 1) {
             System.out.println("you have played the citizen, this 
             defeats the slave");
        }
        else if (numberx == 2) {
             System.out.println("you have played the citizen, this 
             ties with the citizen");
        }

        else if (numberx == 3) {
              System.out.println("you have played the citizen, 
           this defeats the slave");
         }
        else
        {
             //print out something else if number is not 1,2 or 3
        }
       break;
}

编辑

此外，我建议，如果你打算将

  if(eOS ==1 && numberx== //some other values apart from 1)
  {

  }


因为numberx是随机的，可以有除1以外的其他值，所以可以对其进行分解，如下所示：

   if (eOS == 1) {
       if(numberx==1)
       {
            //print out something; 
       } 

       else if(numberx==//another value e.g. 2)
       {
           //print out something else;
       }

       else{
           //
       }
    }
    else if(eOS==2)//the rest of the code

不客气。如果答案解决了您面临的问题，您也可以勾选接受。您在
if（eOS==1&&numberx==1）中编写的代码{
没有任何意义，该块中所有嵌套的
if
块将永远不会执行，因为它要求
eOS
在始终
1
的位置为
2
。