Java QueryDSL意外标记,带有any()和in子句
我有两个模型,Java QueryDSL意外标记,带有any()和in子句,java,hibernate,querydsl,Java,Hibernate,Querydsl,我有两个模型,Location和LocationAttribute,具有多对多关系。 我有一个LocationAttribute ID列表,希望找到至少有一个ID的所有位置 在这些属性中 Location.java: @Entity public class Location { @Id @GeneratedValue @Column(name="LOCATION_ID") protected int id; @ManyToMany(targetEnt
Location
和LocationAttribute
,具有多对多关系。
我有一个LocationAttribute ID列表,希望找到至少有一个ID的所有位置
在这些属性中
Location.java:
@Entity
public class Location {
@Id
@GeneratedValue
@Column(name="LOCATION_ID")
protected int id;
@ManyToMany(targetEntity = LocationAttribute.class)
@JoinTable(name="LOCATION_TO_LOCATION_ATTRIBUTE",
joinColumns = @JoinColumn(name="LOCATION_ID", referencedColumnName = "LOCATION_ID"),
inverseJoinColumns = @JoinColumn(name="LOCATION_ATTRIBUTE_ID", referencedColumnName = "LOCATION_ATTRIBUTE_ID")
)
private List<LocationAttribute> locationAttributes;
}
我尝试了以下QueryDSL代码:
List<Integer> locationAttributeIds = new ArrayList<Integer>();
locationAttributeIds.add(1);
locationAttributeIds.add(2);
locationAttributeIds.add(3);
QLocation location = QLocation.location;
JPAQuery query = new JPAQuery(entityManager, JPQLTemplates.DEFAULT);
query.from(location) .where(location.locationAttributes.any().id.in(locationAttributeIds));
query.list(location);
我找到了很多与我的问题相关的网站,但不确定如何解决这个问题
如果您能告诉我如何找到列表中至少有一个
LocationAttribute.id
s的所有位置,我将不胜感激。谢谢 改用以下JPAQuery构造函数
new JPAQuery(entityManager);
JPQLTemplates
提供了通用的序列化,但没有找到Hibernate的所有JPQL变体。仅使用EntityManager参数Querydsl将为您选择正确的JPQLTemplates子类实例
java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: , near line 5, column 53 [select location
from ch.locatee.test.querydslerror.locatee.Location location
where exists (select location_locationAttributes_cc6d8
from location.locationAttributes as location_locationAttributes_cc6d8
where location_locationAttributes_cc6d8.id in :x1_0_, :x1_1_, :x1_2_)]
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1750)
at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1677)
at org.hibernate.jpa.internal.QueryImpl.getResultList(QueryImpl.java:458)
at com.mysema.query.jpa.impl.AbstractJPAQuery.getResultList(AbstractJPAQuery.java:194)
at com.mysema.query.jpa.impl.AbstractJPAQuery.list(AbstractJPAQuery.java:246)
at ch.locatee.test.querydslerror.locatee.AppTest.testSomething(AppTest.java:63)
new JPAQuery(entityManager);