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Java play框架中一对一关系的JPA错误_Java_Jpa_Playframework - Fatal编程技术网

Java play框架中一对一关系的JPA错误

Java play框架中一对一关系的JPA错误,java,jpa,playframework,Java,Jpa,Playframework,我正在使用play-1.2.3 我有两门课,其中一些: LabelItem: @Entity @Table(name="T_LABEL_ITEM") public class LabelItem extends Model{ @OneToMany(mappedBy="labelItem") public List<LabelValue> labelValues; } 启动播放服务器时,会显示错误页面: "A JPA error occurred (Unable to bui

我正在使用play-1.2.3

我有两门课,其中一些:

LabelItem:

@Entity
@Table(name="T_LABEL_ITEM")
public class LabelItem extends Model{
  @OneToMany(mappedBy="labelItem")
  public List<LabelValue> labelValues;
}
启动播放服务器时,会显示错误页面:

"A JPA error occurred (Unable to build EntityManagerFactory): mappedBy reference an unknown target entity property: models.LabelValue.labelItem in models.LabelItem.labelValues"
还有:数据库中的T_Label_VALUE表只有一个id列,“VALUE”列没有创建


有人能帮忙吗?我想不出来。

JPA不会持久化静态变量。如果希望由JPA管理,请将labelItem设置为实例变量

"A JPA error occurred (Unable to build EntityManagerFactory): mappedBy reference an unknown target entity property: models.LabelValue.labelItem in models.LabelItem.labelValues"