Java 使用stringbuilder和bufferedreader读取多个链接
我试图在下面的代码中从xml源txt文件中读取多个rss链接。我正在使用Java 使用stringbuilder和bufferedreader读取多个链接,java,android,bufferedreader,stringbuilder,delimiter,Java,Android,Bufferedreader,Stringbuilder,Delimiter,我试图在下面的代码中从xml源txt文件中读取多个rss链接。我正在使用作为分隔符。从debug开始,它似乎将所有链接发送到RSS\u LINK,这显然不起作用 StringBuilder rsslink = new StringBuilder(); InputStream is = getResources().openRawResource(R.raw.xmlsource); BufferedReader br = new BufferedReader(new InputStreamRead
作为分隔符。从debug开始,它似乎将所有链接发送到RSS\u LINK
,这显然不起作用
StringBuilder rsslink = new StringBuilder();
InputStream is = getResources().openRawResource(R.raw.xmlsource);
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = null;
try {
while ((line = br.readLine()) != null)
{
rsslink.append(line) ;
}
String [] arr = rsslink.toString().split(";");
for (int i = 0; i < arr.length; i++)
{
}
}
catch (IOException e)
{
e.printStackTrace();
}
String RSS_LINK = rsslink.toString();
Log.d(Constants.TAG, "Service started");
List<RssItem> rssItems = null;
try
{
XMLRssParser parser = new XMLRssParser();
rssItems = parser.parse(getInputStream(RSS_LINK));
}
catch (XmlPullParserException e)
{
Log.w(e.getMessage(), e);
}
catch (IOException e)
{
Log.w(e.getMessage(), e);
}
Bundle bundle = new Bundle();
bundle.putSerializable(ITEMS, (Serializable) rssItems);
ResultReceiver receiver = intent.getParcelableExtra(RECEIVER);
receiver.send(0, bundle);
}
StringBuilder rsslink=new StringBuilder();
InputStream is=getResources().openRawResource(R.raw.xmlsource);
BufferedReader br=新的BufferedReader(新的InputStreamReader(is));
字符串行=null;
试一试{
而((line=br.readLine())!=null)
{
rsslink.append(行);
}
字符串[]arr=rsslink.toString().split(“;”);
对于(int i=0;i
新代码
protected void onHandleIntent(Intent intent)
{
StringBuilder rsslink = new StringBuilder();
InputStream is = getResources().openRawResource(R.raw.xmlsource);
BufferedReader br = new BufferedReader(new InputStreamReader(is));
String line = null;
try {
while ((line = br.readLine()) != null)
{
rsslink.append(line) ;
}
String [] arr = rsslink.toString().split(";");
for (int i = 0; i < arr.length; i++)
{
String RssLink = arr[i];
Log.d(Constants.TAG, "Service started");
List<RssItem> rssItems = null;
try
{
XMLRssParser parser = new XMLRssParser();
rssItems = parser.parse(getInputStream(RssLink));
}
catch (XmlPullParserException e)
{
Log.w(e.getMessage(), e);
}
catch (IOException e)
{
Log.w(e.getMessage(), e);
}
Bundle bundle = new Bundle();
bundle.putSerializable(ITEMS, (Serializable) rssItems);
ResultReceiver receiver = intent.getParcelableExtra(RECEIVER);
receiver.send(0, bundle);
}
}
catch (IOException e)
{
e.printStackTrace();
}
protectedvoid onHandleIntent(意图)
{
StringBuilder rsslink=新的StringBuilder();
InputStream is=getResources().openRawResource(R.raw.xmlsource);
BufferedReader br=新的BufferedReader(新的InputStreamReader(is));
字符串行=null;
试一试{
而((line=br.readLine())!=null)
{
rsslink.append(行);
}
字符串[]arr=rsslink.toString().split(“;”);
对于(int i=0;i
您拆分了rsslink
,但没有使用生成的arr
,而是继续使用rsslink
,它仍然具有所有链接和;
组合
您需要将所有rss处理(解析等)放入循环:
String [] arr = rsslink.toString().split(";");
for (int i = 0; i < arr.length; i++)
{
// HERE IS THE PLACE TO HANDLE a single RSS Link. arr contains the single link
}
String[]arr=rsslink.toString().split(“;”);
对于(int i=0;i
谢谢,我通过将处理部分移动到for循环中,然后发送RSS\u LINK=arr[i]使它起到了一定的作用
我现在面临的问题是,它在链接之间循环,并在返回到循环顶部时删除上一个链接,因此它只显示循环中的链接内容。感谢您提供新代码。它看起来像这样:ResultReceiver receiver=intent.getParcelableExtra(receiver);
始终引用接收方的同一实例和调用发送(0,bundle)的同一实例
因此,以前会取消或覆盖循环中的发送。但是,我的知识到此为止。您可以尝试确保始终获得新的接收方实例,或者-您尝试在发送下一个请求之前等待结果-或者-您再次在stackoverflow.com中询问此特定问题。希望您能够至少在这一点上是有帮助的:-)谢谢你的帮助..不管怎样,我都会选择这个作为答案