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Java 尝试按姓氏排序对象的ArrayList,如果姓氏相同,则按姓氏排序_Java_Sorting_Arraylist - Fatal编程技术网

Java 尝试按姓氏排序对象的ArrayList,如果姓氏相同,则按姓氏排序

Java 尝试按姓氏排序对象的ArrayList,如果姓氏相同,则按姓氏排序,java,sorting,arraylist,Java,Sorting,Arraylist,我从一个数组创建了一个ArrayList ArrayList <Person> PersonArrayList = new ArrayList<>(Arrays.asList(PersonArray)); arraylistpersonarraylist=newarraylist(Arrays.asList(PersonArray)); 做这件事最好的方法是什么 尝试类似于: 我已经创建了gettergetLastName()和getFirstName()最简单的方法

我从一个数组创建了一个
ArrayList

ArrayList <Person> PersonArrayList = new ArrayList<>(Arrays.asList(PersonArray));
arraylistpersonarraylist=newarraylist(Arrays.asList(PersonArray));
做这件事最好的方法是什么

尝试类似于:


我已经创建了getter
getLastName()
getFirstName()

最简单的方法是使用
比较
然后比较

personArrayList.sort(Comparator.comparing(Person::getLastName)
                               .thenComparing(Person::getFirstName));

“Person::getLastName”是什么意思?@Skemelio这是一个相当于以下
(Person-Person)->Person.getLastName()
。基本上,Comparator
Comparator.comparating(Person::getLastName)。然后Comparating(Person::getFirstName)
首先提取人员的姓氏进行比较,如果他们是相同的,则提取人员的姓氏并进行比较。