Java是否会阻止runtime.exec创建的进程?
从Java代码中,我按照以下方式调用脚本文件:Java是否会阻止runtime.exec创建的进程?,java,runtime.exec,Java,Runtime.exec,从Java代码中,我按照以下方式调用脚本文件: Process process =Runtime.getRuntime().exec("sh /usr/local/garner/garnerd start"); int status = process.waitFor(); garnerd脚本代码如下所示(依次调用garner.sh): Garner shell脚本(Garner.sh)源代码为: /usr/local/garner/garnerd status if [ $? -eq 0
Process process =Runtime.getRuntime().exec("sh /usr/local/garner/garnerd start");
int status = process.waitFor();
garnerd脚本代码如下所示(依次调用garner.sh):
Garner shell脚本(Garner.sh)源代码为:
/usr/local/garner/garnerd status
if [ $? -eq 0 ]; then
echo "`date` $0 :Garner is allready running"
exit 0
fi
touch /dev/blank
cd /usr/local/garner
uname -a | grep -i cygwin
if [ $? -eq 0 ]
then
export CYGWIN="$CYGWIN error_start=dumper -d %1 %2"
/usr/local/garner/garner.exe -n -c /usr/local/garner/conf/garner.conf -p /usr/local/garner/garner.pid -l /usr/local/garner/log/garner.log -L 4 &
else
/usr/local/garner/garner -c /usr/local/garner/conf/garner.conf -p /usr/local/garner/garner.pid -l /usr/local/garner/log/garner.log -L 4 &
fi
cd -
当我调用./garner start时,它会创建pid文件。之后,如果我看到这个文件的内容,它会显示garner的进程id
[root@localhost garner]# cat garner.pid
9282
但当我通过下面的命令检查进程id的详细信息时,它显示了使用信号3的“SigBlk:0000000000000004”
[root@localhost garner]# cat /proc/9282/status
Name: garner
State: S (sleeping)
SleepAVG: 78%
Tgid: 9282
Pid: 9282
PPid: 9281
TracerPid: 0
Uid: 0 0 0 0
Gid: 0 0 0 0
FDSize: 64
Groups: 0 1 2 3 4 6 10
VmPeak: 58888 kB
VmSize: 58884 kB
VmLck: 0 kB
VmHWM: 7124 kB
VmRSS: 7124 kB
VmData: 17192 kB
VmStk: 88 kB
VmExe: 84 kB
VmLib: 4480 kB
VmPTE: 156 kB
StaBrk: 05af0000 kB
Brk: 060ec000 kB
StaStk: 7fff0329d950 kB
Threads: 2
SigQ: 0/47721
SigPnd: 0000000000000000
ShdPnd: 0000000000000000
SigBlk: 0000000000000004
SigIgn: 0000000000001002
SigCgt: 0400000180006005
CapInh: 0000000000000000
CapPrm: 00000000fffffeff
CapEff: 00000000fffffeff
Cpus_allowed: 00000000,00000000,00000000,00000000,00000000,00000000,00000000,00ffffff
Mems_allowed: 00000000,00000003
如果我在linux机器上手动运行命令(./garnerdstart),它会显示“SigBlk:0000000000000000”。
这意味着Java会阻止进程?如果是,那么为什么以及在什么情况下??来自java.lang.Process
:
因为某些本机平台仅为提供有限的缓冲区大小
标准输入和输出流,未能及时写入输入
流或读取子流程的输出流可能会导致
子进程阻塞,甚至死锁
详细解释该问题并提出解决方案。您可以使用apache commons exec从java运行命令。它有处理I/P、O/P流的方法,这些方法会阻止缓冲区填充和阻塞进程。谢谢你的回复,但我仍然不清楚你的答案。。请帮我解决这个问题。@Michael。。我已经阅读并尝试了文章中给出的例子(即4.3,4.4)…但我仍然面临同样的问题。
[root@localhost garner]# cat /proc/9282/status
Name: garner
State: S (sleeping)
SleepAVG: 78%
Tgid: 9282
Pid: 9282
PPid: 9281
TracerPid: 0
Uid: 0 0 0 0
Gid: 0 0 0 0
FDSize: 64
Groups: 0 1 2 3 4 6 10
VmPeak: 58888 kB
VmSize: 58884 kB
VmLck: 0 kB
VmHWM: 7124 kB
VmRSS: 7124 kB
VmData: 17192 kB
VmStk: 88 kB
VmExe: 84 kB
VmLib: 4480 kB
VmPTE: 156 kB
StaBrk: 05af0000 kB
Brk: 060ec000 kB
StaStk: 7fff0329d950 kB
Threads: 2
SigQ: 0/47721
SigPnd: 0000000000000000
ShdPnd: 0000000000000000
SigBlk: 0000000000000004
SigIgn: 0000000000001002
SigCgt: 0400000180006005
CapInh: 0000000000000000
CapPrm: 00000000fffffeff
CapEff: 00000000fffffeff
Cpus_allowed: 00000000,00000000,00000000,00000000,00000000,00000000,00000000,00ffffff
Mems_allowed: 00000000,00000003