Java HttpResponse和BufferedReader
我正在尝试读取缓冲区(android应用程序)并将值设置为我的Java HttpResponse和BufferedReader,java,android,httpresponse,bufferedreader,http-get,Java,Android,Httpresponse,Bufferedreader,Http Get,我正在尝试读取缓冲区(android应用程序)并将值设置为我的TextView'httpStuff'。但是我不认为我从URI那里得到了一些回应 我没有得到任何运行时错误。我尝试了许多相同逻辑的味道。似乎什么都没用 INTERNET权限已在清单中设置SdkVersion=“15”。有什么帮助吗 HttpClient client = new DefaultHttpClient(); URI website = new URI("http://www.mybringback.com"); HttpG
TextView
'httpStuff'
。但是我不认为我从URI那里得到了一些回应
我没有得到任何运行时错误。我尝试了许多相同逻辑的味道。似乎什么都没用
INTERNET
权限已在清单中设置<代码>SdkVersion=“15”。有什么帮助吗
HttpClient client = new DefaultHttpClient();
URI website = new URI("http://www.mybringback.com");
HttpGet request = new HttpGet();
request.setURI(website);
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
InputStream is = entity.getContent();
BufferedReader in = new BufferedReader(new InputStreamReader(is));
httpStuf.setText( in.readLine());
尝试获取
响应的状态代码
,然后可以与()
int responseCode=response.getStatusLine().getStatusCode()
我认为您缺少while循环,而且,当您在.readLine()中只说时,可能是它从响应返回了一个空行,尽管它有足够的数据。因此,请确保完全像这样阅读读取器并检查其内容
while ((line = rd.readLine()) != null) {
httpStuf.setText(line+"\r\n");
}
希望这能对您有所帮助。这段代码对我很有用
InputStream is = response.getEntity().getContent();
String strResponse = inputStreamToString(is);
private String inputStreamToString(InputStream is)
{
String line = "";
StringBuilder total = new StringBuilder();
// Wrap a BufferedReader around the InputStream
BufferedReader rd = new BufferedReader(new InputStreamReader(is), 1024 * 4);
// Read response until the end
try
{
while ((line = rd.readLine()) != null)
{
total.append(line);
}
} catch (IOException e)
{
Log.e(TAG, "error build string" + e.getMessage());
}
// Return full string
return total.toString();
}
我使用这个方法只是捕获HTTP响应,它对我来说很好
public String httpGetResponse(String url) {
try {
Log.i("HTTP Request", "httpGet Request for : " + url);
DefaultHttpClient client = new DefaultHttpClient();
HttpGet get = new HttpGet(url);
//get.setHeader("Connection", "keep-alive");
HttpResponse response = client.execute(get);
InputStream is = response.getEntity().getContent();
BufferedReader bufferedReader = new BufferedReader(
new InputStreamReader(is));
StringBuilder str = new StringBuilder();
String line = null;
while ((line = bufferedReader.readLine()) != null) {
str.append(line + "\n");
}
return str.toString();
} catch (Exception e) {
Log.e("HTTP error", "Error in function httpGetResponse : "
+ e.getMessage());
return null;
}
}
我在Oncreate()中添加了下面的代码,它成功了!由于API级别为11,不允许在UI线程上执行网络操作(包括HttpClient和HttpUrlConnection)。如果执行此操作,将获得NetworkOnMainThreadException。StrictMode.ThreadPolicy policy=新建StrictMode.ThreadPolicy.Builder().permitAll().build();StrictMode.setThreadPolicy(策略);我在Oncreate()中添加了下面的代码,它成功了!由于API级别为11,不允许在UI线程上执行网络操作(包括HttpClient和HttpUrlConnection)。如果执行此操作,将获得NetworkOnMainThreadException。StrictMode.ThreadPolicy policy=新建StrictMode.ThreadPolicy.Builder().permitAll().build();StrictMode.setThreadPolicy(策略);我在Oncreate()中添加了下面的代码,它成功了!由于API级别为11,不允许在UI线程上执行网络操作(包括HttpClient和HttpUrlConnection)。如果执行此操作,将获得NetworkOnMainThreadException。StrictMode.ThreadPolicy policy=新建StrictMode.ThreadPolicy.Builder().permitAll().build();StrictMode.setThreadPolicy(策略);您可以使用AsyncTask来修复此问题。以下是一个例子: