Java 在while循环前后确定网格中的间距并实现它

我想知道是否有人给我指出了正确的方向。我正试图弄清楚我将如何设计这段代码：

private static void displaySeating(int s,int n) {

        int  i, k;

        i = 0;
        k = 0;
        while (i < s) {
            i++;
            System.out.print("\t X");
            if (i % 8 == 0) {
                System.out.println();
            }
        }

        while ( k < n) {
            k++;
            System.out.print("\t O");
            if ((k+s) % 8 == 0)  {
                System.out.println();
            }
        }

  }

输出输出如下所示

以下是您想要的：

private static void displaySeating(int s,int n) {

int  i, k;

    i = 0;
    k = 0;

    // print left edge
    System.out.print("#");

    while (i < s) {
        i++;
        System.out.print("\t X");
        if (i % 8 == 0) {
            // print right edge
            System.out.println("\t#");

            // print left edge of next row
            System.out.print("#");
        }
    }        

    while ( k < n) {
        k++;
        System.out.print("\t O");
        if ((k+s) % 8 == 0)  {
            // print right edge
            System.out.println("\t#");

            // print left edge of next row
            System.out.print("#");
        }
    }

    if ((s + n) % 8 != 0) {
        // this means the last row isn't completely full with 0's

        // fill up the row with tabs to get to the edge
        while ((k+s) % 8 != 0) {
            k++;
            System.out.print("\t");
        }
        // print the right edge
        System.out.println("\t#");

        // add the lower edge
        System.out.println("#########################################################################"); 
    } else {
        // this means the last row was filled completely but the left edge of 
        // the next row has already been printed, so we make the lower edge 1 smaller.
        System.out.println("########################################################################");
    }
}

private静态无效显示座位（int s，int n）{
int i，k；
i=0；
k=0；
//打印左边缘
系统输出打印（“#”）；
而（i

编辑

---

发现一个错误：如果

（s+n）%8==0，我们不需要用制表符填充最后一行。在上面的代码中添加了一个补丁。
问题非常不清楚。请正确解释…如果我理解正确，您需要7行
X
，直到达到第一个参数，然后
0
，直到第二个参数？对不起，int变量wick和wickre决定有多少X和o。非常感谢！这样一个简单的解决方案到底！
private static void displaySeating(int s,int n) {

int  i, k;

    i = 0;
    k = 0;

    // print left edge
    System.out.print("#");

    while (i < s) {
        i++;
        System.out.print("\t X");
        if (i % 8 == 0) {
            // print right edge
            System.out.println("\t#");

            // print left edge of next row
            System.out.print("#");
        }
    }        

    while ( k < n) {
        k++;
        System.out.print("\t O");
        if ((k+s) % 8 == 0)  {
            // print right edge
            System.out.println("\t#");

            // print left edge of next row
            System.out.print("#");
        }
    }

    if ((s + n) % 8 != 0) {
        // this means the last row isn't completely full with 0's

        // fill up the row with tabs to get to the edge
        while ((k+s) % 8 != 0) {
            k++;
            System.out.print("\t");
        }
        // print the right edge
        System.out.println("\t#");

        // add the lower edge
        System.out.println("#########################################################################"); 
    } else {
        // this means the last row was filled completely but the left edge of 
        // the next row has already been printed, so we make the lower edge 1 smaller.
        System.out.println("########################################################################");
    }
}