Java 需要帮助解析这个JSON吗
我有以下格式的JSON文件。第一个对象是客户信息,第二个对象是订单信息,然后是n个对象,用于获取每个订购零件的详细信息。我需要把它转换成Java POJO 这就是JSON的样子。这是从外部供应商,所以我必须与它的工作,因为它是Java 需要帮助解析这个JSON吗,java,json,parsing,pojo,jackson-databind,Java,Json,Parsing,Pojo,Jackson Databind,我有以下格式的JSON文件。第一个对象是客户信息,第二个对象是订单信息,然后是n个对象,用于获取每个订购零件的详细信息。我需要把它转换成Java POJO 这就是JSON的样子。这是从外部供应商,所以我必须与它的工作,因为它是 { "report_title": "title", "result_date": "08/12/2020 22:40:51", "company"
{
"report_title": "title",
"result_date": "08/12/2020 22:40:51",
"company": "company name",
"add1": "123 main st",
"add2": null,
"city": "some city",
"state": "state",
"country": "United States of America",
"zip": "12345",
"name": "first last",
"username": "firstlast",
"role": "Manager"
},
{
"launch_date": "08/12/2020 19:05:19",
"client": "client1",
"order_number": "1",
"total_orders": "1",
"type": "type",
"status": "Finished",
"reference": "order reference",
"fulfill": "some name",
"duration": "00:07:12",
"order title": "title",
"order_groups": null,
"part_nums": "1,2,3",
},
{
"part_num": "1234",
"name": "asdf",
"other_name": "asdf",
"manufacturer": "aasdf",
"status": "asdfasf",
"id": 12345,
"title": "some title",
"type": "Ig",
"notes": "long winded notes",
"impact": null,
"solution": null,
},
{
"part_num": "1235",
"name": "asdf1",
"other_name": "asdf1",
"manufacturer": "aasdf1",
"status": "asdfasf1",
"id": 12346,
"title": "some title",
"type": "Ig",
"notes": "long winded notes",
"impact": null,
"solution": null,
}
...
我创建了四个类:Customer、OrderInfo、OrderDetail和Enclosuring类Order
我想我把问题发得有点太早了 我接受了Ajay Kr Choudhary的建议,只是分别解析每个节点并分别映射它们。虽然没有我想要的那么高效或自动化,但总比没有好
JsonNode rootNode = mapper.readTree(inputFile);
Customer customer = mapper.treeToValue(rootNode.get(0), Customer.class);
OrderInfo orderInfo = mapper.treeToValue(rootNode.get(1), OrderInfo.class);
OrderDetail orderDetail = mapper.treeToValue(rootNode.get(2), OrderDetail.class);
您能否分享您的代码和结果,以便我们更好地了解您的尝试?@GiorgiTsiklauri添加了代码片段。不知道投反对票是为了什么?想解释一下吗?这可以在Jackson库的JsonNode的帮助下实现。您可以像这样解析字符串JsonNode inputNode=new ObjectMapper.readTreeinputString;现在,您可以使用索引在inputNode上调用get方法,并获得所需的字段。标准JSON文件应该只包含一个对象,其中其他对象本身就是字段值。这不是一个可怕的问题,但您不能将它们一起输入到标准JSON解析器中。@realponsignist我理解这一点。然而,由于这个json是从外部供应商处收到的,所以我无法控制它。
public static void main (String [] args) {
File inputFile = new File(filepath);
String content = Files.readString(Path.of(inputFile.getPath()), StandardCharsets.US_ASCII);
ObjectMapper mapper = new ObjectMapper();
Customer customer = mapper.readValue(content, Customer.class);
OrderInfo orderInfo = mapper.readValue(content, OrderInfo.class);
}
@Data
@NoArgsConstructor
@JsonIgnoreProperties( ignoreUnknown = true )
public class Customer {
@JsonProperty("report_title") private String reportTitle;
@JsonProperty("result_date") private String resultDate;
@JsonProperty("company") private String company;
...
}
JsonNode rootNode = mapper.readTree(inputFile);
Customer customer = mapper.treeToValue(rootNode.get(0), Customer.class);
OrderInfo orderInfo = mapper.treeToValue(rootNode.get(1), OrderInfo.class);
OrderDetail orderDetail = mapper.treeToValue(rootNode.get(2), OrderDetail.class);