Java spring数据jpa存储库在查询中将集合用作@Param

我在使用SpringDataJPA存储库执行自定义查询时遇到了一个问题

@查询annated方法未指定列表类型的参数

以下是实体类：

@Entity
@Table(name = "\"user\"")
public class User {
  @Id
  @GeneratedValue(generator = "increment")
  private long id;

  @Column(unique = true, nullable = false)
  private String mail;

  @ManyToMany(targetEntity = Interest.class, mappedBy = "users")
  private List<Interest> interests = new ArrayList<Interest>();
  ...
  ... setters and getters.

@Entity
@Table(name = "interest")
public class Interest {
  @Id
  @Column(name = "interest_name", nullable = false, unique = true)
  private String name;

  @ManyToMany(targetEntity = User.class, fetch = FetchType.LAZY)
  private List<User> users = new ArrayList<User>();
  ...
  ... setters and getters.

没有为参数2指定值，尽管第二个参数具有有效值，请按照以下要求更改代码：

   Change the code as per below:

   Old Code:

   `@Repository
   public interface UserRepository extends JpaRepository<User, Long> {
   @Query("select distinct u from User u where u <> :currentUser and
         u.interests in :currentInterests")
   List<User> getUsersWithSameInterests(@Param("currentUser") User user,
         @Param("currentInterests") List<Interest> interests);
   }`

   Updated Code:

   `@Repository
   public interface UserRepository extends JpaRepository<User, Long> {
   @Query("select distinct u from User u where u.user :currentUser 
           and u.interests in :currentInterests")
   List<User> getUsersWithSameInterests(@Param("currentUser") User user,
         @Param("currentInterests") List<Interest> interests);
  }`    

旧代码： `@存储库 公共接口用户存储库扩展了JpaRepository{ @查询（“从用户u中选择不同的u，其中u:currentUser和 u、 利益：当前利益） 列出getUsersWithSameInterests（@Param（“currentUser”）用户， @参数（“当前利益”）列表利益）； }` 更新代码： `@存储库 公共接口用户存储库扩展了JpaRepository{ @查询（“从用户u中选择不同的u，其中u.User:currentUser 和美国利益：当前利益） 列出getUsersWithSameInterests（@Param（“currentUser”）用户， @参数（“当前利益”）列表利益）； }`

---

将值放入父项之间，

。。。u、 对（：currentInterests）

感兴趣，然后查看它是否有效。如果命名参数为

？1

和

？2

，则也可以尝试使用位置占位符。括号和位置占位符都没有帮助。我马上就试过了。

：currentInterests

放在括号内。

@Autowired
private UserRepository userRepository;
  @Override
  public List<User> getUsersWithSameInterests(User user) {
    return userRepository.getUsersWithSameInterests(user, user.getInterests());
  }

org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not extract ResultSet
.
.
.
Caused by: java.sql.SQLException: No value specified for parameter 2
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:957)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:896)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:885)
at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:860)
at com.mysql.jdbc.PreparedStatement.checkAllParametersSet(PreparedStatement.java:2205)
at com.mysql.jdbc.PreparedStatement.fillSendPacket(PreparedStatement.java:2185)
at com.mysql.jdbc.PreparedStatement.fillSendPacket(PreparedStatement.java:2115)
at com.mysql.jdbc.PreparedStatement.executeQuery(PreparedStatement.java:1936)
at org.apache.commons.dbcp2.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:83)
at org.apache.commons.dbcp2.DelegatingPreparedStatement.executeQuery(DelegatingPreparedStatement.java:83)
at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.extract(ResultSetReturnImpl.java:70)
... 73 more

   Change the code as per below:

   Old Code:

   `@Repository
   public interface UserRepository extends JpaRepository<User, Long> {
   @Query("select distinct u from User u where u <> :currentUser and
         u.interests in :currentInterests")
   List<User> getUsersWithSameInterests(@Param("currentUser") User user,
         @Param("currentInterests") List<Interest> interests);
   }`

   Updated Code:

   `@Repository
   public interface UserRepository extends JpaRepository<User, Long> {
   @Query("select distinct u from User u where u.user :currentUser 
           and u.interests in :currentInterests")
   List<User> getUsersWithSameInterests(@Param("currentUser") User user,
         @Param("currentInterests") List<Interest> interests);
  }`