Java 使用Jongo和Jackson 2,如何将MongoDB对象id(在POJO中以字符串_id表示)反序列化为十六进制字符串表示?
我使用最新版本的MongoDB数据库和最新版本的官方JAVA MongoDB驱动程序 我在pom.xml中使用的依赖项:Java 使用Jongo和Jackson 2,如何将MongoDB对象id(在POJO中以字符串_id表示)反序列化为十六进制字符串表示?,java,mongodb,jackson,jersey-2.0,jongo,Java,Mongodb,Jackson,Jersey 2.0,Jongo,我使用最新版本的MongoDB数据库和最新版本的官方JAVA MongoDB驱动程序 我在pom.xml中使用的依赖项: <properties> <project.build.sourceEncoding>UTF-8</project.build.sourceEncoding> <maven.compiler.source>1.7</maven.compiler.source>
<properties>
<project.build.sourceEncoding>UTF-8</project.build.sourceEncoding>
<maven.compiler.source>1.7</maven.compiler.source>
<maven.compiler.target>1.7</maven.compiler.target>
...
<jersey.container.version>2.13</jersey.container.version>
<jackson.version>2.4.3</jackson.version>
<genson.version>1.1</genson.version>
<jongo.version>1.1</jongo.version>
</properties>
<dependencies>
...
<dependency>
<groupId>org.glassfish.jersey.containers</groupId>
<artifactId>jersey-container-servlet</artifactId>
<version>${jersey.container.version}</version>
</dependency>
<dependency>
<groupId>org.glassfish.jersey.media</groupId>
<artifactId>jersey-media-json-jackson</artifactId>
<version>${jersey.container.version}</version>
</dependency>
<!-- Required only when you are using JAX-RS Client -->
<dependency>
<groupId>org.glassfish.jersey.core</groupId>
<artifactId>jersey-client</artifactId>
<version>${jersey.container.version}</version>
</dependency>
<dependency>
<groupId>javax.ws.rs</groupId>
<artifactId>javax.ws.rs-api</artifactId>
<version>2.0.1</version>
</dependency>
<dependency>
<groupId>org.glassfish.jersey.media</groupId>
<artifactId>jersey-media-multipart</artifactId>
<version>2.13</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-core</artifactId>
<version>${jackson.version}</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>${jackson.version}</version>
</dependency>
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-annotations</artifactId>
<version>${jackson.version}</version>
</dependency>
<dependency>
<groupId>org.jongo</groupId>
<artifactId>jongo</artifactId>
<version>${jongo.version}</version>
</dependency>
<dependency>
<groupId>org.mongodb</groupId>
<artifactId>mongo-java-driver</artifactId>
<version>2.12.3</version>
</dependency>
</dependencies>
我的web服务:
import javax.ws.rs.Consumes;
import javax.ws.rs.DELETE;
import javax.ws.rs.GET;
import javax.ws.rs.POST;
import javax.ws.rs.PUT;
import javax.ws.rs.Path;
import javax.ws.rs.PathParam;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import com.hive5.dao.UsersDAO;
import com.hive5.enums.CustomHttpResponse;
import com.hive5.pojo.User;
@Path("/v1")
public class V1_Users {
@GET
@Path("/users/{firstName}")
@Produces(MediaType.APPLICATION_JSON)
public Response getUser(@PathParam("firstName") String firstName) {
if (firstName != null && !firstName.trim().isEmpty()) {
Response response = UsersDAO.getUser(firstName);
return response;
} else {
return Response
.status(CustomHttpResponse.REQUEST_NOT_ACCEPTABLE
.getStatusCode())
.entity(CustomHttpResponse.REQUEST_NOT_ACCEPTABLE
.getStatusMessage()).build();
}
}
...
}
我的刀:
import java.io.IOException;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import javax.ws.rs.core.Response;
import org.apache.log4j.Logger;
import org.bson.types.ObjectId;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.hive5.enums.CustomHttpResponse;
import com.hive5.pojo.User;
import com.mongodb.BasicDBObject;
import com.mongodb.DB;
import com.mongodb.DBCollection;
import com.mongodb.DBCursor;
import com.mongodb.DBObject;
import com.mongodb.MongoClient;
import com.mongodb.MongoException;
public class UsersDAO {
...
public static Response getUser(String firstName) {
DB db = MONGO_CLIENT.getDB(DATABASE_NAME);
DBCollection collection = db.getCollection("users");
BasicDBObject whereQuery = new BasicDBObject();
whereQuery.put("firstName", firstName);
DBCursor cursor = null;
DBObject dbObject = null;
User user = null;
ObjectMapper mapper = new ObjectMapper();
CustomHttpResponse customHttpResponse = CustomHttpResponse.OK;
try {
cursor = collection.find(whereQuery).limit(1);
if (cursor.count() > 0) {
dbObject = cursor.next();
user = mapper.readValue(dbObject.toString(), User.class);
} else {
// User Not Found
customHttpResponse = CustomHttpResponse.NOT_FOUND_CUSTOM;
customHttpResponse
.formatStatusMessagePatternWithArguments(firstName);
}
} catch (MongoException | IOException e) {
customHttpResponse = CustomHttpResponse.INTERNAL_SERVER_ERROR;
LOG_TO_CONSOLE.fatal(e, e);
LOG_TO_FILE.fatal(e, e);
} finally {
if (customHttpResponse == CustomHttpResponse.OK
|| customHttpResponse == CustomHttpResponse.NOT_FOUND_CUSTOM) {
LOG_TO_CONSOLE.debug(customHttpResponse.toString());
}
}
Response response = null;
switch (customHttpResponse) {
case OK:
System.out.println("user.get_id() -> " + user.get_id());
response = Response.status(customHttpResponse.getStatusCode())
.entity(user).build();
break;
default:
response = Response.status(customHttpResponse.getStatusCode())
.entity(customHttpResponse.getStatusMessage()).build();
break;
}
return response;
}
...
}
tomcat web服务器控制台中显示的输出(在请求了上面的web服务之后,请参阅上面的我的DAO类和getUser(String firstName){…}方法):
使用POSTMAN请求web服务后得到的JSON结果:
{
"firstName": "Yolo",
"lastName": "DOUCE",
"age": 31,
"_id": {
"new": false,
"inc": -2041720087,
"machine": -1473854181,
"timeSecond": 1413818742,
"timestamp": 1413818742,
"time": 1413818742000,
"date": 1413818742000
}
}
正如您所看到的,_id字段不是十六进制字符串格式,而是有多个字段,这不是我所期望的
1-实际上,在我的DAO中,我能够打印此字段的十六进制字符串格式,因此我不明白为什么在我的web服务中,它返回一个显然包含字符串id对象表示形式的响应?
2-我的第二个问题是,在我的特殊情况下,如何使用jongo和/或jackson Quicker xml V2和MongoDB反序列化为JSON并返回字符串id(位于我的用户POJO中的字段)的十六进制字符串表示形式?始终使用@ObjectId将属性映射到ObjectId的新实例。将此属性映射到字符串时,这是错误的
为了避免这种行为,我们可以使用以下自定义JSON序列化程序类(最初由某个用户1878815提供)NoObjectIdSerializer,我对其进行了一些修改:
import java.io.IOException;
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.SerializerProvider;
public class NoObjectIdSerializer extends JsonSerializer<String> {
@Override
public void serialize(String value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonProcessingException {
if(value == null){
jgen.writeNull();
}else{
jgen.writeString(value);
}
}
}
有
这个答案是基于之前的答案提供的,非常感谢他
另外,要获得更详细的解释,请遵循以下步骤
{
"firstName": "Yolo",
"lastName": "DOUCE",
"age": 31,
"_id": {
"new": false,
"inc": -2041720087,
"machine": -1473854181,
"timeSecond": 1413818742,
"timestamp": 1413818742,
"time": 1413818742000,
"date": 1413818742000
}
}
import java.io.IOException;
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.SerializerProvider;
public class NoObjectIdSerializer extends JsonSerializer<String> {
@Override
public void serialize(String value, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonProcessingException {
if(value == null){
jgen.writeNull();
}else{
jgen.writeString(value);
}
}
}
import org.jongo.marshall.jackson.oid.ObjectId;
import com.fasterxml.jackson.databind.annotation.JsonSerialize;
import com.mypackage.NoObjectIdSerializer;
import com.google.common.base.MoreObjects;
import java.util.Objects;
public class User {
@ObjectId
@JsonSerialize(using = NoObjectIdSerializer.class)
protected final String _id;
...
}