Java org.springframework.orm.jpa.JpaSystemException:无法通过反射设置字段值[POST_INSERT_INDICATOR]值

我与一个Spring Boot项目合作，我有以下实体

@Entity
public class Ip {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "IP_ADDR_ID_2")
    private Long id;

    @Column(name = "IP_ADDRESS_2")
    @NotEmpty
    private String address;

    @OneToMany(cascade = CascadeType.ALL, mappedBy = "ip")
    private List<IMAssociation> httpInfoMessages2;

}

列表

是通过代码生成的

List<IMAssociation> imAssociations = new ArrayList<>();

for(int j =0; j < 5; j++){

     IMAssociation imAssociation = new IMAssociation(Long.valueOf(integerListEntry.getKey()),
                                            message);
    imAssociations.add(imAssociation);
}


Ip ip = new Ip('127.0.0.1', imAssociations); 

List<Ip> ips = new ArrayList<>();
ips.add(ip);

这里的问题是什么

更新

我已经更改了

I关联

类及其下面提供的

@Entity
public class Message {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "S_ID_2")
    private Long sId;

    @Column(name = "STATUS_ID_2")
    private Long statusId;

    @NotEmpty
    @Column(name = "STATUS_2")
    private String status;

    @OneToMany(cascade = CascadeType.ALL, mappedBy = "message")
    private List<IMAssociation> message;
}

@Entity
@Table(name = "IP_HTTP_MESSAGE")
//@IdClass(AssociationId.class)
public class IMAssociation implements Serializable {

//    @Id
//    @GeneratedValue(strategy = GenerationType.IDENTITY)
//    private Long id;

    @Id
    @Column(name = "IP_ADDRESS_ID")
    private Long ipAddressId;

    @Id
    @Column(name = "HTTP_MESSAGE_ID")
    private Long httpMessageId;

    @ManyToOne
    @PrimaryKeyJoinColumn(name = "IP_ADDRESS_ID", referencedColumnName = "IP_ADDR_ID_2")
//    @JoinColumn(name = "ipAddressId", updatable = false, insertable = false, referencedColumnName = "IP_ADDR_ID_2")
    private Ip ip;

    @ManyToOne
    @PrimaryKeyJoinColumn(name = "HTTP_MESSAGE_ID", referencedColumnName = "S_ID_2")
//    @JoinColumn(name = "httpMessageId", updatable = false, insertable = false, referencedColumnName = "S_ID_2")
    private Message message;


    //    @ManyToOne
    @JoinColumn(name = "IP_ADDRESS_2", updatable = false, insertable = false, referencedColumnName = "IP_ADDRESS_2")
    private String address;

    @JoinColumn(name = "STATUS_CODE", updatable = false, insertable = false, referencedColumnName = "STATUS_ID_2")
    private Long code;

    @JoinColumn(name = "STATUS_MESSAGE", updatable = false, insertable = false, referencedColumnName = "STATUS_2")
    private String codeMessage;


    public IMAssociation() {
    }

    public IMAssociation(Long code, String codeMessage) {
        this.code = code;
        this.codeMessage = codeMessage;
    }
}

现在，我在运行应用程序时出现以下错误

Caused by: javax.persistence.EntityExistsException: A different object with the same identifier value was already associated with the session : [com.ef.entity.IMAssociation#IMAssociation{, ipAddressId=null, httpMessageId=null, ip=null, message=null, address='null', code=404, codeMessage='404_Not Found'}]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1664) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1602) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1608) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:1152) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at sun.reflect.GeneratedMethodAccessor19.invoke(Unknown Source) ~[na:na]
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[na:1.8.0_144]
    at java.lang.reflect.Method.invoke(Method.java:498) ~[na:1.8.0_144]

这就是你的问题：

SO的类似职位：

您可以在此处有3个选项：

您仍然可以实现复合键，但必须删除

imaassociation

实体中自动生成的Id。复合密钥将仅由两个属性组成—

ipAddressId

和

httpMessageId

，它们分别是从

地址

和

消息

实体派生的/外键

或者实现一个主键：在这里，您可以通过标识策略使用id自动生成，但必须删除您声明的其他id字段--

ipAddressId

和

httpMessageId

如果仍要保留3个Id字段-

Id

、

ipAddressId

和

httpMessageId

，请删除Id自动生成（

@GeneratedValue

注释），并手动为

iAssociation

实体分配Id值

---

可能不需要

ipAddressId

和

httpMessageId

我认为保存这些值的列是通过

@PrimaryKeyJoinColumn

注释在dblevel中自动生成的，并且可以通过

ip.getMessage（）和
ip.getId（）在
imaassociation
中访问该值
请查看您的实体中有多个主键
i关联
。您可以声明具有复合主键/复合键的
@IdClass
或
@EmbeddedId
，但我看不出您使用了其中任何一个。此外，您在此处使用的
@PrimaryKeyJoinColumn
不正确。属性
name
应该映射到表的物理列名，而不是某些实体属性。所以它应该是
@PrimaryKeyColumn（name=“IP\u ADDRESS\u ID”，referencedColumnName=“IP\u ADDR\u ID\u 2”）
和
@PrimaryKeyColumn（name=“HTTP\u MESSAGE\u ID”，referencedColumnName=“S\u ID\u 2”）
我已经尝试过
@IdClass（AssociationId.class）
在
Ip
类的顶部，其中
AssociationId
实现了
可序列化的
。这并不能解决问题，仍然会提供相同的错误。使用
@EmbeddedId
的正确方法是什么？我用它代替了
@Id
，得到了一些error@Ish实际上，我已经尝试了我提供的所有建议，但仍然得到相同的错误。如果您现在有一个开放的IDE，您是否介意提供一个有效的解决方案？我已经尝试了第一个选项，但出现了一些错误。我在更新的问题中提供了错误堆栈。如果您能提供一个有效的解决方案，我将不胜感激，因为这样做不会出错，但令人惊讶的是，我在地址列中找不到任何值，我想是wiredremove
String address
和使用
ip.getAddress（）
@Entity
@Table(name = "IP_HTTP_MESSAGE")
//@IdClass(AssociationId.class)
public class IMAssociation implements Serializable {

//    @Id
//    @GeneratedValue(strategy = GenerationType.IDENTITY)
//    private Long id;

    @Id
    @Column(name = "IP_ADDRESS_ID")
    private Long ipAddressId;

    @Id
    @Column(name = "HTTP_MESSAGE_ID")
    private Long httpMessageId;

    @ManyToOne
    @PrimaryKeyJoinColumn(name = "IP_ADDRESS_ID", referencedColumnName = "IP_ADDR_ID_2")
//    @JoinColumn(name = "ipAddressId", updatable = false, insertable = false, referencedColumnName = "IP_ADDR_ID_2")
    private Ip ip;

    @ManyToOne
    @PrimaryKeyJoinColumn(name = "HTTP_MESSAGE_ID", referencedColumnName = "S_ID_2")
//    @JoinColumn(name = "httpMessageId", updatable = false, insertable = false, referencedColumnName = "S_ID_2")
    private Message message;


    //    @ManyToOne
    @JoinColumn(name = "IP_ADDRESS_2", updatable = false, insertable = false, referencedColumnName = "IP_ADDRESS_2")
    private String address;

    @JoinColumn(name = "STATUS_CODE", updatable = false, insertable = false, referencedColumnName = "STATUS_ID_2")
    private Long code;

    @JoinColumn(name = "STATUS_MESSAGE", updatable = false, insertable = false, referencedColumnName = "STATUS_2")
    private String codeMessage;


    public IMAssociation() {
    }

    public IMAssociation(Long code, String codeMessage) {
        this.code = code;
        this.codeMessage = codeMessage;
    }
}

Caused by: javax.persistence.EntityExistsException: A different object with the same identifier value was already associated with the session : [com.ef.entity.IMAssociation#IMAssociation{, ipAddressId=null, httpMessageId=null, ip=null, message=null, address='null', code=404, codeMessage='404_Not Found'}]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1664) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1602) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.convert(AbstractEntityManagerImpl.java:1608) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at org.hibernate.jpa.spi.AbstractEntityManagerImpl.persist(AbstractEntityManagerImpl.java:1152) ~[hibernate-entitymanager-5.0.12.Final.jar:5.0.12.Final]
    at sun.reflect.GeneratedMethodAccessor19.invoke(Unknown Source) ~[na:na]
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[na:1.8.0_144]
    at java.lang.reflect.Method.invoke(Method.java:498) ~[na:1.8.0_144]