Java 如何从Android的webService创建图像
所以,我有一个连接到Web服务的应用程序,我已经在那里检索数据了,现在我想检索一个图像链接,让imageView通过链接获取该图像。这可能吗?感谢您的帮助:DJava 如何从Android的webService创建图像,java,android,json,imageurl,Java,Android,Json,Imageurl,所以,我有一个连接到Web服务的应用程序,我已经在那里检索数据了,现在我想检索一个图像链接,让imageView通过链接获取该图像。这可能吗?感谢您的帮助:D @Override protected Void doInBackground(Void... params) { HttpHandler sh = new HttpHandler(); String jsonStr = sh.makeServiceCall(url);
@Override
protected Void doInBackground(Void... params) {
HttpHandler sh = new HttpHandler();
String jsonStr = sh.makeServiceCall(url);
Log.e(TAG, "Response from URL: " + jsonStr);
if (jsonStr != null) {
try {
JSONArray array = new JSONArray(jsonStr);
for (int i = 0; i < array.length(); i++) {
JSONObject jsonObject = array.getJSONObject(i);
JSONArray paises = jsonObject.optJSONArray("paises");
if (paises != null) {
for (int j = 0; j < paises.length(); j++) {
JSONObject jsonObject1 = paises.getJSONObject(j);
System.out.println(jsonObject1.optString("Designacao"));
String K_PAIS = jsonObject1.getString("K_PAIS");
String Designacao = jsonObject1.getString("Designacao");
String URL_IMAGE_SMALL = jsonObject1.getString("URL_IMAGE_SMALL");
String URL_IMAGEM = "http://something.something.pt" + URL_IMAGE_SMALL;
new DownloadImage(imageView6).execute(URL_IMAGEM);
HashMap<String, String> pais = new HashMap<>();
pais.put("K_PAIS", K_PAIS);
pais.put("Designacao", Designacao);
pais.put("URL_IMAGE_SMALL", URL_IMAGE_SMALL);
pais.put("URL_IMAGEM", URL_IMAGEM);
listaPaises.add(pais);
}
}
System.out.println(jsonObject.optString("Designacao"));
}
} catch (final JSONException e) {
Log.e(TAG, "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(), "Json parsin error: " + e.getMessage(), Toast.LENGTH_LONG).show();
}
});
}
} else {
Log.e(TAG, "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(), "Couldn't get json from server. Check LogCat for possible errpr!", Toast.LENGTH_LONG).show();
}
});
}
return null;
}
{...}
public class DownloadImage extends AsyncTask<String, Void, Bitmap> {
ImageView bmImage;
public DownloadImage(ImageView bmImage) {
this.bmImage = (ImageView) bmImage;
}
protected Bitmap doInBackground(String... urls) {
String urldisplay = urls[0];
Bitmap mIcon11 = null;
try {
InputStream in = new java.net.URL(urldisplay).openStream();
mIcon11 = BitmapFactory.decodeStream(in);
} catch (Exception e) {
Log.d("Error", e.getStackTrace().toString());
}
return mIcon11;
}
protected void onPostExecute(Bitmap result) {
bmImage.setImageBitmap(result);
}
}
@覆盖
受保护的Void doInBackground(Void…参数){
HttpHandler sh=新的HttpHandler();
字符串jsonStr=sh.makeServiceCall(url);
Log.e(标签,“来自URL的响应:+jsonStr”);
if(jsonStr!=null){
试一试{
JSONArray数组=新的JSONArray(jsonStr);
对于(int i=0;i
您可以使用任何第三方库
示例使用Glide
库
此库将帮助您从url
获取并显示ImageView
上的图像
例如:
Glide.with(context).load(image_url).into(your_image_view);
这里是该库的链接:您可以使用,这是一个很棒的图像库
例如:
Picasso.with(context).load("http://i.imgur.com/DvpvklR.png").into(imageView);
通过Gradle添加依赖项:
compile 'com.squareup.picasso:picasso:2.5.2'
您必须像平常一样在XML中设置ImageView。然后,您可以使用任何第三方库,如或,从url加载图像,并将其设置为活动/片段中的ImageView。在应用程序构建中。gradle add
compile 'com.github.bumptech.glide:glide:3.7.0'
使用此代码从url加载图像
Glide.with(getApplicationContext()).load("image_url").into(ImageView);
如果不想使用第三方库,请尝试此操作
new DownloadImage(imamgeview).execute(url);
创建异步任务
public class DownloadImage extends AsyncTask<String, Void, Bitmap> {
CircleImageView bmImage;
public DownloadImage(ImageView bmImage) {
this.bmImage = (CircleImageView) bmImage;
}
protected Bitmap doInBackground(String... urls) {
String urldisplay = urls[0];
Bitmap mIcon11 = null;
try {
InputStream in = new java.net.URL(urldisplay).openStream();
mIcon11 = BitmapFactory.decodeStream(in);
} catch (Exception e) {
Log.d("Error", e.getStackTrace().toString());
}
return mIcon11;
}
protected void onPostExecute(Bitmap result) {
bmImage.setImageBitmap(result);
}
}
public类下载映像任务{
圆形图像视图bmImage;
公共下载图像(ImageView bmImage){
this.bmImage=(CircleImageView)bmImage;
}
受保护位图doInBackground(字符串…URL){
字符串urldisplay=url[0];
位图mIcon11=null;
试一试{
InputStream in=newjava.net.URL(urldisplay.openStream();
mIcon11=BitmapFactory.decodeStream(in);
}捕获(例外e){
Log.d(“错误”,例如getStackTrace().toString());
}
返回mIcon11;
}
受保护的void onPostExecute(位图结果){
bmImage.setImageBitmap(结果);
}
}
我希望它能在您的情况下起作用步骤1:创建名为DownloadImage的类
public class DownloadImage extends AsyncTask<String, Void, Bitmap> {
CircleImageView bmImage;
public DownloadImage(ImageView bmImage) {
this.bmImage = (CircleImageView) bmImage;
}
protected Bitmap doInBackground(String... urls) {
String urldisplay = urls[0];
Bitmap mIcon11 = null;
try {
InputStream in = new java.net.URL(urldisplay).openStream();
mIcon11 = BitmapFactory.decodeStream(in);
} catch (Exception e) {
Log.d("Error", e.getStackTrace().toString());
}
return mIcon11;
}
protected void onPostExecute(Bitmap result) {
bmImage.setImageBitmap(result);
}
}
**Json Url如下:*可能与So重复,请澄清,在“new DownloadImage(imamgeview).execute(Url);”中,“Url”是保存链接的变量,对吗?不,应用程序崩溃。。。我有一个变量(URL_IMAGEM),它是json中的一个字符串,我将它添加到execute()中,但是没有luckcan u请将代码粘贴到这里,这样我可以帮助您输入URL。我不明白什么URL?
new DownloadImage(imgUserProfile).execute(userProfileUrl);