如何使用Java中的Jackson将该字符串反序列化为POJO表示?
这就是我目前使用Jackson的方式,但它失败了。我错过了什么如何使用Java中的Jackson将该字符串反序列化为POJO表示?,java,jackson,Java,Jackson,这就是我目前使用Jackson的方式,但它失败了。我错过了什么 { "id":"1", "type":"add", "version": 20146780, "fields": { "pid":"1234", "location":"99,100", "lastModified":"2013-12-30T22:15:37.482Z" } } 不确定可选类在这里做什么,但您可以通过执行以下操作来获取UpdateRequest对象 public Optional&
{
"id":"1",
"type":"add",
"version": 20146780,
"fields": {
"pid":"1234",
"location":"99,100",
"lastModified":"2013-12-30T22:15:37.482Z"
}
}
不确定可选类在这里做什么,但您可以通过执行以下操作来获取UpdateRequest对象
public Optional<UpdateRequest> deserialize(String message) {
ObjectMapper mapper = new ObjectMapper();
Optional<UpdateRequest> updateRequest = Optional
.empty();
try {
updateRequest = Optional.of(mapper.readValue(message,
UpdateRequest.class));
System.out.println(mapper
.writeValueAsString(updateRequest));
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return updateRequest;
}
您可能想看看这篇文档。我收到了一个例外。您可以发布例外的前几行吗?
public Optional<UpdateRequest> deserialize(String message) {
ObjectMapper mapper = new ObjectMapper();
Optional<UpdateRequest> updateRequest = Optional
.empty();
try {
updateRequest = Optional.of(mapper.readValue(message,
UpdateRequest.class));
System.out.println(mapper
.writeValueAsString(updateRequest));
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return updateRequest;
}
UpdateRequest updateRequest = mapper.readValue(message, UpdateRequest.class);