如何使用多线程在java中切换交通灯,使每个灯只亮3秒钟?
我制作了一个交通灯刺激系统,其中每个交通灯,即绿色、红色、黄色,将分别亮3秒钟。 我成功地创建了这个系统的GUI如何使用多线程在java中切换交通灯,使每个灯只亮3秒钟?,java,multithreading,Java,Multithreading,我制作了一个交通灯刺激系统,其中每个交通灯,即绿色、红色、黄色,将分别亮3秒钟。 我成功地创建了这个系统的GUI public class TrafficLightSimulator extends Application implements Runnable{ Circle red = new Circle(); Circle green = new Circle(); Circle yellow = new Circle(); Button b1 = new
public class TrafficLightSimulator extends Application implements Runnable{
Circle red = new Circle();
Circle green = new Circle();
Circle yellow = new Circle();
Button b1 = new Button();
@Override
public void start(Stage stage) {
//Drawing a Rectangle
Rectangle rectangle = new Rectangle();
//grid layout
GridPane grid = new GridPane();
grid.setHgap(20);
grid.setVgap(5);
//buttons
HBox hbButtons = new HBox();
Button buttonStart = new Button("Start");
Button buttonStop = new Button("Stop");
buttonStart.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
green.setFill(Color.YELLOW);
}
});
buttonStop.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
TrafficLightSimulator tl=new TrafficLightSimulator();
Thread t1=new Thread(tl);
t1.start();
}
});
//labels and textfeilds
Label lblGreen = new Label("Green");
TextField tfGreen = new TextField("3");
Label lblYellow = new Label("Yellow");
TextField tfYellow = new TextField("3");
Label lblRed = new Label("Red");
TextField tfRed = new TextField("3");
grid.add(lblGreen, 0, 0);
grid.add(tfGreen, 1, 0);
grid.add(lblYellow, 0, 1);
grid.add(tfYellow, 1, 1);
grid.add(lblRed, 0, 2);
grid.add(tfRed, 1, 2);
grid.setPadding(new Insets(320, 5, 30, 40));
hbButtons.getChildren().addAll(buttonStart, buttonStop);
hbButtons.setAlignment(Pos.BOTTOM_CENTER);
//Setting the properties of the rectangle
rectangle.setX(150);
rectangle.setY(75);
rectangle.setWidth(400);
rectangle.setHeight(200);
rectangle.setArcHeight(50);
rectangle.setArcWidth(50);
Color c = Color.web("#404040");
Color color1 = Color.web("#404040");
Color color2 = Color.web("#808080");
Color greenColor = Color.web("#00FF00");
rectangle.setFill(c);
//setting circle properties
green.setCenterX(230);
green.setCenterY(170);
green.setRadius(50);
green.setFill(greenColor);
yellow.setCenterX(345);
yellow.setCenterY(170);
yellow.setRadius(50);
yellow.setFill(color2);
red.setCenterX(465);
red.setCenterY(170);
red.setRadius(50);
red.setFill(color2);
hbButtons.setPadding(new Insets(15, 12, 15, 12));
hbButtons.setSpacing(10); // Gap between nodes
//Creating a Group object
StackPane rootPane = new StackPane();
Pane p1 = new Pane(red, green, yellow);
Pane p2 = new Pane(rectangle);
grid.add(hbButtons, 2, 2, 2, 1);
// grid.add(grid, 2, 0, 0, 0);
rootPane.getChildren().addAll(p2, p1, grid);
//Creating a scene object
Scene scene = new Scene(rootPane, 600, 500);
//Setting title to the Stage
stage.setTitle("Drawing a Rectangle");
//Adding scene to the stage
stage.setScene(scene);
//Displaying the contents of the stage
stage.show();
}
将“开始”按钮的事件处理程序更改为:
buttonStart.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
Thread t = new Thread() {
@Override
public void run() {
try {
green.setFill(Color.GREEN);
Thread.sleep(3000L);
green.setFill(Color.GRAY);
yellow.setFill(Color.YELLOW);
Thread.sleep(3000L);
yellow.setFill(Color.GRAY);
red.setFill(Color.RED);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
}
});
buttonStart.setOnAction(新的EventHandler(){
公共无效句柄(ActionEvent事件){
线程t=新线程(){
@凌驾
公开募捐{
试一试{
绿色。设置填充(颜色。绿色);
线程。睡眠(3000L);
绿色。刚毛填充(颜色。灰色);
黄色。设置填充(颜色。黄色);
线程。睡眠(3000L);
黄色。刚毛填充(颜色。灰色);
红色。设置填充(颜色。红色);
}捕捉(中断异常e){
e、 printStackTrace();
}
}
};
t、 start();
}
});
请注意,圆的颜色在新线程中更新
在JavaFX中,事件和UI更新都由同一个JavaFX应用程序线程处理。如果我们不在其他线程中运行这些UI更新,渲染将一直阻止,直到事件处理程序完成。谢谢!!!它工作得很好,但我认为我们必须在代码中稍加修改,才能从定时器的文本框中获取文本值。我们还需要添加一个按钮停止操作侦听器来停止线程
buttonStart.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
Thread t = new Thread() {
@Override
public void run() {
try {
green.setFill(Color.GREEN);
System.out.println(Long.parseLong(tfGreen.getText()));
Thread.sleep(Long.parseLong(tfGreen.getText()) * 1000);
green.setFill(Color.GRAY);
yellow.setFill(Color.YELLOW);
Thread.sleep(Long.parseLong(tfYellow.getText()) * 1000);
yellow.setFill(Color.GRAY);
red.setFill(Color.RED);
Thread.sleep(Long.parseLong(tfRed.getText()) * 1000);
red.setFill(Color.GRAY);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
buttonStop.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
green.setFill(Color.GRAY);
yellow.setFill(Color.GRAY);
red.setFill(Color.GRAY);
t.stop();
}
});
}
});
buttonStart.setOnAction(新的EventHandler(){
公共无效句柄(ActionEvent事件){
线程t=新线程(){
@凌驾
公开募捐{
试一试{
绿色。设置填充(颜色。绿色);
System.out.println(Long.parseLong(tfGreen.getText());
sleep(Long.parseLong(tfGreen.getText())*1000);
绿色。刚毛填充(颜色。灰色);
黄色。设置填充(颜色。黄色);
sleep(Long.parseLong(tfYellow.getText())*1000);
黄色。刚毛填充(颜色。灰色);
红色。设置填充(颜色。红色);
sleep(Long.parseLong(tfRed.getText())*1000);
红色。刚毛填充(颜色。灰色);
}捕捉(中断异常e){
e、 printStackTrace();
}
}
};
t、 start();
setOnAction(新的EventHandler(){
公共无效句柄(ActionEvent事件){
绿色。刚毛填充(颜色。灰色);
黄色。刚毛填充(颜色。灰色);
红色。刚毛填充(颜色。灰色);
t、 停止();
}
});
}
});
看看java.util.Timer,这里有一个例子:非常感谢您提供的解决方案。它对我非常有用。
buttonStart.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
Thread t = new Thread() {
@Override
public void run() {
try {
green.setFill(Color.GREEN);
System.out.println(Long.parseLong(tfGreen.getText()));
Thread.sleep(Long.parseLong(tfGreen.getText()) * 1000);
green.setFill(Color.GRAY);
yellow.setFill(Color.YELLOW);
Thread.sleep(Long.parseLong(tfYellow.getText()) * 1000);
yellow.setFill(Color.GRAY);
red.setFill(Color.RED);
Thread.sleep(Long.parseLong(tfRed.getText()) * 1000);
red.setFill(Color.GRAY);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
};
t.start();
buttonStop.setOnAction(new EventHandler<ActionEvent>() {
public void handle(ActionEvent event) {
green.setFill(Color.GRAY);
yellow.setFill(Color.GRAY);
red.setFill(Color.GRAY);
t.stop();
}
});
}
});