Java：按字母顺序输入的名称的选择排序

我已经有了使用数组进行选择排序的代码：

public class SelectionSortTest
{ 

 public static void main(String[] args)
 {
      String[] stringArray = {"Flash", "Green Arrow", "superman", "spiderman", "green lantern"};

      System.out.println("Unsorted array:");
      for(String element: stringArray)
           System.out.print(element + " ");
      System.out.println();

      selectionSort(stringArray);

      System.out.println("Sorted array:");
      for(String element: stringArray)
            System.out.print(element + " ");
      System.out.println();
 }


 static void selectionSort(Comparable[] array)
 {
      int smallindex;
      for(int i = 0; i < array.length; i++)
      {
           smallindex = i; // set first element as smallest
           for(int j = i + 1; j < array.length; j++) // find smallest
                if(array[j].compareTo(array[smallindex]) < 0)
                     smallindex = j;
           if(smallindex != i)
                swap(array, smallindex, i);
      }
 }


 static void swap(Object[] array, int index1, int index2)
 {
      Object temp = array[index1];
      array[index1] = array[index2];
      array[index2] = temp;
 } 
}

与：

扫描仪输入=新扫描仪（System.in）；
对于（int i=0；

---

但它不起作用。有什么建议吗？

您可以添加以下代码以输入逗号分隔的字符串作为用户输入

    Scanner input = new Scanner(System.in);
    String inputArray = input.next();
    String[] stringArray = inputArray.split(","); 

现在您可以使用

stringArray

并执行其余代码。希望这对您有所帮助

---

干杯！

您必须首先初始化阵列

Scanner sc = new Scanner(System.in);
System.err.println("enter size of ur table");
int size = sc.nextInt();    
String array[] = new String[size];
for (int i = 0; i < size; i++) {
array[i] = sc.nextLine();
System.err.println("element " + i + "is :" + array[i]);
} 

Scanner sc=新扫描仪（System.in）；
System.err.println（“输入您表格的大小”）；
int size=sc.nextInt（）；
字符串数组[]=新字符串[大小]；
对于（int i=0；i

别介意，伙计们，我知道怎么做了：

import java.util.Scanner;

public class selectionsort
{ 
public static void main (String args[])
{
    Scanner in = new Scanner (System.in);
    System.out.print ("Enter the number of names you wish to enter: ");
    int n = in.nextInt();
    String array[] = new String [n]; //Array to store the names in.

in.nextLine(); // < --- an extra next Line

for (int i = 0; i < array.length; i++)
{
    System.out.println("Please enter the name: ");
    array[i]= in.nextLine();

}
   System.out.println("Unsorted array:");
      for(String element: array)
           System.out.print(element + " ");
      System.out.println();

      selectionSort(array);
      System.out.println("SelectionSorted array:");
      for(String element: array)
            System.out.print(element + " ");
      System.out.println();


}
static void selectionSort(Comparable[] array)
 {
      int smallindex;
      for(int i = 0; i < array.length; i++)
      {
           smallindex = i; // set first element as smallest
           for(int j = i + 1; j < array.length; j++) // find smallest
                if(array[j].compareTo(array[smallindex]) < 0)
                     smallindex = j;
           if(smallindex != i)
                swap(array, smallindex, i);
      }
 }
static void swap(Object[] array, int index1, int index2)
 {
      Object temp = array[index1];
      array[index1] = array[index2];
      array[index2] = temp;
 } 


}

import java.util.Scanner；
公共类选择排序
{ 
公共静态void main（字符串参数[]）
{
扫描仪输入=新扫描仪（系统输入）；
System.out.print（“输入要输入的名称数：”）；
int n=in.nextInt（）；
字符串数组[]=新字符串[n]；//用于存储名称的数组。
in.nextLine（）；//<---额外的下一行
for（int i=0；i

最好保留一个排序的数组，每次用户输入名称时，将其作为数组中的正确点插入。由于用户将是目前为止最大的瓶颈，他们甚至不会注意到这一点…@Boris the Spider没事，我刚刚明白了，请看下面我的回答谢谢。我刚刚明白了你发帖了。上面回答谢谢。我刚在你发帖前弄明白。上面回答：D:D:D:D:D

Scanner sc = new Scanner(System.in);
System.err.println("enter size of ur table");
int size = sc.nextInt();    
String array[] = new String[size];
for (int i = 0; i < size; i++) {
array[i] = sc.nextLine();
System.err.println("element " + i + "is :" + array[i]);
} 

import java.util.Scanner;

public class selectionsort
{ 
public static void main (String args[])
{
    Scanner in = new Scanner (System.in);
    System.out.print ("Enter the number of names you wish to enter: ");
    int n = in.nextInt();
    String array[] = new String [n]; //Array to store the names in.

in.nextLine(); // < --- an extra next Line

for (int i = 0; i < array.length; i++)
{
    System.out.println("Please enter the name: ");
    array[i]= in.nextLine();

}
   System.out.println("Unsorted array:");
      for(String element: array)
           System.out.print(element + " ");
      System.out.println();

      selectionSort(array);
      System.out.println("SelectionSorted array:");
      for(String element: array)
            System.out.print(element + " ");
      System.out.println();


}
static void selectionSort(Comparable[] array)
 {
      int smallindex;
      for(int i = 0; i < array.length; i++)
      {
           smallindex = i; // set first element as smallest
           for(int j = i + 1; j < array.length; j++) // find smallest
                if(array[j].compareTo(array[smallindex]) < 0)
                     smallindex = j;
           if(smallindex != i)
                swap(array, smallindex, i);
      }
 }
static void swap(Object[] array, int index1, int index2)
 {
      Object temp = array[index1];
      array[index1] = array[index2];
      array[index2] = temp;
 } 


}