Java Hibernate Envers:嵌入式扩展MappedSuperClass在启动时引发异常
我目前正试图在我的项目中使用Hibernate Envers,但我遇到了以下异常。我认为这是因为MedicalSummaryId不包含数据并扩展了映射的超类,但我不知道如何修复它 我使用的是Hibernate4.3.8.Final 例外情况:Java Hibernate Envers:嵌入式扩展MappedSuperClass在启动时引发异常,java,hibernate,hibernate-envers,Java,Hibernate,Hibernate Envers,我目前正试图在我的项目中使用Hibernate Envers,但我遇到了以下异常。我认为这是因为MedicalSummaryId不包含数据并扩展了映射的超类,但我不知道如何修复它 我使用的是Hibernate4.3.8.Final 例外情况: Caused by: org.hibernate.MappingException: Type not supported: org.hibernate.type.ComponentType at org.hibernate.envers.conf
Caused by: org.hibernate.MappingException: Type not supported: org.hibernate.type.ComponentType
at org.hibernate.envers.configuration.internal.metadata.IdMetadataGenerator.addIdProperties(IdMetadataGenerator.java:97)
at org.hibernate.envers.configuration.internal.metadata.IdMetadataGenerator.addId(IdMetadataGenerator.java:161)
at org.hibernate.envers.configuration.internal.metadata.AuditMetadataGenerator.generateFirstPass(AuditMetadataGenerator.java:598)
at org.hibernate.envers.configuration.internal.EntitiesConfigurator.configure(EntitiesConfigurator.java:107)
at org.hibernate.envers.configuration.spi.AuditConfiguration.<init>(AuditConfiguration.java:130)
at org.hibernate.envers.configuration.spi.AuditConfiguration.getFor(AuditConfiguration.java:180)
at org.hibernate.envers.event.spi.EnversIntegrator.integrate(EnversIntegrator.java:76)
at org.hibernate.internal.SessionFactoryImpl.<init>(SessionFactoryImpl.java:312)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1859)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl$4.perform(EntityManagerFactoryBuilderImpl.java:852)
... 87 more
MedicalHistoryId.java
@Embeddable
public class MedicalHistoryId implements Serializable {
@NotNull public MedicalSummaryId medicalSummaryId;
@NotNull public long id = 0;
}
MedicalSummaryId.java
@Embeddable
public class MedicalSummaryId extends AggregateRootId{
// no data
}
AggregateRoot.id
@Embeddable
@MappedSuperclass
public class AggregateRootId implements Serializable {
protected Integer id;
}
感谢您的帮助。问题似乎来自复合键,因此,我找到了一个不令人满意的解决方法,而不是使用复合键,如果我使用简单键,它会工作
@Embeddable
@MappedSuperclass
public class AggregateRootId implements Serializable {
protected Integer id;
}