切换菜单Java

我有一个开关菜单，我希望它循环整个菜单，包括方向，但它只是不断循环我选择的操作。我如何改变它？我从do/while切换到while循环

 int count = 0;

    String first;
    String last;
    String num;
    Contact person;

    System.out.println("What would you like to do?");
    System.out.println("Type c to create");
    System.out.println("Tpe e to edit");
    System.out.println("Tpe d to delete");
    System.out.println("Type q to quit");

    Scanner input = new Scanner(System.in);
    char choice = input.next().charAt(0);

    AddressBook addressBook = new AddressBook();
    while ('q' != choice) {
        switch (choice) {

            case 'c':
                System.out.println("Enter first name, last name and phone number");

                addressBook.addContact();

                count++;

                System.out.println("Total number of contact: " + count);

                break;

            case 'e':
                System.out.println("Enter name to be edited");

                first = input.next();
                last = input.next();
                num = null;

                person = new Contact(first, last, num);
                addressBook.edit(person);

                break;
            case 'd':
                System.out.println("Enter name to be deleted");

                first = input.next();
                last = input.next();
                num = null;

                person = new Contact(first, last, num);

                addressBook.removeContact(person);
                break;
            default:
                System.out.println("Operation does not exist");
        }

    }
}

---

}

将

字符选择

初始化为默认字符：

charchoice='a'

然后移动所有这些：

System.out.println("What would you like to do?");
System.out.println("Type c to create");
System.out.println("Tpe e to edit");
System.out.println("Tpe d to delete");
System.out.println("Type q to quit");

choice = input.next().charAt(0);

在while循环中：

while ('q' != choice) {
    //show menu options
    //allow user to select a menu option

    //use switch to operate based on user decision

    //once the operation is complete, as long as the user didn't select q, 
    //the menu options show once more and allow another selection
}

无需使用
选项

1.将
while（'q'！=choice）
更改为
while（true）

2.移动到代码下方，同时

     System.out.println("What would you like to do?");
     System.out.println("Type c to create");
     System.out.println("Tpe e to edit");
     System.out.println("Tpe d to delete");
     System.out.println("Type q to quit");

三,。再加一个箱子

 case 'q':

   break;

但是（q！=choice）会出现一个错误，因为choice稍后会在code@Sidney，你完全正确。检查我的编辑！一个简单的解决方法是提前声明
choice
，将其初始化为默认值，然后允许其被覆盖。是的，这是一个很好的方法。绝对干净。我不确定OP在他们的教案中的位置，所以我采用了最直接的建议：）额外变量意味着额外内存：）