Java &引用；“无法解析输入”；当添加一个try..catch时

我最初试图让我的throw语句在没有try-catch和

userInput=input.nextInt（）的情况下工作行运行良好。但是当我尝试添加try..catch时，它不喜欢我的输入，说它无法解析。我不认为我的尝试是正确的，但我正计划在我的输入得到认可后解决这个问题，但我也希望你能对你看到的反馈有所帮助

谢谢

import java.util.Scanner;

    public class Program6 
    {
        public static void main(String[] args) 
        {
            final int NUMBER_HIGH_LIMIT = 100;
            final int NUMBER_LOW_LIMIT = 10;
            int userInput;

            try
            {
                System.out.print("Enter a number between 10 and 100: ");
                userInput = input.nextInt();//Says input cannot be resolved

                Verify v = new Verify(NUMBER_HIGH_LIMIT, NUMBER_LOW_LIMIT);
            }
            catch(NumberHighException exception)
            {
                userInput = 0;
            }
            catch(NumberLowException exception) 
            {
                userInput = 0;  
            }
        }
    }

您需要创建一个名为
input
的扫描仪：

public class Program6 {

  public static void main(String[] args) {
    final int NUMBER_HIGH_LIMIT = 100;
    final int NUMBER_LOW_LIMIT = 10;
    int userInput;

    try {
      Scanner input = new Scanner(System.in);
      System.out.print("Enter a number between 10 and 100: ");
      userInput = input.nextInt();//Says input cannot be resolved

      Verify v = new Verify(NUMBER_HIGH_LIMIT, NUMBER_LOW_LIMIT);

    } catch (NumberHighException exception) {
      userInput = 0;
    } catch (NumberLowException exception) {
      userInput = 0;
    }
  }
}

您需要创建一个名为
input
的扫描仪：

public class Program6 {

  public static void main(String[] args) {
    final int NUMBER_HIGH_LIMIT = 100;
    final int NUMBER_LOW_LIMIT = 10;
    int userInput;

    try {
      Scanner input = new Scanner(System.in);
      System.out.print("Enter a number between 10 and 100: ");
      userInput = input.nextInt();//Says input cannot be resolved

      Verify v = new Verify(NUMBER_HIGH_LIMIT, NUMBER_LOW_LIMIT);

    } catch (NumberHighException exception) {
      userInput = 0;
    } catch (NumberLowException exception) {
      userInput = 0;
    }
  }
}

在Java中使用变量之前，需要先声明变量。可能是他在添加try/catch时意外删除了带有声明的行。在Java中使用变量之前，需要声明变量。可能是他在添加try/catch时意外删除了带有声明的行。