Java 将两个表相互比较并打印出差异
我的MySQL中有两个列完全相同的表,我们可以称它们为id、name、path、date。现在我想对这两个表进行比较,以了解表1和表2的区别,以及表2和表1的区别。我只想在我的Java程序中打印它,现在一个简单的System.out.print的差异将是完美的Java 将两个表相互比较并打印出差异,java,mysql,sql,database,diff,Java,Mysql,Sql,Database,Diff,我的MySQL中有两个列完全相同的表,我们可以称它们为id、name、path、date。现在我想对这两个表进行比较,以了解表1和表2的区别,以及表2和表1的区别。我只想在我的Java程序中打印它,现在一个简单的System.out.print的差异将是完美的 我只想检查两个表中name列中条目的差异。非常感谢您的帮助 这将连接id上的两个表,并显示名称不同的行: select a.name, b.name from table1 a join table2 b on a.id = b.id
我只想检查两个表中name列中条目的差异。非常感谢您的帮助 这将连接id上的两个表,并显示名称不同的行:
select a.name, b.name
from table1 a
join table2 b on a.id = b.id
where a.name <> b.name
这将连接id上的两个表,并向您显示名称不同的行:
select a.name, b.name
from table1 a
join table2 b on a.id = b.id
where a.name <> b.name
我确信您可以区分两个数据库,并看到它们之间的差异,比如testdb和proddb 这是文件
我确信您可以区分两个数据库,并看到它们之间的差异,比如testdb和proddb 这是文件
如果您只想查看表1中存在但不在表2中的名称列表,请尝试以下操作:
SELECT a.name
FROM table1 a
LEFT JOIN table2 b ON a.name = b.name
WHERE table2.name IS NULL
在该查询中交换table1和table2,以获取table2中不匹配的名称。如果您只想查看table1中存在但不在table2中的名称列表,请尝试以下操作:
SELECT a.name
FROM table1 a
LEFT JOIN table2 b ON a.name = b.name
WHERE table2.name IS NULL
交换该查询中的表1和表2,以获得表2中不匹配的名称。正确,应接受
下面是Java JDBC代码示例,显示了他的SQL代码的实际操作。我没有像问题中那样使用MySQL。相反,本例使用,创建一个临时内存中数据库
try {
Class.forName ( "org.h2.Driver" );
} catch ( final ClassNotFoundException e ) {
e.printStackTrace ( );
}
try ( Connection conn = DriverManager.getConnection ( "jdbc:h2:mem:trash_me_db" ) ;
Statement stmt = conn.createStatement ( ) ) {
String sql = null;
// Table 1
sql = "CREATE TABLE t1_ (\n" +
" id_ INT IDENTITY ,\n" +
" name_ VARCHAR \n" +
");";
stmt.executeUpdate ( sql );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Jesse');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Wendy');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Lisa');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Susan');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Jimmy');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Wine');" );
// Dump
System.out.println ( "\nDump table t1_" );
try ( ResultSet rs = stmt.executeQuery ( "SELECT * FROM t1_ ;" ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
// Table 2
sql = "CREATE TABLE t2_ (\n" +
" id_ INT IDENTITY ,\n" +
" name_ VARCHAR \n" +
");";
stmt.executeUpdate ( sql );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Jesse');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Wendy');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Lisa');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Susan');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Jimmy');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Beer');" );
// Dump
System.out.println ( "\nDump table t2_" );
try ( ResultSet rs = stmt.executeQuery ( "SELECT * FROM t2_ ;" ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
// Difference, left.
System.out.println ( "\nShow names that exist in t1_ but not in t2_." );
sql = "SELECT *\n" +
"FROM t1_ \n" +
"LEFT JOIN t2_ ON t1_.name_ = t2_.name_\n" +
"WHERE t2_.name_ IS NULL";
try ( ResultSet rs = stmt.executeQuery ( sql ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
// Difference, right.
System.out.println ( "\nShow names that exist in t2_ but not in t1_." );
sql = "SELECT *\n" +
"FROM t2_ \n" +
"LEFT JOIN t1_ ON t2_.name_ = t1_.name_\n" +
"WHERE t1_.name_ IS NULL";
try ( ResultSet rs = stmt.executeQuery ( sql ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
} catch ( final SQLException e ) {
e.printStackTrace ( );
}
跑步的时候
转储表t1_
id:1 |姓名:杰西
id:2 |姓名:Wendy
id:3 |姓名:丽莎
id:4 |姓名:苏珊
id:5 |姓名:吉米
id:6 |名称:葡萄酒
转储表t2_
id:1 |姓名:杰西
id:2 |姓名:Wendy
id:3 |姓名:丽莎
id:4 |姓名:苏珊
id:5 |姓名:吉米
id:6 |姓名:啤酒
显示存在于t1_u1;但不存在于t2_1;中的名称。
id:6 |名称:葡萄酒
显示存在于t2_u2;中但不存在于t1_2;中的名称。
id:6 |姓名:啤酒
这是正确的,应该被接受
下面是Java JDBC代码示例,显示了他的SQL代码的实际操作。我没有像问题中那样使用MySQL。相反,本例使用,创建一个临时内存中数据库
try {
Class.forName ( "org.h2.Driver" );
} catch ( final ClassNotFoundException e ) {
e.printStackTrace ( );
}
try ( Connection conn = DriverManager.getConnection ( "jdbc:h2:mem:trash_me_db" ) ;
Statement stmt = conn.createStatement ( ) ) {
String sql = null;
// Table 1
sql = "CREATE TABLE t1_ (\n" +
" id_ INT IDENTITY ,\n" +
" name_ VARCHAR \n" +
");";
stmt.executeUpdate ( sql );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Jesse');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Wendy');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Lisa');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Susan');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Jimmy');" );
stmt.execute ( "INSERT INTO t1_ ( name_ ) VALUES ('Wine');" );
// Dump
System.out.println ( "\nDump table t1_" );
try ( ResultSet rs = stmt.executeQuery ( "SELECT * FROM t1_ ;" ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
// Table 2
sql = "CREATE TABLE t2_ (\n" +
" id_ INT IDENTITY ,\n" +
" name_ VARCHAR \n" +
");";
stmt.executeUpdate ( sql );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Jesse');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Wendy');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Lisa');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Susan');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Jimmy');" );
stmt.execute ( "INSERT INTO t2_ ( name_ ) VALUES ('Beer');" );
// Dump
System.out.println ( "\nDump table t2_" );
try ( ResultSet rs = stmt.executeQuery ( "SELECT * FROM t2_ ;" ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
// Difference, left.
System.out.println ( "\nShow names that exist in t1_ but not in t2_." );
sql = "SELECT *\n" +
"FROM t1_ \n" +
"LEFT JOIN t2_ ON t1_.name_ = t2_.name_\n" +
"WHERE t2_.name_ IS NULL";
try ( ResultSet rs = stmt.executeQuery ( sql ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
// Difference, right.
System.out.println ( "\nShow names that exist in t2_ but not in t1_." );
sql = "SELECT *\n" +
"FROM t2_ \n" +
"LEFT JOIN t1_ ON t2_.name_ = t1_.name_\n" +
"WHERE t1_.name_ IS NULL";
try ( ResultSet rs = stmt.executeQuery ( sql ) ) {
while ( rs.next ( ) ) {
final int id = rs.getInt ( "id_" ); //Retrieve by column name
final String name = rs.getString ( "name_" );
System.out.println ( "id: " + id + " | name: " + name );
}
}
} catch ( final SQLException e ) {
e.printStackTrace ( );
}
跑步的时候
转储表t1_
id:1 |姓名:杰西
id:2 |姓名:Wendy
id:3 |姓名:丽莎
id:4 |姓名:苏珊
id:5 |姓名:吉米
id:6 |名称:葡萄酒
转储表t2_
id:1 |姓名:杰西
id:2 |姓名:Wendy
id:3 |姓名:丽莎
id:4 |姓名:苏珊
id:5 |姓名:吉米
id:6 |姓名:啤酒
显示存在于t1_u1;但不存在于t2_1;中的名称。
id:6 |名称:葡萄酒
显示存在于t2_u2;中但不存在于t1_2;中的名称。
id:6 |姓名:啤酒
您是否只想查看表1中存在但表2中不存在的名称列表,反之亦然?确切地说,如果可能,我如何用Java查询和打印结果。我的Java程序中已经有一个工作的MySQL连接,所以我只想知道如何设置查询。您是否只想看到表1中存在但表2中不存在的名称列表,反之亦然?完全正确,如果可能,我如何用Java查询和打印结果。我的Java程序中已经有一个可以工作的MySQL连接,所以我只想知道如何设置查询。