Java 为什么打印声明“不正确”=&燃气轮机&引用；在您输入扫描仪的输入后，请输入

我正在尝试创建一个基于文本的冒险游戏，我正在尝试添加一个功能，每当游戏需要您的输入时，在您输入的位置旁边会显示一个小记号“=>”。对于这里的代码，每当我在命令提示符（Windows7）中运行它时，就会显示输入，而小勾号不会显示。输入输入后，勾号会在输入后显示。我希望能够将记号和输入都放在一行上，就像这样，“=>[使用输入]”。请帮忙

import java.io.IOException;
import java.util.Scanner;

import org.fusesource.jansi.AnsiConsole;



public class Game {

    public static String BLACK = "\u001B[0;30m";
    public static String RED = "\u001B[0;31m";
    public static String GREEN = "\u001B[0;32m";
    public static String YELLOW = "\u001B[0;33m";
    public static String BLUE = "\u001B[0;34m";
    public static String MAGENTA = "\u001B[0;35m";
    public static String CYAN = "\u001B[0;36m";
    public static String WHITE = "\u001B[0;37m";

    public final static String ESC = "\033[";

    public static String name;
    public static String gender;

    public static void main(String[] args) {
        AnsiConsole.systemInstall();

        check();
    }

    public static void start() {

        Scanner a = new Scanner(System.in);

        System.out.println("###############################################################################");
        System.out.println("#                                                                             #");
        System.out.println("#                        " + YELLOW + "^.^" + WHITE + " " + "Adventure Time Is Yes " + YELLOW + "^.^" + WHITE + "                        #");
        System.out.println("#                                                                             #");
        System.out.println("###############################################################################");

        //Get Name
        System.out.print("\n");
        System.out.println("Hello young lad! What is thy " + RED + "name " + WHITE + "you were given at birth?");
        System.out.print("=> ");
        //Global Variable for Name
        name = a.next();

        System.out.print("\n");

        System.out.println("Hello " + RED + name + WHITE + "! Are you a Male or Female?");
        System.out.print("=> ");
        gender = a.next();


    }

    public static void check() {

        Scanner a = new Scanner(System.in);

        System.out.println("Can you see these colors?: ");
        System.out.println(RED + "Red " + GREEN + "Green " + YELLOW + "Yellow " + BLUE + "Blue " + MAGENTA + "Magenta " + CYAN + "Cyan " + WHITE + "White");
        System.out.println("Y/N");
        System.out.print("=> ");

        String as = a.nextLine();
        as.toUpperCase();

        if (as == "Y") {
            System.out.println(ESC + "2J");
            start();
        } else {
            System.out.println(ESC + "2J");
            start();
            //Future idea is to make it so there is an exact copy of the game but without color :D
        }

    }
}

/*try {
System.in.read();
} catch (IOException e) {
e.printStackTrace();
}

System.exit(0);*/

//System.out.println(ESC + "2J"); Clear Lines On Screen

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刷新输出流，以确保在请求输入之前写入的所有内容都已通过缓冲区。

您可以使用outputstreamName.Flush（）刷新输出流。有关更多帮助，请参阅或

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刷新输出流将帮助您找出代码失败的地方。

我该如何准确地刷新输出流？我不是要打印到文件，而是要打印到控制台。所以使用outputstreamName.flush（）将不可用，对吗？不对。可以对任何缓冲输出流调用flush操作，并且应该在您希望确保缓冲区已完全处理到输出时调用flush操作。你的问题是一个很好的例子，说明了为什么你可能想这么做。