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Hibernate Java-意外的AST节点_Java_Hibernate - Fatal编程技术网

Hibernate Java-意外的AST节点

Hibernate Java-意外的AST节点,java,hibernate,Java,Hibernate,我正在使用Hibernate 5开发一个Spring引导应用程序。我对存储库有一个自定义的@Query public interface TeamResourceRepository extends CrudRepository<ResourceItem, Integer> { @Query("Select i from ResourceItem as i JOIN i.resourceCategories as c WHERE c.ID = ?1") List&l

我正在使用Hibernate 5开发一个Spring引导应用程序。我对存储库有一个自定义的
@Query

public interface TeamResourceRepository extends CrudRepository<ResourceItem, Integer> {

    @Query("Select i from ResourceItem as i JOIN i.resourceCategories as c WHERE c.ID = ?1")
    List<ResourceItem> findByCategory(int id);

    @Query("Select i from ResourceItem as i JOIN i.tags as t WHERE (t.description = ?1 "
            + " OR i.name LIKE  ?1%) AND i.isActive ORDER BY i.name")
    List<ResourceItem> findByTag(String search);
}

问题可能与param子句类似。 尝试用通配符连接参数:

OR i.name LIKE  CONCAT(?1,'%')

在异常中写入整个查询:

Select i from com.midamcorp.resource_server.model.ResourceItem as i JOIN i.tags as t WHERE (t.description = ?1  OR i.name LIKE  ?1) AND i.isActive ORDER BY i.name 

查看第138列有问题的错误,您应该查看
i.isActive
。我想
I.isActive=true
会解决这个问题。

你的类
ResourceItem
看起来怎么样?请添加code@Jens,已添加。谢谢。谢谢,但不幸的是,它仍然给出相同的错误。这确实是正确的。就我而言,是i.isActive=1。我感谢你的帮助,这似乎是一个相当奇怪的错误。
Select i from com.midamcorp.resource_server.model.ResourceItem as i JOIN i.tags as t WHERE (t.description = ?1  OR i.name LIKE  ?1) AND i.isActive ORDER BY i.name