Java 类构造函数中的stackoverflow错误

请原谅这可能是一个非常基本的问题，但我正在编写一个程序来存储员工信息，它工作正常，直到它试图在我的员工类中设置信息。它给出了一个stackoverflow错误，我不知道为什么。谢谢你的帮助

主要类别：

import java.util.Scanner;

public class Main
{
    public static void main(String[] args)
    {
        Scanner Input = new Scanner(System.in);

        System.out.println("Enter the number of employees to enter.");
        int employeeCount = Input.nextInt();
        Input.nextLine();

        Employee employee[] = new Employee[employeeCount];
        String namesTemp;
        String streetTemp;
        String cityTemp;
        String stateTemp;
        String zipCodeTemp;
        String address;
        String dateOfHireTemp;

        for(int x = 0; x < employeeCount; x++)
        {
            System.out.println("Please enter the name of Employee " + (x + 1));
            namesTemp = Input.nextLine();
            System.out.println("Please enter the street for Employee " + (x + 1));
            streetTemp = Input.nextLine();
            System.out.println("Please enter the city of Employee " + (x + 1));
            cityTemp = Input.nextLine();
            System.out.println("Please enter the state of Employee " + (x + 1));
            stateTemp = Input.nextLine();
            System.out.println("Please enter the zip code of Employee " + (x + 1));
            zipCodeTemp = Input.nextLine();
            address = streetTemp + ", " + cityTemp + ", " + stateTemp + ", " + zipCodeTemp;
            System.out.println("Please enter the date of hire for Employee " + (x + 1));
            dateOfHireTemp = Input.nextLine();
            System.out.println("The employee ID for employee " + (x + 1) + " is " + (x + 1));
            employee[x] = new Employee(x, namesTemp, address, dateOfHireTemp);
        }
    }
}

名称类别：

public class Name 
{
    public Name name;

    public Name(String name)
    {
        Name employeeName = new Name(name);
        this.name = employeeName;
    }
}

---

StackOverflowException最常见的原因是在不知情的情况下出现递归，这是在这里发生的吗

public Name(String name)
{
    Name employeeName = new Name(name);  // **** YIKES!! ***
    this.name = employeeName;
}

宾果：递归

此构造函数将创建一个新名称对象，其构造函数将创建一个新名称对象，其构造函数将。。。因此，您将不断创建新的名称对象，直到堆栈内存耗尽为止。解决方案：不要这样做。为字符串指定名称：

class Name {
    String name; // ***** String field!

    public Name(String name)
    {
        this.name = name;  // this.name is a String field
    }

---

通常，类用于将数据与功能组合在一起。似乎Name类只是字符串的包装器，没有添加任何功能。在Java职业生涯的这一点上，最好声明字符串名称；在Employee类中，同时删除Name类。请注意，这将删除代码中描述的气垫船装满鳗鱼的错误。

堆栈溢出发生在哪一行？

class Name {
    String name; // ***** String field!

    public Name(String name)
    {
        this.name = name;  // this.name is a String field
    }