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Java org.hibernate.exception.genericjdbception:无法在hibernate中执行语句_Java_Hibernate_Annotations - Fatal编程技术网

Java org.hibernate.exception.genericjdbception:无法在hibernate中执行语句

Java org.hibernate.exception.genericjdbception:无法在hibernate中执行语句,java,hibernate,annotations,Java,Hibernate,Annotations,我试图使用可嵌入注释在一个对象中存储不同的值,并将其持久化到一个表中 我有两门课: 用户详细信息: package org.hibernet.src; @Entity @Table (name="UserDetails") public class userDetails { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int userId; @Temporal(TemporalType.DATE) private

我试图使用可嵌入注释在一个对象中存储不同的值,并将其持久化到一个表中

我有两门课: 用户详细信息:

package org.hibernet.src;
@Entity
@Table (name="UserDetails")
 public class userDetails {
 @Id 
@GeneratedValue(strategy = GenerationType.AUTO)
private int userId;
@Temporal(TemporalType.DATE)
private Date dob;
public Date getDob() {
    return dob;
}
public void setDob(Date dob) {
    this.dob = dob;
}
private String userName;
@Embedded
private Address address;

public Address getAddress() {
    return address;
}
public void setAddress(Address address) {
    this.address = address;
}
public int getUserId() {
    return userId;
}
public void setUserId(int userId) {
    this.userId = userId;
}
public String getUserName() {
    return userName;
}
public void setUserName(String userName) {
    this.userName = userName;
}

}
  • 可嵌入类的地址类:

     @Embeddable
    
     public class Address {
    
    @Column(nullable=true)
    private String street;
    
    @Column(nullable=true)
    private String city;
    
     @Column(nullable=true)
     private String state;
    
    
    public String getStreet() {
    return street;
    }
    public void setStreet(String street) {
    this.street = street;
    }
    public String getCity() {
        return city;
    }
     public void setCity(String city) {
        this.city = city;
     }
    public String getState() {
    return state;
    }
    public void setState(String state) {
        this.state = state;
    }
    
    } 这是我的主要课程:

    public static void main(String[] args) {
    
    userDetails user = new userDetails();
    Address add = new Address();
    
    user.setUserName("Dipesh");
    user.setDob(new Time(0));
    add.setCity("vadodara");
    add.setState("gujarat");
    add.setStreet("raopura");
    
    
    
    SessionFactory sessionfactory = new     
     Configuration().configure().buildSessionFactory();
    Session session = sessionfactory.openSession();
    session.beginTransaction();
    session.save(user);
    session.save(add);
    /*user = (userDetails)session.get(userDetails.class, 6);*/
    
    session.getTransaction().commit();
    session.close();
    
    }

  • 我试图存储数据,但它显示:

       ERROR: Field 'pincode' doesn't have a default value
       Exception in thread "main" org.hibernate.exception.GenericJDBCException:    
        could not execute statement
    
          at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:54)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:126)
    at org.hibernate.engine.jdbc.spi.SqlExceptionHelper.convert(SqlExceptionHelper.java:112)
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:211)
    at org.hibernate.id.IdentityGenerator$GetGeneratedKeysDelegate.executeAndExtract(IdentityGenerator.java:96)
    at org.hibernate.id.insert.AbstractReturningDelegate.performInsert(AbstractReturningDelegate.java:58)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3032)
    at org.hibernate.persister.entity.AbstractEntityPersister.insert(AbstractEntityPersister.java:3558)
    at org.hibernate.action.internal.EntityIdentityInsertAction.execute(EntityIdentityInsertAction.java:98)
    at org.hibernate.engine.spi.ActionQueue.execute(ActionQueue.java:490)
    at org.hibernate.engine.spi.ActionQueue.addResolvedEntityInsertAction(ActionQueue.java:195)
    at org.hibernate.engine.spi.ActionQueue.addInsertAction(ActionQueue.java:179)
    at org.hibernate.engine.spi.ActionQueue.addAction(ActionQueue.java:214)
    at org.hibernate.event.internal.AbstractSaveEventListener.addInsertAction(AbstractSaveEventListener.java:324)
    at org.hibernate.event.internal.AbstractSaveEventListener.performSaveOrReplicate(AbstractSaveEventListener.java:288)
    at org.hibernate.event.internal.AbstractSaveEventListener.performSave(AbstractSaveEventListener.java:194)
    at org.hibernate.event.internal.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:125)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:209)
    at org.hibernate.event.internal.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:55)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:194)
    at org.hibernate.event.internal.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:49)
    at org.hibernate.event.internal.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:90)
    at org.hibernate.internal.SessionImpl.fireSave(SessionImpl.java:715)
    at org.hibernate.internal.SessionImpl.save(SessionImpl.java:707)
    at org.hibernate.internal.SessionImpl.save(SessionImpl.java:702)
    at org.hibernate.test.userTest.main(userTest.java:36)
    Caused by: java.sql.SQLException: Field 'pincode' doesn't have a default    
    value
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1056)
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:957)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3376)
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3308)
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1837)
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:1961)
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2543)
    at     
        com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:1737)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2022)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1940)
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:1925)
    at org.hibernate.engine.jdbc.internal.ResultSetReturnImpl.executeUpdate(ResultSetReturnImpl.java:208)
    ... 22 more
    
    我的地址中有pincode,但它显示了一个错误,所以我删除了它,但它仍然显示了那个错误


    请帮我解决这个问题。

    数据库中的表有一个字段pincode,您尚未为其定义默认值,因此不能为空。但是,您的实体没有该字段的映射,并且您没有为此字段发送值。因此,java.sql.SQLException:字段“pincode”没有默认值

    1)调整实体,使其包含字段“pincode”

    2) 或者更改基础表,使pincode字段具有默认值:

     ALTER TABLE user_details MODIFY pincode NUMBER(10) NULL DEFAULT NULL;
    

    选择数字(10)作为示例。将其替换为pincode变量类型。

    我遇到了与org.hibernate.exception.genericjdbception相同的错误:无法执行我忘记初始化会话工厂的语句

    初始化(如下)会话工厂解决了我的问题。

    @Autowired
    private SessionFactory sessionFactory;
    
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.sessionFactory = sessionFactory;
    }
    

    我的数据库中没有名为Address的表。我看到您使用的是@embeddeble,在第一次阅读时就忽略了这一点P但是您的表确实有一个字段pincode。编辑了我的答案。我的userdetails表中没有任何内容。请告诉我pincode字段的来源?异常从数据库传播回来。使用Embedded,可以将该可嵌入实体嵌入到实体类中,这使得它在实体类的同一个表中为嵌入的实体添加列,并且没有这样一个表映射到该可嵌入实体的持久实体。我的数据库中没有地址表,因为我想将其嵌入UserDetails。我的user_details表为空!!我在不同的数据库中搜索。我在用户详细信息中有一列pincode。我已经删除了它,但是现在它显示了
    org.hibernate.MappingException:Unknown entity:org.hibernet.src.Address
    error您配置了hibernate配置文件了吗?它必须定义实体类:Let us。
    @Autowired
    private SessionFactory sessionFactory;
    
    public void setSessionFactory(SessionFactory sessionFactory) {
        this.sessionFactory = sessionFactory;
    }