Java rally中特定用户故事的缺陷

如何使用java中的rally rest api检索/获取特定用户故事表单rally的缺陷

下面的代码我已经试过了

QueryRequest projectRequest = new QueryRequest("Defect");
projectRequest.setProject(
    "https://rally1.rallydev.com/slm/webservice/v2.0/project/"+prjid);
projectRequest.setQueryFilter(new QueryFilter("Requirement", "=", UserR));
//projectRequest.setScopedDown(true);
QueryResponse projectQueryResponse = this.restApi.query(projectRequest);

假定

String projectRef = "/project/12345";
String storyRef = "/hierarchicalrequirement/67890";

下面是一个返回用户故事缺陷的示例：

try {
                restApi = new RallyRestApi(
                        new URI(host),
                        username,
                        password);
                restApi.setApplicationName(applicationName); 

                QueryRequest defectRequest = new QueryRequest("Defect");
                defectRequest.setProject(projectRef);
                defectRequest.setFetch(new Fetch(new String[] {"Name", "FormattedID","State", "Priority", "Severity", "Requirement"}));
                defectRequest.setLimit(1000);
                defectRequest.setScopedDown(false);
                defectRequest.setScopedUp(false);
                defectRequest.setQueryFilter(new QueryFilter("Requirement", "=", storyRef));

                QueryResponse defectQueryResponse = restApi.query(defectRequest);

                for (int i=0; i<defectQueryResponse.getResults().size();i++){
                    JsonObject defectJsonObject = defectQueryResponse.getResults().get(i).getAsJsonObject();
                    System.out.println("Name: " + defectJsonObject.get("Name") + " State: " + defectJsonObject.get("State") + " Priority: " + defectJsonObject.get("Priority") + " FormattedID: " + defectJsonObject.get("Requirement"));
                }


            } finally {
                if (restApi != null) {
                    restApi.close();
                }
            }

试试看{
restApi=新的RallyRestApi(
新URI（主机），
用户名，
密码）；
restApi.setApplicationName（applicationName）；
QueryRequest defectRequest=新的QueryRequest（“缺陷”）；
defectRequest.setProject（projectRef）；
setFetch（新的Fetch（新字符串[]{“Name”、“FormattedID”、“State”、“Priority”、“Severity”、“Requirement”}））；
缺陷请求。设置限制（1000）；
defectRequest.setScopedDown（错误）；
defectRequest.setScopedUp（错误）；
setQueryFilter（新的QueryFilter（“Requirement”，“Requirement”，“=”，storyRef））；
QueryResponse缺陷QueryResponse=restApi.query（缺陷请求）；
对于（int i=0；iIt将检索特定用户故事的所有缺陷？请澄清我。