Java 使用Spring Security添加自定义属性do会话

我需要为Spring Security创建的会话添加一个自定义属性

我尝试使用UsernamePasswordAuthenticationFilter来实现这一点。我在spring配置中以以下方式配置了此自定义筛选器：

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:mvc="http://www.springframework.org/schema/mvc"
    xmlns:tx="http://www.springframework.org/schema/tx"
    xmlns:security="http://www.springframework.org/schema/security"
    xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
        http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd
        http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.0.xsd
        http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.0.xsd
        http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-4.0.xsd">

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/view/"></property>
        <property name="suffix" value=".jsp"></property>
    </bean>

    <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
        <property name="basename" value="/WEB-INF/SpringMessages" />
    </bean>

    <bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver" >
        <property name="maxUploadSize" value="100000000"></property>
    </bean>

    <bean id="myDataSource" class="com.mchange.v2.c3p0.ComboPooledDataSource" destroy-method="close">
        <property name="driverClass" value="com.mysql.jdbc.Driver" />
        <property name="jdbcUrl" value="jdbc:mysql://127.0.0.1:3306/my_database" />
        <property name="user" value="root" />
        <property name="password" value="1234" />
        <property name="minPoolSize" value="5" />
        <property name="maxPoolSize" value="20" />
        <property name="maxStatements" value="50" />
        <property name="idleConnectionTestPeriod" value="3000" />
        <property name="loginTimeout" value="300" />
    </bean>

    <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="myDataSource" />
        <property name="jpaVendorAdapter">
            <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
        </property>
        <property name="jpaProperties">
            <props>
                <prop key="hibernate.show_sql">false</prop>
            </props>
        </property>
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" autowire-candidate="default">
        <property name="entityManagerFactory" ref="entityManagerFactory" />
    </bean>

    <bean id="customAuthenticationDetails" class="com.mycompany.mysystem.login.configuration.CustomUsernamePasswordAuthenticationFilter">
        <property name="authenticationManager" ref="authenticationManager"/>
    </bean>

    <context:component-scan base-package="com.mycompany.mysystem.*"/>

    <mvc:resources mapping="/resources/**" location="/WEB-INF/resources/" />

    <mvc:annotation-driven />

    <tx:annotation-driven />

    <security:http auto-config="false" disable-url-rewriting="false">
        <security:form-login login-page="/login" username-parameter="j_username" password-parameter="j_password" login-processing-url="/j_spring_security_check" default-target-url="/index" authentication-failure-url="/login?status=error" />
        <security:logout logout-success-url="/login?status=logout" logout-url="/j_spring_security_logout" />
        <security:access-denied-handler error-page="/acesso" />
        <security:headers disabled="true"/>
        <security:custom-filter after="FORM_LOGIN_FILTER" ref="customAuthenticationDetails" />
        <security:intercept-url pattern="/resources/**" access="permitAll" />
        <security:intercept-url pattern="/login" access="permitAll" />
    </security:http>

    <security:authentication-manager id="authenticationManager">
        <security:authentication-provider>
            <security:jdbc-user-service
                data-source-ref="myDataSource"
                users-by-username-query="my users"
                authorities-by-username-query="my authorities" />
        </security:authentication-provider>
    </security:authentication-manager>

    <security:global-method-security jsr250-annotations="enabled" pre-post-annotations="enabled" proxy-target-class="true" />

</beans>

我做错了什么？我认为这是一个概念错误，但我没有找到任何解决方案来向spring会话添加自定义属性

致以最良好的祝愿

编辑

My Web.xml：

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    id="WebApp_ID" version="3.0">

    <display-name>MySystem</display-name>

    <servlet>
        <servlet-name>spring</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>spring</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-servlet.xml</param-value>
    </context-param>

    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>
    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

</web-app>

我的系统
春天
org.springframework.web.servlet.DispatcherServlet
1.
春天
/
org.springframework.web.context.ContextLoaderListener
上下文配置位置
/WEB-INF/spring-servlet.xml
springSecurityFilterChain
org.springframework.web.filter.DelegatingFilterProxy
springSecurityFilterChain
/*

编辑2

---

我用另一种方法解决了这个问题，因此无法在这个主题上发布，但问题已经解决。

发布您的web.xml请说明您需要添加什么和为什么。@M.Deinum我需要在我的所有控制器中提供一个用户表（Functionario）的信息（因为：不要问为什么，架构就这样做），如果您理解的话。我想在任何时候都可以获得我需要的信息，但是在所有控制器中建立连接看起来比通过会话更糟糕。用户已经是会话的一部分，为什么不创建自己的用户对象并使用它而不是默认的Spring Security用户呢？这样，您只需向每个控制器方法（即

主体

或

身份验证

）添加一个参数即可获得访问权限。节省您手动将其存储在会话中，并与框架的其余部分很好地集成。但是如果你真的想创建一个

AuthenticationSuccessHandler

来为你做这件事。@M.Deinum我替换了默认的Spring安全用户，它工作正常！谢谢你的提示。

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    id="WebApp_ID" version="3.0">

    <display-name>MySystem</display-name>

    <servlet>
        <servlet-name>spring</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>spring</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring-servlet.xml</param-value>
    </context-param>

    <filter>
        <filter-name>springSecurityFilterChain</filter-name>
        <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>
    <filter-mapping>
        <filter-name>springSecurityFilterChain</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

</web-app>