Java 用菱形数字填充二维数组

我需要一些使用嵌套for循环填充二维数组的帮助。 所需的输出是

20.0 19.0 18.0 17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0 18.0 19.0 20.0
19.0 18.0 17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0 18.0 19.0
18.0 17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0 18.0
17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0
16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0
15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0
14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0
13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0
12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0
11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0
10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0
11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0
12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0
13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0
14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0
15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 5.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0
16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 6.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0
17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 7.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0
18.0 17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 8.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0 18.0
19.0 18.0 17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 9.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0 18.0 19.0
20.0 19.0 18.0 17.0 16.0 15.0 14.0 13.0 12.0 11.0 10.0 11.0 12.0 13.0 14.0 15.0 16.0 17.0 18.0 19.0 20.0

这是我填充数组的代码

int行；
int列；
int计数器=10；
int计数器1=10；
对于（行=0；行

我已经声明数组是20乘20，而

obj.getZ

只是简单地调用这个方法

public-double-getZ（双x，双y）{
双z=（Math.abs（x）+Math.abs（y））；
返回z；

---

数组是由x和y的绝对值构成的z值。

不是最佳解决方案，但它应该解决以下问题：

导入java.util.array；
课堂擦伤{
公共静态void main（字符串[]args）{
int[]arr=新int[21][21]；
int row=20；
int列=0；
对于（int i=0；i<21；i++）{
列=行；
对于（int j=0；j<21；j++）{
arr[i][j]=列；
如果（j<10）{
列=列-1；
}否则{
列=列+1；
}
}
如果（i<10）{
行=行-1；
}否则{
行=行+1；
}
}
对于（int[]arrRow:arr）{
System.out.println（Arrays.toString（arrRow））；
}
}
}

结果是：

[20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
[19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
[18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
[17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17]
[16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]
[15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
[14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
[13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
[12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
[11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
[12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
[13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
[14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
[15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
[16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]
[17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17]
[18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
[19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
[20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

---

不是最好的解决方案，但它应该解决问题：

导入java.util.array；
课堂擦伤{
公共静态void main（字符串[]args）{
int[]arr=新int[21][21]；
int row=20；
int列=0；
对于（int i=0；i<21；i++）{
列=行；
对于（int j=0；j<21；j++）{
arr[i][j]=列；
如果（j<10）{
列=列-1；
}否则{
列=列+1；
}
}
如果（i<10）{
行=行-1；
}否则{
行=行+1；
}
}
对于（int[]arrRow:arr）{
System.out.println（Arrays.toString（arrRow））；
}
}
}

结果是：

[20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]
[19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
[18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
[17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17]
[16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]
[15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
[14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
[13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
[12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
[11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
[10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
[12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12]
[13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13]
[14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]
[15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
[16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16]
[17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17]
[18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18]
[19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19]
[20, 19, 18, 17, 16, 15, 14, 13, 12, 11, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20]

---

您可以使用以下方法创建和填充此数组：

int m=10；
int n=10；
int[][]arr=IntStream.rangeClosed（-m，m）
.mapToObj（i->IntStream.rangeClosed（-n，n）
.map（j->Math.abs（i）+Math.abs（j））
.toArray（））
.toArray（int[]]：：新建）；

//输出
Arrays.stream（arr.map）（行->Arrays.stream（行）
.mapToObj（字符串：：valueOf）
.collect（收集器.连接（“”））
.forEach（System.out:：println）；

---

对于

double[][]

数组，其工作原理相同：

int m=10；
int n=10；
double[][]arr=IntStream.rangeClosed（-m，m）
.mapToObj（i->IntStream.rangeClosed（-n，n）
.mapToDouble（j->Math.abs（i）+Math.abs（j））
.toArray（））
.toArray（双[]]：：新）；

//格式化输出
Arrays.stream（arr.map）（行->Arrays.stream（行）
.mapToObj（i->String.format（“%4.1f”，i））
.collect（收集器.连接（“”））
.forEach（System.out:：println）；

---

---

另请参见：

您可以使用以下方法创建和填充此数组：

int m=10；
int n=10；
int[][]arr=IntStream.rangeClosed（-m，m）
.mapToObj（i->IntStream.rangeClosed（-n，n）
.map（j->Math.abs（i）+Math.abs（j））
.toArray（））
.toArray（int[]]：：新建）；

//输出
Arrays.stream（arr.map）（行->Arrays.stream（行）
.mapToObj（字符串：：valueOf）
.collect（收集器.连接（“”））
.forEach（System.out:：println）；

---

对于

double[][]

数组，其工作原理相同：

int m=10；
int n=10；
double[][]arr=IntStream.rangeClosed（-m，m）
.mapToObj（i->IntStream.rangeClosed（-n，n）
.mapToDouble（j->Math.abs（i）+Math.abs（j））
.toArray（））
.toArray（双[]]：：新）；

//格式化输出
Arrays.stream（arr.map）（行->Arrays.stream（行）
.mapToObj（i->String.format（“%4.1f”，i））
.collect（收集器.连接（“”））
.forEach（System.out:：println）；

---

---

另请参见：

谢谢我使用了您的想法并进行了一些编辑以适应我的代码，但效果非常好谢谢我使用了您的想法并进行了一些编辑以适应我的代码，但效果非常好

20,0 19,0 18,0 17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0 18,0 19,0 20,0
19,0 18,0 17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0 18,0 19,0
18,0 17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0 18,0
17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0
16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0
15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0
14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0
13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0
12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  2,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0
11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  2,0  1,0  2,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0
10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  2,0  1,0  0,0  1,0  2,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0
11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  2,0  1,0  2,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0
12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  2,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0
13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  3,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0
14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  4,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0
15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  5,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0
16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  6,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0
17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  7,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0
18,0 17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0  8,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0 18,0
19,0 18,0 17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0  9,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0 18,0 19,0
20,0 19,0 18,0 17,0 16,0 15,0 14,0 13,0 12,0 11,0 10,0 11,0 12,0 13,0 14,0 15,0 16,0 17,0 18,0 19,0 20,0