Java 如何在URL中传递多个参数？_Java_Android_Url_Servlets

Java 如何在URL中传递多个参数？

java android url servlets

Java 如何在URL中传递多个参数？,java,android,url,servlets,Java,Android,Url,Servlets,我试图弄清楚如何在URL中传递多个参数。我想将纬度和经度从我的android类传递到java servlet。我该怎么做 URL url; double lat=touchedPoint.getLatitudeE6() / 1E6; double lon=touchedPoint.getLongitudeE6() / 1E6; url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+lon); url = n

我试图弄清楚如何在URL中传递多个参数。我想将纬度和经度从我的android类传递到java servlet。我该怎么做

URL url;
double lat=touchedPoint.getLatitudeE6() / 1E6;
double lon=touchedPoint.getLongitudeE6() / 1E6;
url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+lon);

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

在这种情况下，输出（写入文件）为

28.53438677.472097

。这是可行的，但我想在两个单独的参数中传递纬度和经度，以便减少我在服务器端的工作量。如果不可能，我如何至少在

lat

和

lon

之间添加一个空格，以便使用

tokenizer

类获取纬度和经度。我试着跟着台词走，但没用

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

我的servlet代码如下所示：

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

req.setCharacterEncoding("UTF-8");
resp.setCharacterEncoding("UTF-8");
final String par1 =  req.getParameter("param1");
final String par2 = req.getParameter("param2");
FileWriter fstream = new FileWriter("C:\\Users\\Hitchhiker\\Desktop\\out2.txt");
BufferedWriter out = new BufferedWriter(fstream);
out.write(par1);
out.append(par2);
out.close();

我还想知道，这是将数据从android设备传递到服务器的最安全的方式。

我对Java知之甚少，但URL查询参数应该用“&”分隔，而不是“？”

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

使用“sub delim”作为关键字是一个很好的参考位置。是另一个很好的来源。

这

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&param2="+lon);

必须工作。出于任何奇怪的原因1，在第一个参数之前需要

？

，在下列参数之前需要

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

使用复合参数，如

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"_"+lon);

这也行，但肯定不好。您不能在那里使用空格，因为它在URL中是被禁止的，但您可以将其编码为

%20

或

（但这是更糟糕的样式）

    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

1声明

？

将路径和参数分开，并且

和将参数彼此分开，并不解释任何原因。一些RFC说“使用？那里和那里”，但我不明白他们为什么不选择相同的字符。
您可以将多个参数作为“？param1=value1¶m2=value2
”传递
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

但这并不安全。它容易受到跨站点脚本（XSS）攻击
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

您的参数可以简单地替换为脚本
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

看看这个，然后
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

您可以使用的API使其安全
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

即使在没有上述预防措施的情况下使用https
url进行安全保护，也不是一个好的做法
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

查看相关SE问题：
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996

应该是¶m2
而不是？param2
谢谢，工作起来很有魅力。：）你能回答我最后一个问题吗？这是最安全的方法吗？我正在开发的应用程序将部署在市场上，因此它必须是安全的。关于安全性，答案当然取决于您需要什么样的安全性。如果你想防止未经授权使用你的应用程序，你可能会失去锁定。对于安全通信，HTTPS
通常是一种方式。在客户端，您只需要添加一个“s”，在服务器端，您需要一个私钥和一个由CA签名的证书。或者您可以运行自己的证书，这需要更多的工作。然而。。。这是一个不同的问题，发布它。这不是一个奇怪的原因。？
不是查询字符串的一部分。它只是请求URI和请求查询字符串之间的分隔符。查询字符串参数对依次需要&
作为分隔符。查询字符串参数名称和值对依次需要=
作为分隔符。顺便说一下，查询字符串中的空格应编码为+
。%20
仅适用于请求URI部分。您可以使用urlcoder\encode（）
对查询字符串组件进行编码。我也看到了，但是一些东西？a=1？b=2
更容易编写和解析；使用&
而不是？
作为分隔符没有任何逻辑上的原因。AFAIK+
只是``的便捷快捷方式，URLDecoder
也接受%20
。LDAP以各种方式使用这种格式，但开始讨论大约在1992年做出的决定是徒劳的@关于编码要求，BalusC是正确的。您不能依赖某个特定API的基本特性。不是所有的东西都是Java，也不是所有的东西都是由URLDecover解码的。
我在StringEscapeUtils
中没有看到任何正确编码URL参数的东西，并且URLDecover已经存在。更新了相关SE问题的答案。
    url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+" "+lon);
output- Nothing is written to file
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"&?param2="+lon);
output- 28.534386 (Only Latitude)
        url = new URL("http://10.0.2.2:8080/HelloServlet/PDRS?param1="+lat+"?param2="+lon);
output- 28.532577?param2=77.502996