Java 查询生成器中的JPA2.0谓词条件列表
代码:Java 查询生成器中的JPA2.0谓词条件列表,java,hibernate,jpa,criteria-api,Java,Hibernate,Jpa,Criteria Api,代码: List conditionsList=new ArrayList(); 谓词onStart=criteriaBuilder.greaterThanOrEqualTo(criteriaRoot.get(“insertDateTime”),startTradeDate); 谓词onEnd=criteriaBuilder.lessThanOrEqualTo(criteriaRoot.get(“insertDateTime”),endTradeDate); 条件列表添加(onStart); 条
List conditionsList=new ArrayList();
谓词onStart=criteriaBuilder.greaterThanOrEqualTo(criteriaRoot.get(“insertDateTime”),startTradeDate);
谓词onEnd=criteriaBuilder.lessThanOrEqualTo(criteriaRoot.get(“insertDateTime”),endTradeDate);
条件列表添加(onStart);
条件列表添加(ONED);
CriteriaBuilder CriteriaBuilder=this.entityManager.getCriteriaBuilder();
CriteriaQuery CriteriaQuery=
createQuery(MyClass.class);
Root criteriaRoot=criteriaQuery.from(MyClass.class);
选择(criteriaRoot).where(条件列表);
上面的最后一行没有编译,因为它期望conditionsList
对象是一个布尔值列表,而不是谓词列表
请告诉我如何将上述谓词添加到hibernate
标准中?将列表
转换为数组谓词[]
,如下所示:
List<Predicate> conditionsList = new ArrayList<Predicate>();
Predicate onStart = criteriaBuilder.greaterThanOrEqualTo(criteriaRoot.get("insertDateTime"), startTradeDate);
Predicate onEnd = criteriaBuilder.lessThanOrEqualTo(criteriaRoot.get("insertDateTime"), endTradeDate);
conditionsList.add(onStart);
conditionsList.add(onEnd);
CriteriaBuilder criteriaBuilder = this.entityManager.getCriteriaBuilder();
CriteriaQuery<MyClass> criteriaQuery =
criteriaBuilder.createQuery(MyClass.class);
Root<MyClass> criteriaRoot = criteriaQuery.from(MyClass.class);
criteriaQuery.select(criteriaRoot).where(conditionsList);
您应该添加编译器错误
criteriaQuery.select(criteriaRoot).where(conditionsList.toArray(new Predicate[] {}));