Java JSON解析器为何给出错误org.JSON.JSONException:应为';:';在5[字符6第1行]处的键之后
我是json新手,必须从web服务响应中获取值。我已经为此使用了org.json库。下面是示例json值:Java JSON解析器为何给出错误org.JSON.JSONException:应为';:';在5[字符6第1行]处的键之后,java,json,Java,Json,我是json新手,必须从web服务响应中获取值。我已经为此使用了org.json库。下面是示例json值: {"tms_guid": "9LaHmoHpmTd811R", "recharge_status": "100", "message": "Transaction Successful", "response_time": { "verifyClient": 0.0281, "verifyGuid": 0.8695, "verifyOp
{"tms_guid": "9LaHmoHpmTd811R",
"recharge_status": "100",
"message": "Transaction Successful",
"response_time": {
"verifyClient": 0.0281,
"verifyGuid": 0.8695,
"verifyOperator": 0.8698,
"verifyMsid": 0.8698,
"tms_guid": 1.6971,
"queryErr": 7.4243,
"StoringRecharge": 7.4358,
"UpdatingBalance": 7.448
}
}
我的解析JSON输入字符串是:
private final static String JSON_TEST_DATA
= "{"
+ " \"tms_guid\": \"9LaHmoHpmTd811R\", "
+ " \"recharge_status\": \"100\", "
+ " \"message\": \"Transaction Successful\", "
+ " \"response_time\": { "
+ " \"verifyClient\": 0.0281, "
+ " \"verifyGuid\": 0.8695, "
+ " \"verifyOperator\": 0.8698,"
+ " \"verifyMsid\": 0.8698,"
+ " \"tms_guid\": 1.6971,"
+ " \"queryErr\": 7.4243,"
+ " \"StoringRecharge\": 7.4358,"
+ " \"UpdatingBalance\": 7.448"
+ " }"
+ "}";
公共静态void main(最终字符串[]argv)抛出JSONException{
System.out.println(JSON_TEST_DATA);
final JSONObject testObj = new JSONObject(JSON_TEST_DATA);
System.out.println(testObj.toString());
}
例外情况如下:
Exception in thread "main" org.json.JSONException: Expected a ':' after a key at 5 [character 6 line 1]
at org.json.JSONTokener.syntaxError(JSONTokener.java:432)
at org.json.JSONObject.<init>(JSONObject.java:206)
at org.json.JSONObject.<init>(JSONObject.java:310)
at com.kalsym.wsp.sp.icebeep.TestIceBeep.main(TestIceBeep.java:73)
线程“main”org.json.JSONException中的异常:在5[字符6第1行]处的键后应为“:”
位于org.json.JSONTokener.syntaxError(JSONTokener.java:432)
位于org.json.JSONObject(JSONObject.java:206)
位于org.json.JSONObject(JSONObject.java:310)
位于com.kalsym.wsp.sp.iceep.TestIceBeep.main(TestIceBeep.java:73)
我也见过类似的例子。但无法找到解决方案。我看不出有任何问题。我使用了与您相同的代码,但我能够执行您的程序: 您可以看到我的代码,我也使用了相同的JavaAPI
import org.json.JSONException;
import org.json.JSONObject;
public class TestCode {
private final static String JSON_TEST_DATA
= "{"
+ " \"tms_guid\": \"9LaHmoHpmTd811R\", "
+ " \"recharge_status\": \"100\", "
+ " \"message\": \"Transaction Successful\", "
+ " \"response_time\": { "
+ " \"verifyClient\": 0.0281, "
+ " \"verifyGuid\": 0.8695, "
+ " \"verifyOperator\": 0.8698,"
+ " \"verifyMsid\": 0.8698,"
+ " \"tms_guid\": 1.6971,"
+ " \"queryErr\": 7.4243,"
+ " \"StoringRecharge\": 7.4358,"
+ " \"UpdatingBalance\": 7.448"
+ " }"
+ "}";
public static void main (String arg[]) throws JSONException{
//System.out.println(JSON_TEST_DATA);
final JSONObject testObj = new JSONObject(JSON_TEST_DATA);
System.out.println(" --"+testObj.getString("recharge_status")+"\n");
System.out.println(testObj.toString());
}
}
可能是一些字符集问题 我刚刚遇到了一个类似的问题,结果发现从另一个地方复制的JSON字符串包含不间断的空格字符,即使在调试器下也很难注意到:)。我正在从该字符串(通过电子邮件接收)中删除HTML标记,方法是:
jstr=jstr.replaceAll(“,”);//删除<和>
结果看起来像是有效的JSON,但是有了这些不间断的空格。。。这有助于:
jstr = jstr.replaceAll("<.*?>|\u00a0", "");
jstr=jstr.replaceAll(“|\u00a0”,”);
我建议您删除部分输入,直到问题消失。这应该指向这样的字符。虽然我认为这是一个有效的字符,但它似乎不喜欢。
。你能试着删除它吗?我不了解关于“在出现问题之前删除部分输入”的文字。
jstr = jstr.replaceAll("<.*?>|\u00a0", "");