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java中的StringBuilder类_Java_String_Exception - Fatal编程技术网

java中的StringBuilder类

java中的StringBuilder类,java,string,exception,Java,String,Exception,我正在尝试学习如何使用StringBuilder类进行异常处理。我的当前代码没有捕获异常,因为有一个空字符串。我希望它能捕获空白字段并显示错误信息。< /P> try { String name1 = nameField.getText(); String street = streetField.getText(); String city = cityField.getText(); String state = stateField.getText();

我正在尝试学习如何使用StringBuilder类进行异常处理。我的当前代码没有捕获异常,因为有一个空字符串。我希望它能捕获空白字段并显示错误信息。< /P>
try {
    String name1 = nameField.getText();  
    String street = streetField.getText();
    String city = cityField.getText();
    String state = stateField.getText();
    String zip = zipField.getText();
    String phone = phoneField.getText();
    String regexStr = "^(1\\-)?[0-9]{3}\\-?[0-9]{3}\\-?[0-9]{4}$";


    nameDisplay.setText("Hello " + name1 + "!");
    streetDisplay.setText(street);
    cityDisplay.setText(city + ", ");
    stateDisplay.setText(state);
    zipDisplay.setText(zip);
    phoneDisplay.setText(phone);
    } 
    catch (NullPointerException e) {
        JOptionPane.showMessageDialog(null,"Please enter name");
    }

您应该检查变量,而不是捕获NPE异常

if (city != null) {
    cityDisplay.setText(city + ", ");
} else {
   JOptionPane.showMessageDialog(null, "Please enter the name of city");
}

等等。

您永远不应该捕获NullPointerException。NullPointerException是一个bug。您没有捕获异常。相反,您可以修复该错误,使其不再发生。要检查是否在字段中输入了名称,请使用
if(nameField.getText()[.trim()].isEmpty())
。那么我应该将异常列为什么?正确。我想确保用户在名称字段中输入文本。如果为空,则应显示错误。对不起,我是新手。请阅读我的修改意见。标题没有意义