Java Jar有所不同，但它们不应该如此

我有一个创建jar的方法

public class Test {

    public static void main(String[] args) throws Exception {
        aha();
        aha();
        aha();
        aha();
        Thread.sleep(5000);
        aha();
    }

    private static void aha() throws IOException, NoSuchAlgorithmException {
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        JarOutputStream jos = new JarOutputStream(baos);
        jos.putNextEntry(new ZipEntry("sd"));
        jos.write("sdf".getBytes());
        jos.close();
        MessageDigest md = MessageDigest.getInstance("sha1");
        byte[] digest = md.digest(baos.toByteArray());
        for (byte b : digest) {
            System.out.print("," + b);
        }
        System.out.println();
    }
}

输出为：

,-57,-44,59,113,-126,-15,71,62,-90,-120,27,36,-3,69,26,-55,63,107,-93,102
,-57,-44,59,113,-126,-15,71,62,-90,-120,27,36,-3,69,26,-55,63,107,-93,102
,-57,-44,59,113,-126,-15,71,62,-90,-120,27,36,-3,69,26,-55,63,107,-93,102
,-57,-44,59,113,-126,-15,71,62,-90,-120,27,36,-3,69,26,-55,63,107,-93,102
,-124,-26,-79,-28,-34,77,-72,83,92,53,30,-13,95,21,-92,55,70,24,-72,39

---

我需要相同的摘要，但最后的摘要不同。如何成为可复制散列？

尽管几乎看不见，但如果您将

ZipEntry

写入

JarOutputStream

，底层的

zipoutpstream

将为您初始化上次修改时间

if (e.xdostime == -1) {
    // by default, do NOT use extended timestamps in extra
    // data, for now.
    e.setTime(System.currentTimeMillis());
}

您必须使用

setTime

手动初始化时间，以获得恒定结果