Java 在assertj中使用ComparatorForType似乎不适用于作为对象属性的对象属性
我想测试两个对象的相等性,但对它们的某些嵌套属性上存在的Java 在assertj中使用ComparatorForType似乎不适用于作为对象属性的对象属性,java,assertj,Java,Assertj,我想测试两个对象的相等性,但对它们的某些嵌套属性上存在的double值的精度有一定的判断权。似乎是一个合适的解决方案,但如果我的Foo对象具有类型为Bar的属性,其中Bar.baz是一个double的对象,则它似乎不起作用,我希望对其应用此精度判断。没有完全解决我要测试的情况 一些示例代码 import static org.assertj.core.api.Assertions.assertThat; import java.util.Comparator; import java.util
double
值的精度有一定的判断权。似乎是一个合适的解决方案,但如果我的Foo
对象具有类型为Bar
的属性,其中Bar.baz
是一个double
的对象,则它似乎不起作用,我希望对其应用此精度判断。没有完全解决我要测试的情况
一些示例代码
import static org.assertj.core.api.Assertions.assertThat;
import java.util.Comparator;
import java.util.Objects;
import org.junit.Test;
public class ComparatorForTypeTest {
private static final Comparator<Double> DOUBLE_COMPARATOR = new Comparator<Double>() {
@Override
public int compare(Double d1, Double d2) {
return Math.abs(d1 - d2) <= 0.1 ? 0 : 1;
}
};
class Foo {
private int id;
private double baz;
private Bar bar;
public Foo(int id, double baz, Bar bar) {
this.id = id;
this.baz = baz;
this.bar = bar;
}
public Foo withBar(Bar bar) {
Foo that = this;
that.bar = bar;
return that;
}
@Override
public int hashCode() {
return Objects.hash(id, baz, bar);
}
@Override
public boolean equals(Object obj) {
if (this == obj) {
return true;
} else if (obj == null || obj.getClass() != Foo.class) {
return false;
}
Foo that = (Foo) obj;
return Objects.equals(this.id, that.id)
&& Objects.equals(this.baz, that.baz)
&& Objects.equals(this.bar, that.bar);
}
@Override
public String toString() {
return String.format("Foo[id=%d, score=%f, bar=%s]", id, baz, bar == null ? null : bar.toString());
}
}
class Bar {
private int id;
private double baz;
public Bar(int id, double baz) {
this.id = id;
this.baz = baz;
}
@Override
public int hashCode() {
return Objects.hash(id, baz);
}
@Override
public boolean equals(Object obj) {
if (this == obj) {
return true;
} else if (obj == null || obj.getClass() != Bar.class) {
return false;
}
Bar that = (Bar) obj;
return Objects.equals(this.id, that.id)
&& Objects.equals(this.baz, that.baz);
}
@Override
public String toString() {
return String.format("Bar[id=%d, score=%f]", id, baz);
}
}
@Test
public void itComparesBars() {
Bar a = new Bar(1, 1.4);
Bar b = new Bar(1, 1.45);
Bar c = new Bar(2, 1.4);
assertThat(a).isNotEqualTo(b);
assertThat(b).isNotEqualTo(c);
assertThat(a).isNotEqualTo(c);
assertThat(a).usingComparatorForType(DOUBLE_COMPARATOR, Double.class).isEqualToComparingFieldByField(b);
}
@Test
public void itComparesFoos() {
Foo a = new Foo(1, 1.4, null);
Foo b = new Foo(1, 1.45, null);
Foo c = new Foo(2, 1.4, null);
assertThat(a).isNotEqualTo(b);
assertThat(b).isNotEqualTo(c);
assertThat(a).isNotEqualTo(c);
assertThat(a).usingComparatorForType(DOUBLE_COMPARATOR, Double.class).isEqualToComparingFieldByField(b);
Bar barA = new Bar(1, 1.4);
Bar barB = new Bar(1, 1.45);
assertThat(a.withBar(barA)).usingComparatorForType(DOUBLE_COMPARATOR, Double.class).isEqualToComparingFieldByFieldRecursively(b.withBar(barA));
assertThat(a.withBar(barA)).usingComparatorForType(DOUBLE_COMPARATOR, Double.class).isEqualToComparingFieldByFieldRecursively(b.withBar(barB));
}
}
import static org.assertj.core.api.Assertions.assertThat;
导入java.util.Comparator;
导入java.util.Objects;
导入org.junit.Test;
类型测试的公共类比较器{
专用静态最终比较器双_比较器=新比较器(){
@凌驾
公共整数比较(双d1,双d2){
return Math.abs(d1-d2)这里的问题是Bar
有一个重写的equals
方法,用于比较Bar
实例,这在中提到过(但我知道javadoc并不总是发现API的最佳方式):
递归属性/字段比较不应用于具有自定义equals实现的字段,即将使用重写的equals方法,而不是逐字段比较
是一个修改递归比较api的工具,它将提供一个选项来强制递归比较,即使equals
被重写(可能)。更好地使用递归比较,它将一个字段一个字段地比较对象,默认情况下忽略任何重写的equals请参见-now