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Java 无法从POI为的字符串单元格中获取数值_Java_Excel_Apache Poi - Fatal编程技术网

Java 无法从POI为的字符串单元格中获取数值

Java 无法从POI为的字符串单元格中获取数值,java,excel,apache-poi,Java,Excel,Apache Poi,要使用POI和java从excel文件中读取列,请执行以下操作: package main; import java.io.FileInputStream; import java.io.InputStream; import java.util.ArrayList; import java.util.HashMap; import java.util.List; import java.util.Map; import org.apache.poi.hssf.usermodel.HSSFC

要使用POI和java从excel文件中读取列,请执行以下操作:

package main;

import java.io.FileInputStream;
import java.io.InputStream;
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import java.util.Map;

import org.apache.poi.hssf.usermodel.HSSFCell;
import org.apache.poi.hssf.usermodel.HSSFRow;
import org.apache.poi.hssf.usermodel.HSSFSheet;
import org.apache.poi.hssf.usermodel.HSSFWorkbook;

public class ReadExcel {

 public static void main(String[] args) {

try {

    InputStream fs = new FileInputStream("/.../ListProducts.xls");
    HSSFWorkbook wb = new HSSFWorkbook(fs);
    HSSFSheet sheet = wb.getSheetAt(0);



    Map<String, Integer> map = new HashMap<String,Integer>(); //Create map
    HSSFRow row = sheet.getRow(0); //Get first row
    //following is boilerplate from the java doc
    short minColIx = row.getFirstCellNum(); //get the first column index for a row
    short maxColIx = row.getLastCellNum(); //get the last column index for a row
    for(short colIx=minColIx; colIx<maxColIx; colIx++) { //loop from first to last index
    HSSFCell cell = row.getCell(colIx); //get the cell
    map.put(cell.getStringCellValue(),cell.getColumnIndex()); //add the cell contents (name of column) and cell index to the map
    }

    List<ReportRow> listOfDataFromReport = new ArrayList<ReportRow>();
    for(int x = 1; x<=sheet.getPhysicalNumberOfRows(); x++){
     ReportRow rr = new ReportRow(); 
     HSSFRow dataRow = sheet.getRow(x); 

     int idxForColumn1 = map.get("Id"); 
     int idxForColumn2 = map.get("Name"); 
     int idxForColumn3 = map.get("Price"); 

     HSSFCell cell1 = dataRow.getCell(idxForColumn1); 
     HSSFCell cell2 = dataRow.getCell(idxForColumn2); 
     HSSFCell cell3 = dataRow.getCell(idxForColumn3);  

     rr.setColumn1(cell1.getNumericCellValue()); 
     rr.setColumn2(cell2.getNumericCellValue());
     rr.setColumn3(cell3.getNumericCellValue());

     listOfDataFromReport.add(rr);

    }

} catch (Exception e) {
    System.out.println(e.getMessage());
}
}

请给出任何建议,我有一个excel文件中的所有单元格,其数值类型为…

您要做的是使用DataFormatter类。您将其传递给一个单元格,它会尽力返回一个字符串,其中包含Excel将为该单元格显示的内容。如果你给它一个字符串单元格,你会得到字符串。如果您将应用了格式规则的数字单元格传递给它,它将根据这些规则对数字进行格式设置,并返回字符串

对于您的情况,若您要求DataFormatter格式化这些单元格,它将返回一个包含双字符串的字符串

尝试使用

DataFormatter formatter = new DataFormatter();
String str = formatter.formatCellValue(cell1);
double dnum = Double.parseDouble(str );
System.out.println("In formated Cell Value--" + dnum);
rr.setColumn1(dnum);
更多参考,让我们看看这些链接,我想它会帮助你。

如果您确定3个值是数字,您可以在阅读之前修改其类型,如下所示:

HSSFCell cell1 = dataRow.getCell(idxForColumn1); 
HSSFCell cell2 = dataRow.getCell(idxForColumn2); 
HSSFCell cell3 = dataRow.getCell(idxForColumn3);  

cell1.setCellType(CellType.NUMERIC);
cell2.setCellType(CellType.NUMERIC);
cell3.setCellType(CellType.NUMERIC);

rr.setColumn1(cell1.getNumericCellValue()); 
rr.setColumn2(cell2.getNumericCellValue());
rr.setColumn3(cell3.getNumericCellValue());

你能发布你的输入excel文件吗。从列的名称来看,
name
Id
,它们看起来确实是
数字类型的。
HSSFCell cell1 = dataRow.getCell(idxForColumn1); 
HSSFCell cell2 = dataRow.getCell(idxForColumn2); 
HSSFCell cell3 = dataRow.getCell(idxForColumn3);  

cell1.setCellType(CellType.NUMERIC);
cell2.setCellType(CellType.NUMERIC);
cell3.setCellType(CellType.NUMERIC);

rr.setColumn1(cell1.getNumericCellValue()); 
rr.setColumn2(cell2.getNumericCellValue());
rr.setColumn3(cell3.getNumericCellValue());