Java 如何从elasticsearch中获取子聚合

我想得到子聚合

    "size" :0 ,
     "aggs": {
            "classification of day": {
               "date_histogram": {
                  "field": "ALARM DATE",
                   "format" : "dd/MM/yyyy",
                  "interval": "day"

               },
               "aggs": {
                  "classification1": {
                     "terms": {
                        "field": "CLASSIFICATION",
                         "keyed":true
                     }
                  }
               }
            }
         }

above json query returns the following output.

    "aggregations": {
          "classification of day": {
             "buckets": [
                {
                   "key_as_string": "25/02/2016",
                   "key": 1456358400000,
                   "doc_count": 166,
                   "classification1": {
                      "doc_count_error_upper_bound": 0,
                      "sum_other_doc_count": 0,
                      "buckets": [
                         {
                            "key": "attack",
                            "doc_count": 58
                         },
                         {
                            "key": "compromise",
                            "doc_count": 30
                         },
                         {
                            "key": "error",
                            "doc_count": 24
                         },
                         {
                            "key": "reconnaissance",
                            "doc_count": 20
                         },
                         {
                            "key": "suspicious",
                            "doc_count": 19
                         },
                         {
                            "key": "warning",
                            "doc_count": 14
                         },
                         {
                            "key": "misuse",
                            "doc_count": 2
                         }
                      ]
                   }
                },
                {
                   "key_as_string": "26/02/2016",
                   "key": 1456444800000,
...

我试过的Java代码

String aggregations1 = "CLASSIFICATION";
        String field1 = "ALARM DATE";
        DateHistogramInterval interval1 = DateHistogramInterval.DAY;

        SearchResponse response = client.prepareSearch(index).setTypes(type)
                .addAggregation(AggregationBuilders.dateHistogram("classification of day").field(field1)
                        .interval(interval1).format("dd/MM/yyyy")
                        .subAggregation(AggregationBuilders.terms("terms").field(aggregations1)))
                .execute().actionGet();

        Iterator<Aggregation> iter = response.getAggregations().iterator();// get("");

        while (iter.hasNext()) {
            Aggregation aggs=iter.next();
            System.out.println(aggs.getName());
            //aggs.
        }

String aggregations1=“分类”；
字符串field1=“报警日期”；
DateHistorograminterval interval1=DateHistorograminterval.DAY；
SearchResponse response=client.prepareSearch（index）.setTypes（type）
.addAggregation（AggregationBuilders.dateHistogram（“日分类”）.field（field1）
.间隔（间隔1）.格式（“dd/MM/yyyy”）
.子集合（AggregationBuilders.terms（“terms”）.字段（aggregations1）））
.execute（）.actionGet（）；
迭代器iter=response.getAggregations（）.Iterator（）；//得到（“”）；
while（iter.hasNext（））{
聚合aggs=iter.next（）；
System.out.println（aggs.getName（））；
//阿格斯。
}

---

问题是我得到了聚合值。这里有日期，但我没有得到分类。基本上，我想提取一个对象的日期分类

我设法让它工作起来了。如果有人觉得这有帮助，我在这里添加我的答案

String aggregations1 = "CLASSIFICATION";
        String field1 = "ALARM DATE";
        DateHistogramInterval interval1 = DateHistogramInterval.DAY;

        SearchResponse sr = client.prepareSearch(index).setTypes(type)
                .addAggregation(AggregationBuilders.dateHistogram("classification of day").field(field1)
                        .interval(interval1).format("dd/MM/yyyy")
                        .subAggregation(AggregationBuilders.terms("classifications").field(aggregations1)))
                .execute().actionGet();





        // sr is here your SearchResponse object
        Histogram agg = sr.getAggregations().get("classification of day");

        Collection<Histogram.Bucket> buckets = (Collection<Histogram.Bucket>) agg.getBuckets();
        // For each entry

        for (Histogram.Bucket bucket : buckets) {

            if (bucket.getDocCount() != 0) {

                System.out.println((int) bucket.getDocCount());
                System.out.println(bucket.getKeyAsString());
                Terms terms =bucket.getAggregations().get("classifications");
                Collection<Terms.Bucket> bkts = terms.getBuckets();
                for (Bucket b : bkts) {

                    if (b.getDocCount() != 0) {
                        //ESClassification classificaiton = new ESClassification();
                        System.out.println((int) b.getDocCount());
                        System.out.println(b.getKeyAsString());

                    } else {
                        //list = Collections.<ESClassification> emptyList();
                    }

                }


            } else {
                //list = Collections.<ESClassification> emptyList();
            }

        }

String aggregations1=“分类”；
字符串field1=“报警日期”；
DateHistorograminterval interval1=DateHistorograminterval.DAY；
SearchResponse sr=client.prepareSearch（索引）.setTypes（类型）
.addAggregation（AggregationBuilders.dateHistogram（“日分类”）.field（field1）
.间隔（间隔1）.格式（“dd/MM/yyyy”）
.子聚合（聚合生成器.术语（“分类”）.字段（聚合1）））
.execute（）.actionGet（）；
//sr是您的SearchResponse对象
直方图agg=sr.getAggregations（）.get（“日分类”）；
集合bucket=（集合）agg.getbucket（）；
//对于每个条目
用于（直方图。桶：桶）{
if（bucket.getDocCount（）！=0）{
System.out.println（（int）bucket.getDocCount（））；
System.out.println（bucket.getKeyAsString（））；
Terms=bucket.getAggregations（）.get（“分类”）；
集合bkts=terms.getBucket（）；
用于（铲斗b:bkts）{
如果（b.getDocCount（）！=0）{
//ESClassification Classification=新的ESClassification（）；
System.out.println（（int）b.getDocCount（））；
System.out.println（b.getKeyAsString（））；
}否则{
//list=Collections.emptyList（）；
}
}
}否则{
//list=Collections.emptyList（）；
}
}

完美。我真的在找它。好问题，完美答案