Java 显示JSF表中对象的数组列表

我想在JSF表中显示对象的ArrayList：

我创建了这个对象：

public List<TData> td = new ArrayList<TData>();

    public class TData {

        private long id;
        private String key;
        private String language;
        private String translation;

        public TData(){};

        public TData(long id, String key, String language, String translation) {
            // super();
            this.id = id;
            this.key = key;
            this.language = language;
            this.translation = translation;
        }

        public long getId() {
            return id;
        }

        public void setId(long id) {
            this.id = id;
        }

        public String getKey() {
            return key;
        }

        public void setKey(String key) {
            this.key = key;
        }

        public String getLanguage() {
            return language;
        }

        public void setLanguage(String language) {
            this.language = language;
        }

        public String getTranslation() {
            return translation;
        }

        public void setTranslation(String translation) {
            this.translation = translation;
        }

    }

    public List<TData> getDataObj() {
        return td;
    }

    @PostConstruct
    public void loadData() {

        String query = "SELECT c FROM TranslationTestEntitie c";
        List<Object> result =  dao.jpqlQuery(query, 1, 0);

        for(int i =0; i < result.size(); i++){
            TranslationTestEntitie test = (TranslationTestEntitie) result.get(i);
            td.add((TData) result.get(i));

        }

    }

我以对象列表的形式从数据库中获取结果。如何将这些对象显示到JSF页面中

这是实体的源代码

@Entity
@Table(name = "Translations")
public class TranslationTestEntitie extends AbstractEntityWithId {

    private static final long serialVersionUID = 2029240552230401080L;

    @Column(name = "id", insertable=false, updatable=false)
    private long id;
    @Column(name = "key", insertable=false, updatable=false)
    private String key;
    @Column(name = "language", insertable=false, updatable=false)

    private String language;
    @Column(name = "translation", insertable=false, updatable=false)
    private String translation;

    public TranslationTestEntitie() {
    }

    // Getters and setters
    public Long getId() {
        return id;
    }

    //@Transient    Field will not be saved in database
    public void setId(long id) {
        this.id = id;
    }

    public String getKey() {
        return key;
    }

    public void setKey(String key) {
        this.key = key;
    }

    public String getLanguage() {
        return language;
    }

    public void setLanguage(String language) {
        this.language = language;
    }

    public String getTranslation() {
        return translation;
    }

    public void setTranslation(String translation) {
        this.translation = translation;
    }

}

---

我假设JPA返回的对象与TData相同，因为我具有相同的对象属性。

显然，返回的对象是TranslationTestEntitie类型，而不是TData类型。您需要编写代码将TranslationTestEntitie转换为TData类型的对象

TranslationTestEntitie test = (TranslationTestEntitie) result.get(i);
TData newTData = new TData(test.getId(), test.getKey(), test.getLanguage(),  test.getTranslation());
td.add(newTData);

如果它有相同的字段，为什么不能使用TranslationTestEntitie本身呢

List<TranslationTestEntitie> td=  new ArrayList<TranslationTestEntitie>();

for(int i =0; i < result.size(); i++){
        TranslationTestEntitie test = (TranslationTestEntitie) result.get(i);
        td.add(test);
}

List td=new ArrayList（）；
对于（int i=0；i

我更新了帖子。这两个对象具有相同的属性。这不会改变答案：）您必须编写一个方法，使用TranslationTestEntitie对象中的值创建一个新的TData对象。我是这项技术的新手，请您给我一些如何解决此问题的详细信息。

如果它具有相同的字段，为什么不能使用TranslationTestEntitie本身？

我怎么做？您可以创建一个TranslationTestEntitie列表（而不是TData），然后简单地将结果添加到循环中。为什么不使用列表而不是列表？

TranslationTestEntitie test = (TranslationTestEntitie) result.get(i);
TData newTData = new TData(test.getId(), test.getKey(), test.getLanguage(),  test.getTranslation());
td.add(newTData);

List<TranslationTestEntitie> td=  new ArrayList<TranslationTestEntitie>();

for(int i =0; i < result.size(); i++){
        TranslationTestEntitie test = (TranslationTestEntitie) result.get(i);
        td.add(test);
}