Java Hibernate 4.3.0最终版和spring 4.1版

我不知道是我错了，请帮我解决以上问题。 获取反序列化异常。由于此反序列化，它也会导致eof异常。上述类中存在错误

以下是表格结构

`用户id`int11非空自动增量， `user_name`varchar50字符集utf8默认为空， `密码'varchar256默认为空， `密码\u创建\u日期`datetime默认为空， `salt`varchar50默认为空， `地址_id`小数10,0不为空， `客户端id`int11默认为空， `first_name`varchar100默认为空， `姓氏'varchar100默认为空， `电子邮件'varchar100默认为空， `是否由用户名'tinyint1默认值'0'组成， `手机`小数10,0默认为空， `dob`varchar45默认为空， `last4ssn`varchar45默认为空， `锁定的'tinyint1不为空， `已禁用'tinyint1默认值'0'， `登录失败\u计数'int11默认为空， `date_created`日期不为空， `date_modified`日期默认为空， `由_id `小数10,0默认为空的_创建， `按_id `小数10,0默认值NULL修改_， `时区'varchar256默认为空， `语言'varchar256默认为空， `用户输入电话`小数10,0默认为空， `不通知'tinyint1默认值'1'， `已确认的术语'tinyint1默认值'0'， 主键`user\u id`， 唯一键`user\u name``user\u name`， KEY`client\u id``client\u id`， 约束`USERS\u ibfk\u 1`外键`client\u id` 引用'client``客户端id` 为它编写一个junit测试，例如，通过一些可能是自注入的EntityManager加载这个类 注释掉可能导致这种情况的关键部分，例如任何实体参考：

@Entity
@Table(name = "USERS")
public class User implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "USER_ID", nullable = false)
    private Number userId;

    @Column(name = "USER_NAME", nullable = true)
    private String userName;

    @ManyToOne
    @JoinColumn(name="CLIENT_ID", unique=false, nullable=true, insertable=true, updatable=true)
    private Client client;

    @Column(name = "PASSWORD", nullable = true)
    private String password;

    @Column(name = "PASSWORD_CREATION_DATE", nullable = false)
    private Timestamp passwordCreationDate;

    @Column(name = "SALT", nullable = true)
    private String salt;

    @Column(name = "ADDRESS_ID", nullable = false)
    private Number addressId;

    @Column(name = "FIRST_NAME", nullable = true)
    private String firstName;

    @Column(name = "LAST_NAME", nullable = true)
    private String lastName;

    @Column(name = "EMAIL" , nullable = true)
    private String email;

    @Column(name = "IS_MADE_UP_USER_NAME"  , nullable = true)
    private boolean isMadeUpUserName;

    @Column(name = "CELL_PHONE" , nullable = true)
    private Number cellPhone;

    @Column(name = "LAST4SSN"  , nullable = true)
    private String last4SSN;

    @Column(name = "LOCKED" , nullable = false)
    private boolean locked;

    @Column(name = "FAILED_LOGIN_COUNT" , nullable = true)
    private Integer failedLoginCount;

    @Column(name = "DATE_CREATED" , nullable = false)
    private Timestamp dateCreated;

    @Column(name = "DATE_MODIFIED" , nullable = true)
    private Timestamp dateModified;

    @Column(name = "CREATED_BY_ID" , nullable = true)
    private Number createdBy;

    @Column(name = "MODIFIED_BY_ID" , nullable = true)
    private Number modifiedBy;

    @Column(name = "TIME_ZONE" , nullable = true)
    private String timeZone;

    @Column(name = "LANGUAGE"  , nullable = true)
    private String language;

    @Column(name = "USER_ENTERED_TEL"  , nullable = true)
    private Number userEnteredTel;

    @Column(name = "DO_NOT_NOTIFY"  , nullable = true)
    private boolean doNotNotify;
    enter code here
    @Column(name = "DISABLED"  , nullable = true)
    private boolean disabled;

    @Column(name = "TERMS_CONFIRMED" , nullable = true)
    private boolean termsConfirmed;

以及内部的相关方法 运行简单的jpabean，这应该很好 现在检查您的“客户机”类，确保它不引用任何其他实体，并在上面使用最基本的设置进行注释，例如

现在，您应该更接近导致问题的声明

您还应该启用HibernateSQL日志记录和参数日志记录，以查看下面发生了什么

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我在一个类似的设置中遇到了一个相同的错误，它是由错误的建模/篡改注释和关系引起的，该源帮助我解决了这个问题：

什么时候发生异常-在部署应用程序或应用程序中的某段代码时，您可能会认为是异常的罪魁祸首？是的，发布导致此异常的代码当我点击“登录”按钮时，我得到了上述异常。希望是由于上面的类

@Entity
@Table(name = "USERS")
public class User implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "USER_ID", nullable = false)
    private Number userId;

    @Column(name = "USER_NAME", nullable = true)
    private String userName;

    @ManyToOne
    @JoinColumn(name="CLIENT_ID", unique=false, nullable=true, insertable=true, updatable=true)
    private Client client;

    @Column(name = "PASSWORD", nullable = true)
    private String password;

    @Column(name = "PASSWORD_CREATION_DATE", nullable = false)
    private Timestamp passwordCreationDate;

    @Column(name = "SALT", nullable = true)
    private String salt;

    @Column(name = "ADDRESS_ID", nullable = false)
    private Number addressId;

    @Column(name = "FIRST_NAME", nullable = true)
    private String firstName;

    @Column(name = "LAST_NAME", nullable = true)
    private String lastName;

    @Column(name = "EMAIL" , nullable = true)
    private String email;

    @Column(name = "IS_MADE_UP_USER_NAME"  , nullable = true)
    private boolean isMadeUpUserName;

    @Column(name = "CELL_PHONE" , nullable = true)
    private Number cellPhone;

    @Column(name = "LAST4SSN"  , nullable = true)
    private String last4SSN;

    @Column(name = "LOCKED" , nullable = false)
    private boolean locked;

    @Column(name = "FAILED_LOGIN_COUNT" , nullable = true)
    private Integer failedLoginCount;

    @Column(name = "DATE_CREATED" , nullable = false)
    private Timestamp dateCreated;

    @Column(name = "DATE_MODIFIED" , nullable = true)
    private Timestamp dateModified;

    @Column(name = "CREATED_BY_ID" , nullable = true)
    private Number createdBy;

    @Column(name = "MODIFIED_BY_ID" , nullable = true)
    private Number modifiedBy;

    @Column(name = "TIME_ZONE" , nullable = true)
    private String timeZone;

    @Column(name = "LANGUAGE"  , nullable = true)
    private String language;

    @Column(name = "USER_ENTERED_TEL"  , nullable = true)
    private Number userEnteredTel;

    @Column(name = "DO_NOT_NOTIFY"  , nullable = true)
    private boolean doNotNotify;
    enter code here
    @Column(name = "DISABLED"  , nullable = true)
    private boolean disabled;

    @Column(name = "TERMS_CONFIRMED" , nullable = true)
    private boolean termsConfirmed;

//@ManyToOne
//@JoinColumn(name="CLIENT_ID", unique=false, nullable=true, insertable=true, 
//            updatable=true)
//private Client client;

@ManyToOne
@JoinColumn(name="CLIENT_ID")
private Client client;