Java 使用xpath更新xml文档
您好这是我的xml文档:Java 使用xpath更新xml文档,java,xml,xpath,document,Java,Xml,Xpath,Document,您好这是我的xml文档: <city> <beirut> <restaurant> <name>sada</name> </restaurant> </beirut> <jbeil> <restaurant> <name>toto</name> <rating>
<city>
<beirut>
<restaurant>
<name>sada</name>
</restaurant>
</beirut>
<jbeil>
<restaurant>
<name>toto</name>
<rating>4.3/5</rating>
</restaurant>
<restaurant>
<name>jojo</name>
<rating>4.3/5</rating>
</restaurant>
</jbeil>
<sour>
<restaurant>
<name>sada</name>
</restaurant>
</sour>
</city>
我想使用xpath和netbeans将jbeil中jojo餐厅的评级从4.3/5更新为4.5/5请帮助
该代码给出了评级
try {
File inputFile = new File("src/xpath/josephXml.xml");
DocumentBuilderFactory dbFactory
= DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder;
dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(inputFile);
doc.getDocumentElement().normalize();
XPath xPath = XPathFactory.newInstance().newXPath();
String expression = "/City/Jbeil/Restaurant";
NodeList nodeList = (NodeList) xPath.compile(expression).evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nodeList.getLength(); i++) {
Node nNode = nodeList.item(i);
System.out.println("\nCurrent Element :"
+ nNode.getNodeName());
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("rating : "
+ eElement
.getElementsByTagName("rating")
.item(0)
.getTextContent());
我只想更新jbeil中名为jojo的餐馆的评级,请帮助这是一种可能的XPath,可以在jbeil市找到名为jojo的餐馆,然后返回相应的评级元素:
/city/jbeil/restaurant[name='jojo']/rating
注意XML和XPath是区分大小写的,所以我在上面的XPath中使用了所有小写字符来匹配这个问题中发布的XML
我对Java了解不多,但通过internet快速搜索*建议如下:
XPath xpath = XPathFactory.newInstance().newXPath();
String expression = "/city/jbeil/restaurant[name='jojo']/rating";
Element e = (Element)xpath.evaluate(expression, doc, XPathConstant.NODE);
if (e != null)
e.setTextContent("4.5/5");
*@user3630405不客气。你应该开始接受解决问题的答案,请回顾:我在做一个类似的例子。我的实现正在返回一个DeferredTextImpl实例,该实例实际上不能作为元素类型的大小写。然而,对于一个节点来说可能是这样的,它实际上是包含setTextContent方法的接口。如果有人想知道它是哪个节点,它就是org.w3c.dom.Node。