Java 冬眠赢了';t保存具有多通关系的实体

Java 冬眠赢了';t保存具有多通关系的实体,java,mysql,hibernate,Java,Mysql,Hibernate,这是我的桌子: CREATE TABLE `admin_log` ( `LOG_ID` bigint(20) NOT NULL AUTO_INCREMENT, `USER_ID` bigint(20) NOT NULL, `CREATION_DATE` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00', `ACTION` varchar(100) NOT NULL, `DETAILS` varchar(100) DEFAULT

这是我的桌子:

CREATE TABLE `admin_log` (
  `LOG_ID` bigint(20) NOT NULL AUTO_INCREMENT,
  `USER_ID` bigint(20) NOT NULL,
  `CREATION_DATE` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
  `ACTION` varchar(100) NOT NULL,
  `DETAILS` varchar(100) DEFAULT NULL,
  PRIMARY KEY (`LOG_ID`),
  KEY `ADMIN_LOG_FK1` (`USER_ID`),
  CONSTRAINT `ADMIN_LOG_FK1` FOREIGN KEY (`USER_ID`) REFERENCES `user_master` (`USER_ID`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=utf8
以下是我的实体:

@Entity
@Table ( name = "admin_log" )
public class AdminLog {

    private Long            logId;
    private UserMaster      user;
    ...

    @Id
    @GeneratedValue ( strategy = IDENTITY )
    @Column ( name = "LOG_ID", unique = true, nullable = false, length = 20 )
    public Long getLogId () {
        return logId;
    }

    public void setLogId ( Long logId ) {
        this.logId = logId;
    }

    @ManyToOne
    @JoinColumn ( name = "USER_ID" )
    public UserMaster getUser () {
        return user;
    }

    public void setUser ( UserMaster user ) {
        this.user = user;
    }
    ...
}


@Entity
@Table ( name = "user_master" )
public class UserMaster {

    private Long        userId;
    ...

    @Id
    @GeneratedValue ( strategy = IDENTITY )
    @Column ( name = "USER_ID", unique = true, nullable = false, length = 20 )
    public Long getUserId () {
        return this.userId;
    }

    public void setUserId ( Long userId ) {
        this.userId = userId;
    }
    ...
}
当我尝试使用
HibernateTemplate
中的
save()
方法保存
AdminLog
时,我收到以下错误:

SEVERE: Column 'USER_ID' cannot be null
org.springframework.dao.DataIntegrityViolationException: could not insert [...AdminLog];
SQL [insert into admin_log (ACTION, CREATION_DATE, DETAILS, USER_ID) values (?, ?, ?, ?)];
constraint [null] nested exception is org.hibernate.exception.ConstraintViolationException: could not insert: [...AdminLog]

问题是
userId
绝对不是空的!这就像Hibernate无法从
AdminLog
中的
user
属性中检索
userId
。我做错了什么?

您必须先持久化
UserMaster
,然后才能持久化
AdminLog

您正试图保存
UserMaster
的临时实例。如果您有对象的
id
,则应首先加载该对象,并在保存之前将其设置为
AdminLog
对象。

在保存管理日志之前您的用户是否持久化?使用@ManyToOne(…cascade={CascadeType.PERSIST,CascadeType.MERGE})如果要在一个调用中同时执行这两个操作,能否在AdminLog中显示设置用户属性的测试代码或示例代码?您说UserMaster有一个id,这是因为您从hibernate中提取了UserMaster吗?