Java 如果使用子类型和泛型，则无法使用Jackson解析Json

我有这样的类层次结构：

@JsonIgnoreProperties(ignoreUnknown = true)
@JsonTypeInfo(use = JsonTypeInfo.Id.NAME, include = JsonTypeInfo.As.PROPERTY)
@JsonSubTypes(
    JsonSubTypes.Type(value = SubClass1::class, name = "SC1"),
    JsonSubTypes.Type(value = SubClass2::class, name = "SC2")
)
interface Base

data class SubClass1(
    @JsonProperty("i") val i: Int
) : Base

data class SubClass2(
    @JsonProperty("s") val s: String
) : Base

我还有一些容器：

data class Container(
    @JsonProperty("base") val base: Base
)

data class GenericContainer<T: Base> (
    @JsonProperty("base") val base: T
)

因为json字符串不包含字段“@type”

关于这一点，我有两个问题：

如果我知道json字符串的类型，我是否可以在不使用类型字段的情况下解析该字符串？因为我可以从一些客户端获得类似这样的json字符串——他们不知道子类型

如果1不可能，我是否可以始终将这些类的“@type”字段写入json字符串

目前我正在使用最新的FasterXMLJackson（2.12.3）

    val mapper = ObjectMapper()

//  It works
    val jsonStringSubClass = mapper.writeValueAsString(SubClass1(1))    // {"base":{"@type":"SC1","i":1}}
    val subClassInstance = mapper.readValue(jsonStringSubClass, SubClass1::class.java)
    println(subClassInstance)   // SubClass1(i=1)

//  It works too
    val jsonStringContainer = mapper.writeValueAsString(Container(SubClass1(1)))    // {"base":{"@type":"SC1","i":1}}
    val containerInstance = mapper.readValue(jsonStringContainer, Container::class.java)
    println(containerInstance)    // Container(base=SubClass1(i=1))

//  It works too
    val jsonStringGenericContainer = mapper.writeValueAsString(GenericContainer(SubClass1(1)))    // {"base":{"@type":"SC1","i":1}}
    val genericType = mapper.typeFactory.constructParametricType(
        GenericContainer::class.java,
        SubClass1::class.java
    )
    val genericContainerInstance = mapper.readValue<GenericContainer<SubClass1>>(jsonStringGenericContainer, genericType)
    println(genericContainerInstance)    // GenericContainer(base=SubClass1(i=1))

data class GenericContainer<T> (
    @JsonProperty("base") val base: T
)

com.fasterxml.jackson.databind.exc.InvalidTypeIdException: Could not resolve subtype of [simple type, class SubClass1]: missing type id property '@type' (for POJO property 'base')
 at [Source: (String)"{"base":{"i":1}}"; line: 1, column: 15] (through reference chain: GenericContainer["base"])