Java TestRestTemplate-在不破坏主体的情况下记录响应

为了记录请求和响应，我添加了一个LoggingRequestInterceptor，它实现了clienthttpprequestinterceptor

响应主体是一个流，如果我将其读取到我的拦截器中，TestRestTemplate将无法将其反序列化到我的对象模型中。换句话说，当我调用testRestTemplate.get…时，我总是会返回空对象（即使我看到对象是我的响应）

要解决RestTemplate的此问题，可以使用BufferingClientHttpRequestFactory来修复它。我不知道如何为TestRestTemplate修复它

我尝试将BufferingClientHttpRequestFactory添加到RestTemplate的实例中，然后使用该实例包装TestRestTemplate：

restTemplateBuilder.configure(restTemplate);

…但是根本没有日志记录

这就是我添加日志拦截器的方式

public static RestTemplateBuilder withInterceptors() {
        List<ClientHttpRequestInterceptor> interceptors = new ArrayList<>();
        interceptors.add(new LoggingRequestInterceptor());

        return new RestTemplateBuilder()
                .interceptors(interceptors);
    }

publicstaticrestemplatebuilderwithinterceptors（）{
列表拦截器=新的ArrayList（）；
add（新的LoggingRequestInterceptor（））；
返回新的RestTemplateBuilder（）
.拦截器（拦截器）；
}

最后，我想： 1.记录响应主体

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2.将其反序列化为对象模型（如果启用日志记录，现在为空）

调试请求/响应的最简单方法是在属性中设置：

logging.level.org.apache.http=DEBUG

并使用BufferingClientHttpResponseWrapper：

public class LoggingRequestInterceptor implements ClientHttpRequestInterceptor {

    private static final Logger logger = LoggerFactory.getLogger(LoggingRequestInterceptor.class);

    @Override
    public ClientHttpResponse intercept(final HttpRequest request, final byte[] body,
            final ClientHttpRequestExecution execution) throws IOException {
        ClientHttpResponse response = execution.execute(request, body);

        response = log(request, body, response);

        return response;
    }

    private ClientHttpResponse log(final HttpRequest request, final byte[] body, final ClientHttpResponse response) {
        final ClientHttpResponse responseCopy = new BufferingClientHttpResponseWrapper(response);
        logger.debug("Method: ", request.getMethod().toString());
        logger.debug("URI: ", , request.getURI().toString());
        logger.debug("Request Body: " + new String(body));
        logger.debug("Response body: " + IOUtils.toString(responseCopy.getBody()));
        return responseCopy;
    }

}

以及设立：

LoggingRequestInterceptor loggingInterceptor = new LoggingRequestInterceptor();
restTemplate.getInterceptors().add(loggingInterceptor);

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调试请求/响应的最简单方法是在属性中设置：

logging.level.org.apache.http=DEBUG

并使用BufferingClientHttpResponseWrapper：

public class LoggingRequestInterceptor implements ClientHttpRequestInterceptor {

    private static final Logger logger = LoggerFactory.getLogger(LoggingRequestInterceptor.class);

    @Override
    public ClientHttpResponse intercept(final HttpRequest request, final byte[] body,
            final ClientHttpRequestExecution execution) throws IOException {
        ClientHttpResponse response = execution.execute(request, body);

        response = log(request, body, response);

        return response;
    }

    private ClientHttpResponse log(final HttpRequest request, final byte[] body, final ClientHttpResponse response) {
        final ClientHttpResponse responseCopy = new BufferingClientHttpResponseWrapper(response);
        logger.debug("Method: ", request.getMethod().toString());
        logger.debug("URI: ", , request.getURI().toString());
        logger.debug("Request Body: " + new String(body));
        logger.debug("Response body: " + IOUtils.toString(responseCopy.getBody()));
        return responseCopy;
    }

}

以及设立：

LoggingRequestInterceptor loggingInterceptor = new LoggingRequestInterceptor();
restTemplate.getInterceptors().add(loggingInterceptor);

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非常感谢你！我也找到了另一种方法。见下：非常感谢！我也找到了另一种方法。见下文：