Java 如何从重复的映射值生成唯一键
我有一个包含地图列表的JSON:Java 如何从重复的映射值生成唯一键,java,groovy,Java,Groovy,我有一个包含地图列表的JSON: { "aprLimits": [{ "orgId": "Company 1", "rangeStart": "54936", "rangeEnd": "54936", "amountLimit": 100000 }, { "orgId": "Company 1", "rangeStart": "59434", "rangeEnd": "59434", "amountLimit": 0.01 }, {
{
"aprLimits": [{
"orgId": "Company 1",
"rangeStart": "54936",
"rangeEnd": "54936",
"amountLimit": 100000
}, {
"orgId": "Company 1",
"rangeStart": "59434",
"rangeEnd": "59434",
"amountLimit": 0.01
}, {
"orgId": "Company 1",
"rangeStart": "54345",
"rangeEnd": "54345",
"amountLimit": 0
}, {
"orgId": "Company 1",
"rangeStart": "54345",
"rangeEnd": "54345",
"amountLimit": 250000
}, {
"orgId": "Company 2",
"rangeStart": "043",
"rangeEnd": "043",
"amountLimit": 0.01
}, {
"orgId": "Company 2",
"rangeStart": "042",
"rangeEnd": "042",
"amountLimit": 1000
}, {
"orgId": "Company 2",
"rangeStart": "032",
"rangeEnd": "032",
"amountLimit": 0
}]}
我的目标是收集与唯一orgId对应的数据,方法是将其转换为一个键,并为其分配其余的值,因此最终结果如下所示:
["Company 1": [[54936, 54936, 100000], [59434, 59434, 0.01], [54345, 54345, 0], [54345, 54345, 250000]], "Company 2": [[043, 043, 0.01], [042, 042, 1000], [032, 032, 0]]]
我已经获得了唯一的orgId并将数据收集到列表中,但是我很难弄清楚如何将唯一键与列表关联
def slurper = new JsonSlurper()
def parsedJson = slurper.parseText(json)
def list = []
def orgIds = parsedJson.aprLimits.orgId.unique()
parsedJson.aprLimits.each {
if (orgIds.contains(it.orgId)) {
data = new ArrayList(Arrays.asList(it.rangeStart, it.rangeEnd, it.amountLimit))
list.add(data)
}}
这里的一个好的开始是
groupBy
,然后塑造所需的数据。Shorter是一个reduce,带有带有默认值的映射。例如
parsedJson.aprLimits.inject(
[:].withDefault{[]} // if a key is missing, add it and make the value an empty vector
){ r, v ->
r[v.orgId] << [v.rangeStart, v.rangeEnd, v.amountLimit]
r
}
parsedJson.aprrimites.inject(
[:]。使用默认值{[]}//如果缺少键,则添加该键并使该值为空向量
){r,v->
r[v.orgId]一个好的开始是groupBy
,然后塑造你想要的数据。Shorter是带有默认值的映射的reduce
parsedJson.aprLimits.inject(
[:].withDefault{[]} // if a key is missing, add it and make the value an empty vector
){ r, v ->
r[v.orgId] << [v.rangeStart, v.rangeEnd, v.amountLimit]
r
}
parsedJson.aprrimites.inject(
[:]。使用默认值{[]}//如果缺少键,则添加该键并使该值为空向量
){r,v->
r[v.orgId]创建一个结果映射,而不是listdef map=[:]
,然后将成对的-orgId和新数组放入该映射map.put(it.orgId,data)
由于存在重复的orgId值,因此只有循环的最后结果才会出现在映射中,例如[Company 1:[54345,54345,250000],Company 2:[032,032,0]]创建一个结果映射,而不是listdef map=[:]
,然后将成对的orgid和新数组放入该映射map.put(it.orgid,data)
由于orgid的值重复,因此只有循环的最后一个结果才会出现在映射中,例如[公司1:[54345,54345,250000],公司2:[032,032,0]]