Java 发生异常时未调用ResponseEntityExceptionHandler
我是春天的新手。我正在用SpringWebMVC开发RESTAPI。对于错误处理,我得到了这个链接 我已经尝试在我的项目中使用ResponseEntityExceptionHandler。但每当我的控制器抛出异常时,它永远不会到达这个ResponseEntityExceptionHandler 下面是我的代码片段 控制器Java 发生异常时未调用ResponseEntityExceptionHandler,java,spring-mvc,spring-security,error-handling,spring-3,Java,Spring Mvc,Spring Security,Error Handling,Spring 3,我是春天的新手。我正在用SpringWebMVC开发RESTAPI。对于错误处理,我得到了这个链接 我已经尝试在我的项目中使用ResponseEntityExceptionHandler。但每当我的控制器抛出异常时,它永远不会到达这个ResponseEntityExceptionHandler 下面是我的代码片段 控制器 @Controller @RequestMapping("/hello") public class HelloController { private stati
@Controller
@RequestMapping("/hello")
public class HelloController {
private static final Logger logger = Logger.getLogger(HelloController.class);
@RequestMapping(value="/{name}", method=RequestMethod.GET)
public @ResponseBody String greet(@PathVariable(value = "name")String name ) throws InvalidInputException, ResourceNotFoundException{
logger.info("start greet() "+name );
System.out.println("start greet() "+name);
String message = null;
if("".equalsIgnoreCase(name))
{
throw new InvalidInputException("Invalid Input");
}
List<String> names = new ArrayList<String>();
names.add("Harshal");
names.add("Smitesh");
if(names.contains(name)){
message = "Hello "+ name;
}else{
throw new ResourceNotFoundException("Requested Resource not found");
}
System.out.println("end greet");
logger.info("end greet()");
return message;
}
}
例外处理程序
@ControllerAdvice
public class RestResponseEntityExceptionHandler extends ResponseEntityExceptionHandler {
private static final Logger logger = Logger.getLogger(RestResponseEntityExceptionHandler.class);
@ExceptionHandler(value={ResourceNotFoundException.class})
@ResponseStatus(value=HttpStatus.NOT_FOUND)
protected ResponseEntity<Object> handleResourceNotFound(RuntimeException ex, WebRequest request){
logger.info("start handleResourceNotFound()");
String bodyOfResponse = "Requested resource does not found";
HttpHeaders httpHeaders = new HttpHeaders();
httpHeaders.setContentType(MediaType.APPLICATION_JSON);
return handleExceptionInternal(ex, bodyOfResponse, httpHeaders, HttpStatus.NOT_FOUND, request);
}
@ExceptionHandler(value={InvalidInputException.class})
@ResponseStatus(value=HttpStatus.BAD_REQUEST)
protected ResponseEntity<Object> handleInvalidInput(RuntimeException ex, WebRequest request){
logger.info("start handleInvalidInput()");
String bodyOfResponse = "Invalid Input";
HttpHeaders httpHeaders = new HttpHeaders();
httpHeaders.setContentType(MediaType.APPLICATION_JSON);
return handleExceptionInternal(ex, bodyOfResponse, httpHeaders, HttpStatus.BAD_REQUEST, request);
}
}
@ControllerAdvice
公共类RestResponseEntityExceptionHandler扩展ResponseEntityExceptionHandler{
私有静态最终记录器Logger=Logger.getLogger(RestResponseEntityExceptionHandler.class);
@ExceptionHandler(值={ResourceNotFoundException.class})
@ResponseStatus(值=HttpStatus.NOT_FOUND)
受保护的响应句柄资源查找(RuntimeException ex,WebRequest请求){
info(“start handleResourceNotFound()”;
字符串bodyOfResponse=“未找到请求的资源”;
HttpHeaders HttpHeaders=新的HttpHeaders();
httpHeaders.setContentType(MediaType.APPLICATION_JSON);
返回handleExceptionInternal(例如,响应主体、HttpHeader、HttpStatus.NOT_FOUND、请求);
}
@ExceptionHandler(值={InvalidInputException.class})
@ResponseStatus(值=HttpStatus.BAD_请求)
受保护的响应handleInvalidInput(RuntimeException ex,WebRequest请求){
info(“start handleInvalidInput()”;
字符串bodyOfResponse=“无效输入”;
HttpHeaders HttpHeaders=新的HttpHeaders();
httpHeaders.setContentType(MediaType.APPLICATION_JSON);
返回handleExceptionInternal(例如,响应主体、HttpHeader、HttpStatus.BAD_请求、请求);
}
}
调度器servlet
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-4.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.0.xsd">
<context:component-scan base-package="com.practice.errorhandlerdemo.controller"/>
<context:annotation-config/>
</beans>
web.xml
<web-app>
<display-name>ErrorHandlerDemo</display-name>
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/my-servlet.xml</param-value>
</init-param>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
ErrorHandlerDemo
调度员
org.springframework.web.servlet.DispatcherServlet
1.
上下文配置位置
/WEB-INF/my-servlet.xml
调度员
/
首先,检查您的配置是否考虑了您的@ControllerAdvice
注释类:它是否位于Spring扫描的包中?您是否以其他方式将其声明为bean
此外,如果不需要它提供的所有异常映射,则不需要扩展ResponseEntityExceptionHandler
编写异常处理的更简单方法:
@ControllerAdvice
public class RestResponseEntityExceptionHandler {
@ExceptionHandler(ResourceNotFoundException.class)
protected ResponseEntity<String> handleResourceNotFound(ResourceNotFoundException ex){
return ResponseEntity
.status(HttpStatus.NOT_FOUND)
.body("Requested resource does not found");
}
@ExceptionHandler(InvalidInputException.class)
protected ResponseEntity<String> handleInvalidInput(InvalidInputException ex){
return ResponseEntity
.badRequest()
.body("Invalid Input");
}
}
@ControllerAdvice
公共类ResponseEntityExceptionHandler{
@ExceptionHandler(ResourceNotFoundException.class)
受保护的响应句柄资源查找(ResourceNotFoundException ex){
返回响应性
.status(未找到HttpStatus.NOT_)
.body(“未找到请求的资源”);
}
@ExceptionHandler(InvalidInputException.class)
受保护的响应handleInvalidInput(InvalidInputException ex){
返回响应性
.badRequest()文件
.正文(“无效输入”);
}
}
请注意,Spring4.1中引入了
ResponseEntity
builder API,但您可以在4.0.x上使用常规构造函数。我在SpringWebMVC4.2.5中也遇到了同样的问题。原因是通过DispatcherServlet
的异常IfNoHandlerFound
参数。默认情况下,它的值为false
,因此所有错误都会生成HttpServletResponse.SC_NOT_FOUND
servlet响应,并且没有异常
将其设置为true后,我的
@exceptionhandler
开始工作报告了一些情况,其中ResponseEntityExceptionHandler
和@ControllerAdvice
都不工作
它们都应该将类下用@ExceptionHandler
注释的方法编译到一个公共位置,所有控制器都可以从该位置引用
如果它对你不起作用。您可以将您的
@ExceptionHandler
方法添加到一个公共的AbstractController
类中,该类由所有其他控制器扩展。您只需要一些配置
在application.properties或application.yml中:
server.error.whitelabel.enabled=false
spring.mvc.throw-exception-if-no-handler-found=true
spring.resources.add-mappings=false
在springboot上加载配置文件:
@Configuration
@EnableWebMvc
@ComponentScan(basePackages = "xx.xxx.xxxx")
@PropertySource("classpath:application.yml")
public class WebAppConfig {
}
问题在于@ExceptionHandler声明ResourceNotFoundException,而作为HandlereSourceNotFind的一个参数,您需要RuntimeException。参数exception和ExceptionHandler的值应匹配 因此,它应该是:
@ExceptionHandler(value={ResourceNotFoundException.class})
protected ResponseEntity<Object> handleResourceNotFound(ResourceNotFoundException ex, WebRequest request){
}
@ExceptionHandler(值={ResourceNotFoundException.class})
受保护的响应句柄资源查找(ResourceNotFoundException ex,WebRequest){
}
一些变通方法
- 仔细检查是否为重写方法使用了正确的签名
- 如果您使用任何IDE,请检查是否有任何@Override标记/符号/箭头可确保您的重写有效
- 检查是否已经从项目的另一个类或依赖项的任何其他类扩展了
ResponseEntityExceptionHandler
- 将断点放在
方法上ResponseEntityExceptionHandler::handleException
- 对于
,您应该将DispatcherServlet配置为在未找到任何处理程序时引发异常NoHandlerFoundException
ResponseEntityExceptionHandler
确实带来了额外的处理程序,但您不一定需要扩展它。关键是要有@ControllerAdvice@ExceptionHandler(value={ResourceNotFoundException.class})
protected ResponseEntity<Object> handleResourceNotFound(ResourceNotFoundException ex, WebRequest request){
}