Java 如果未检测到用户输入,则继续运行
这里我编写了一个简单的程序来获取用户输入Java 如果未检测到用户输入,则继续运行,java,java.util.scanner,user-input,Java,Java.util.scanner,User Input,这里我编写了一个简单的程序来获取用户输入 Scanner keyInput = new Scanner(System.in); System.out.println("Satisfied? yes or no: "); String decision = keyInput.nextLine(); if(decision.matches("no"){ //code }
Scanner keyInput = new Scanner(System.in);
System.out.println("Satisfied? yes or no: ");
String decision = keyInput.nextLine();
if(decision.matches("no"){
//code
} else {
keyInput.close();
//code
}
如果10秒后没有检测到用户输入,我如何使它跳到else语句?
谢谢您可以像这样使用计时器和计时器任务:
import java.util.Timer;
import java.util.TimerTask;
...
TimerTask task = new TimerTask()
{
public void run()
{
if( str.equals("") )
{
System.out.println( "you input nothing. exit..." );
System.exit( 0 );
}
}
};
...
Timer timer = new Timer();
timer.schedule( task, 10*1000 );
Scanner sc = new Scanner(System.in);
String in = sc.readLine();
timer.cancel();