Java JPA-按录取表格状态计数（状态类型枚举）

我声明了一个

Enum

类型StatusEnum，如下所示：

public enum StatusEnum {
PENDING, ACCEPTED, REJECTED, IN_PROGRESS, COMPLETED

}

我正试图从他们的状态中获取录取表格的数量，所以我尝试了查询（在存储库中）：

资源类别：

@GetMapping("/workorders/countByStatus")
@Timed
public List<AdmissionFormStatusCountResponseDTO> admissionFormCountByStatus() {
    return admissionFormService.workorderCountByStatus();
}

---

只有当状态值存在时，它才会使用count进行响应，但对于尚未分配给任何准入表单的Enum状态，我还要求结果中的count=0

在准备您的

admissionFormStatusCountList

后，手动查看其中缺少哪些枚举，并将其添加为值0。您无法将其从数据库中取出。

我按照以下要求进行了更改

我将

admissionFormStatusCountResponsed定义为如下内容：

public class AdmissionFormStatusCountResponseDTO {

private Long accepted;
private Long completed;
private Long inProgress;
private Long pending;
private Long rejected;

public AdmissionFormStatusCountResponseDTO() {
}

public AdmissionFormStatusCountResponseDTO(Long accepted, Long completed, Long inProgress, Long pending, Long rejected) {
    this.accepted = accepted;
    this.completed = completed;
    this.inProgress = inProgress;
    this.pending = pending;
    this.rejected = rejected;
  }
//getters and setters
}

然后使用此DTO将存储库查询更新为：

@Query("select new com.purvik.app1.service.dto.AdmissionFormStatusCountResponseDTO(" +
    "SUM(CASE WHEN a.status='ACCEPTED' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='COMPLETED' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='IN_PROGRESS' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='PENDING' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='REJECTED' then 1 else 0 END)" +
    ") from AdmissionForm a")
AdmissionFormStatusCountResponseDTO admissionFormCountByStatusNew();

服务类别：

public AdmissionFormStatusCountResponseDTO admissionFormCountByStatus(){
    log.debug("Request to get count of AdmissionForm by it's Status ");
    return admissionFormRepository.admissionFormCountByStatusNew();
}

资源终结点：

@GetMapping("/admissionForms/countByStatus")
@Timed
public AdmissionFormStatusCountResponseDTO admissionFormCountByStatus() {
    log.debug("get count of status from stored admissionForm");
    return admissionFormService.admissionFormCountByStatus();
}

现在我的回答是：

{
"accepted": 5,
"completed": 0,
"inProgress": 4,
"pending": 1,
"rejected": 1
}

我不需要在
Enum
中定义所有静态。它是一个基于构造函数的JPQL查询，可以带来预期的结果。希望这能帮助别人

@如果希望在
Enum
中定义响应中的所有静态，则Robert Niestroj是正确的。只是编辑帮助我的代码
 您需要一个包含所有可能状态值的表，以便能够从数据库中获取这些值。
@Query("select new com.purvik.app1.service.dto.AdmissionFormStatusCountResponseDTO(" +
    "SUM(CASE WHEN a.status='ACCEPTED' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='COMPLETED' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='IN_PROGRESS' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='PENDING' then 1 else 0 END)," +
    "SUM(CASE WHEN a.status='REJECTED' then 1 else 0 END)" +
    ") from AdmissionForm a")
AdmissionFormStatusCountResponseDTO admissionFormCountByStatusNew();

public AdmissionFormStatusCountResponseDTO admissionFormCountByStatus(){
    log.debug("Request to get count of AdmissionForm by it's Status ");
    return admissionFormRepository.admissionFormCountByStatusNew();
}

@GetMapping("/admissionForms/countByStatus")
@Timed
public AdmissionFormStatusCountResponseDTO admissionFormCountByStatus() {
    log.debug("get count of status from stored admissionForm");
    return admissionFormService.admissionFormCountByStatus();
}

{
"accepted": 5,
"completed": 0,
"inProgress": 4,
"pending": 1,
"rejected": 1
}