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Java 仅在外大括号中使用逗号拆分字符串的算法_Java_String Split - Fatal编程技术网

Java 仅在外大括号中使用逗号拆分字符串的算法

Java 仅在外大括号中使用逗号拆分字符串的算法,java,string-split,Java,String Split,我只想在第一个大括号内拆分字符串。我如何用java实现它 Input String 1: text2(text3, text4), text5(text6, text7) String1: text2(text3, text4) String2: text5(text6, text7) Input String 2: text2, text3(text4, text5(text6, text7, text8)) String1: text2 String2: text3(text4, te

我只想在第一个大括号内拆分字符串。我如何用java实现它

Input String 1: text2(text3, text4), text5(text6, text7)

String1: text2(text3, text4)
String2: text5(text6, text7)

Input String 2: text2, text3(text4, text5(text6, text7, text8))

String1: text2
String2: text3(text4, text5(text6, text7, text8))
输入字符串可以有任意数量的级别。请假定输入字符串具有匹配的大括号

提前感谢

包ic.ac.uk.relationshipvisualiser.app;
package ic.ac.uk.relationshipvisualiser.app;

import java.util.ArrayList;
import java.util.List;

public class tmpTest3 {

    public static List<String> process(String p_inp) {
        List<String> res = new ArrayList<String>();
        p_inp = p_inp.trim();

        int numberOfOpenBracketsEncountered = 0;

        String t = "";
        String cur = "";

        for (int c=0;c<p_inp.length();c++) {
            cur = p_inp.substring(c,c+1);
            if (cur.equals("(")) {
                numberOfOpenBracketsEncountered++;
            }
            if (cur.equals(")")) {
                numberOfOpenBracketsEncountered--;
            }


            if (cur.equals(",")) {
                if (numberOfOpenBracketsEncountered==0) {
                    if (t.length()>0) res.add(t.trim());
                    t = "";
                } else {
                    cur = cur;
                    t = t + cur;
                }
            } else {
                cur = cur;
                t = t + cur;
            }

        }
        if (t.length()>0) res.add(t.trim());

        return res;
    }

    public static void main(String[] args) {
        System.out.println("Start tmpTest3");

        List<String> inputs = new ArrayList<String>();
        inputs.add("text2(text3, text4), text5(text6, text7)");
        inputs.add("text2, text3(text4, text5(text6, text7))");

        for (int c=0;c<inputs.size();c++) {
            System.out.println("Running test for " + inputs.get(c));
            List<String> res = process(inputs.get(c));
            System.out.println("Got " + res.size() + " strings as a result:");

            for (int d=0;d<res.size();d++) {
                System.out.println(" - :" + res.get(d) + ":");
            }

            System.out.println("----------------------");

        }


        System.out.println("End tmpTest3");
    }   
}
导入java.util.ArrayList; 导入java.util.List; 公共类tmpTest3{ 公共静态列表进程(字符串p_inp){ List res=new ArrayList(); p_inp=p_inp.trim(); int numberOfOpenBracketsEncountered=0; 字符串t=“”; 字符串cur=“”; 对于(int c=0;c0)res.add(t.trim()); t=“”; }否则{ cur=cur; t=t+cur; } }否则{ cur=cur; t=t+cur; } } 如果(t.length()>0)res.add(t.trim()); 返回res; } 公共静态void main(字符串[]args){ System.out.println(“启动tmpTest3”); 列表输入=新的ArrayList(); 输入。添加(“text2(text3,text4),text5(text6,text7)”; 添加(“text2,text3(text4,text5(text6,text7))”;
对于(int c=0;c这对您有效吗?

导入java.util.array

class Program {
public static void main (String[] args) throws java.lang.Exception  {

    String subject1 = "text2(text3, text4), text5(text6, text7)";
    String subject2 = "text2, text3(text4, text5(text6, text7))";
    String p = "\\s*\\d*\\(\\)";
    String[] res = subject1.split(p);
    System.out.println(Arrays.toString(res));
    res=subject2.split(p);
    System.out.println(Arrays.toString(res));

} // end main
} // end 
发出:- [text2(text3,text4),text5(text6,text7)]
[text2,text3(text4,text5(text6,text7))

String str1=inputStr.substring(0,inputStr.indexOf(“,”).trim();String str2=inputStr.substring(inputStr.indexOf(“,”)+1,inputStr.length()).trim();
和inputStr.split(“,”)这显然不起作用。我在split中寻找是否有一个简单的正则表达式可以使用