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Java 使用ObservableList中的对象填充ComboBox时出现问题_Java_Oop_Javafx_Combobox_Javafx 8 - Fatal编程技术网

Java 使用ObservableList中的对象填充ComboBox时出现问题

Java 使用ObservableList中的对象填充ComboBox时出现问题,java,oop,javafx,combobox,javafx-8,Java,Oop,Javafx,Combobox,Javafx 8,我试图用可观察列表中的对象填充一个组合框,但在组合框中它显示了一些其他内容 代码: 下面是它在组合框中的外观: 有人能帮我吗?问题是我没有在Veturat类中重写toString方法。这是可行的,但有更好的解决方案: @FXML private ComboBox<Veturat> box; ObservableList<Veturat> lista = FXCollections.observableArrayList(); public void ad

我试图用可观察列表中的对象填充一个组合框,但在组合框中它显示了一些其他内容

代码:

下面是它在组合框中的外观:


有人能帮我吗?

问题是我没有在Veturat类中重写toString方法。

这是可行的,但有更好的解决方案:
    @FXML
    private ComboBox<Veturat> box;
ObservableList<Veturat> lista = FXCollections.observableArrayList();

public void addToComboBox() throws SQLException, ClassNotFoundException
    {
        box.getItems().clear();
        Class.forName("com.mysql.jdbc.Driver");
        String url = "jdbc:mysql://**.***.**.***/*****";
        String user = "******";
        String pass = "***********";
        connect = (Connection) DriverManager.getConnection(url, user, pass);
        Statement statement;
        String sql = "Select * from veturattable";
        statement = connect.createStatement();
        ResultSet rs = statement.executeQuery(sql);

        while(rs.next())
        {
            int id = rs.getInt("id");
            String vetura = rs.getString("vetura");
            String modeli = rs.getString("modeli");
            int km = rs.getInt("km");
            double qmimi = rs.getDouble("qmimi");
            String ngjyra = rs.getString("ngjyra");
            String targa = rs.getString("targa");

            veturat = new Veturat(id,vetura,modeli,km,qmimi,ngjyra,targa);
            lista.add(veturat);
        }

        box.getItems().addAll(lista);
        rs.close();
        connect.close();
    }