Java 循环卡住时，请执行此操作

代码是一个正在进行的Tic-Tac-Toe游戏。当我运行代码时，它询问X的位置号，然后停止。它与while循环有关，因为当我在没有它的情况下运行它时，它工作得很好。然而，我需要循环将X设置为false，这样它就变成了O

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

---

问题可能出在这一行：

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

            }while(Xturn = true);

这不是一个比较。=运算符是赋值。这会将值true分配给xtorn，然后继续循环，因为分配的结果始终是分配的值

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

为了进行比较，可以使用==。但由于Xtrn一开始是一个布尔值，您可以简单地编写：

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

            }while(Xturn);

---

问题可能出在这一行：

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

            }while(Xturn = true);

这不是一个比较。=运算符是赋值。这会将值true分配给xtorn，然后继续循环，因为分配的结果始终是分配的值

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

为了进行比较，可以使用==。但由于Xtrn一开始是一个布尔值，您可以简单地编写：

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

            }while(Xturn);

改变

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

到

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

xtorn=true是一个赋值，不会检查xtorn是否为true。为此，必须使用xtorn==true或simple xtorn。奥图恩也是如此

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

另外，如所述，您需要在循环内使IfGameOver的值变为true，以便代码退出外部do while循环。

Change

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

}while(Xturn = true);
...
}while (Oturn = true);

到

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

xtorn=true是一个赋值，不会检查xtorn是否为true。为此，必须使用xtorn==true或simple xtorn。奥图恩也是如此

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

---

此外，如所述，您需要在循环内使IfGameOver的值变为true，以便代码退出外部do while循环。

您有多个问题。如前所述，您的while语句中没有使用相等检查，但其他问题会覆盖此问题。在X的回合之后，但在O的回合的do-while循环之前，您正在将Oturn设置为true。因此，您将在X输入之后立即进入Oturn do循环。这应该会把它清理干净

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

import java.util.Scanner;
class TicTacToe

{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int Input;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn = true;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             else
             System.out.println("It is O's turn, position number?");

             Input = -1;
            do
                {
                try
                {
                Input = scan.nextInt();
                board[Input-1] = (Xturn?"X":"O");
                Xturn = !Xturn;
                }
                catch (Exception e)
                {
                    System.out.println("Invalid input. Please enter a valid position number");
                }
                }while(Input==-1);
    } while (!IfGameOver);
}
}

---

你有很多问题。如前所述，您的while语句中没有使用相等检查，但其他问题会覆盖此问题。在X的回合之后，但在O的回合的do-while循环之前，您正在将Oturn设置为true。因此，您将在X输入之后立即进入Oturn do循环。这应该会把它清理干净

import java.util.Scanner;
class TicTacToe


{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int XInput, OInput;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn, Oturn;
    Xturn = true;
    Oturn = false;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             if (Oturn)
             System.out.println("It is O's turn, position number?");

            do
                {
                try
                {
                XInput = scan.nextInt();
                board[XInput-1] = "X";
                Oturn= true;
                Xturn = false;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    XInput = scan.nextInt();
                }
                }while(Xturn = true);
            do
                {
                try
                {
                OInput = scan.nextInt();
                board[OInput-1] = "X";
                Oturn = false;
                Xturn = true;
                }
                catch (NumberFormatException e)
                {
                    System.out.println("Invalid input. Please enter a position number");
                    OInput = scan.nextInt();
                }
                }while (Oturn = true);

    } while (!IfGameOver);
}
}

import java.util.Scanner;
class TicTacToe

{
public static void main(String[] args)

{
    Scanner scan = new Scanner(System.in);
    int Input;
    boolean IfGameOver;
    String []board = {"1","2","3","4","5","6","7","8","9"};
    IfGameOver = false;
    boolean Xturn = true;

    System.out.print("Welcome to Tic-Tac-Toe!\n\n");
do
    {

        {
         System.out.println(" " + board[0] + board[1] + board[2]);
         System.out.println(" " + board[3] + board[4] + board[5]);
         System.out.println(" " + board[6] + board[7] + board[8]);
        }
             if (Xturn)
             System.out.println("It is X's turn, position number?");
             else
             System.out.println("It is O's turn, position number?");

             Input = -1;
            do
                {
                try
                {
                Input = scan.nextInt();
                board[Input-1] = (Xturn?"X":"O");
                Xturn = !Xturn;
                }
                catch (Exception e)
                {
                    System.out.println("Invalid input. Please enter a valid position number");
                }
                }while(Input==-1);
    } while (!IfGameOver);
}
}

---

不用它运行它-代词太多了！您可能希望删除catch语句中的第二个scan.nextInt，因为您将连续两次请求输入。我建议，您使用用户输入循环并将其移动到自己的方法，这样可以进一步降低复杂性，在没有它的情况下运行它-代词太多！您可能希望删除catch语句中的第二个scan.nextInt，因为您将连续两次请求输入。我建议您使用用户输入循环并将其移动到自己的方法，这样可以稍微降低复杂性further@MadProgrammer是的，我做到了：s@JustinBeaubien：这可能不是代码中的唯一错误；我没有彻底检查过。@Mad是的，我检查过：s@JustinBeaubien：这可能不是代码中的唯一错误；我没有彻底检查过。